linear algebra – How to find the value of a in $ frac {a} { ln (1 + a)} = b $?

Well, it may be a basic question, but I do not find how to solve this equation:
$$ frac {a} { ln (1 + a)} = b $$
I've tried using the logarithm relationship, putting everything to the power of e, but if I do that, I end up with:
$$ frac {e ^ {a}} {1 + a} = b $$
So it just becomes an endless loop where I can not get the value of one. So, if anyone has any suggestions, I would appreciate it a lot. Thank you!