If n = 6 and p = 0.50, what is the probability that x ≥ 1?

P(x ≥ 1 | n = 6 and p = 0.50) = ?

Attempt:

p=0.5

n=6

x=1 or 2 etc

(n!/x!(n-x)!)(p^x(1-p)^n-x)

So I calculated 0.0938 for 1 and 2,3 etc etc but none of the answers were right, what am i missing and need to do to arive at the answer?