General topology – A suslinian and non-suslinian continuum?

There is an apparent contradiction in the literature that I would like to address …

continuum means compact metizable connected with more than one point.

A continuum is Suslinean if each collection of discontinuous sub-discontinues in pairs is countable.

In the following example, Author A build a continuum $ Y: = X / sim $ which is the closing of a ray (a one-to-one image of $[01)$[01)$[01)$[01)$) so that the radius is in first category $ Y $. In other words, the radius and its complement are both dense in $ Y $.

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It's clear that $ X $ is Suslinean, so $ Y = X / sim $ is also Suslinean.

On the other hand, since $ Y $ contains a dense ray of first category, there is a sequence of disjoint arcs in pairs in $ Y $ which converges towards $ Y $ in the distance Hausdorff. By a theorem of Author B, $ Y $ is non-Suslinean.

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Question 1: Is there really a contradiction? I must mention that both articles have appeared in good journals and that both authors are well respected in this field.

Question 2: Is the example correct? I found some typos, for example $ A_n $ should be $ C_n cup bigcup … $ and $ overline {z_1 z_1} $ should be $ overline {z_1 z_2} $but otherwise it looks good.

If the answer to these questions is YES, then I will have to look for a flaw in the proof of the author B.