Your first guess is correct. Sometimes there is more than one way to write the same solution.

Clearly, if there are $k$ connected components you’ll need exactly $k-1$ edges to connect them (without forming any cycle).

On the other hand, a tree with $n$ nodes must have exactly $n-1$ edges, so if the graph is acyclic and already has $m$ edges, then it is missing $n-1-m$ edges.

Regarding the example: the given graph has $n=10$ vertices, $m=6$ edges, and $k=4$ connected components (not 3), so the answer is $3=k-1=n-m-1$. The sets of vertices in each connected component are ${1,2,8}, {3}, {4, 6, 10}$, and ${5, 7, 9}$.