# abstract algebra – Algebraic property dominated for 1 \$ times 0 = 0 \$?

It is well known that each number multiplied by $$0$$ is $$0$$ and each number multiplied by $$1$$ is the number itself, now I'm confused to get the answer convinced to this question, Is that $$1 times 0 = 0$$ is the result of the first property "each number multiplied by $$0$$ is $$0$$ or a result of the second property each number multiplied by $$1$$ is the number itself?