derivatives – Using logarithmic differentiation, find $y’$. Am I correct?

Using logarithmic differentiation, find $y’$.

$$y=ln x^{cos(x)} space (x>1)$$

I solved and here is my answer:

$$y’=(ln x)^{cos(x)}(cfrac{cos(x)}{x lnx}-sinxln(ln x)) $$

But I don’t understand what is $(x>1)$ use for?

Or am I missed something?