python – Finding unique top sums from multiple lists

My question arises from this post on MSE where I have provided an answer to solve the question :

There are multiple lists given. The number of lists is arbitrary.
Each list contains numbers and is sorted descendingly.
We shall take exactly $1$ element from each list and calculate the sum of elements.How would you go about finding the top $N$ sums?

Here the top sums need not to be different, just the indices of them. I wanted to write an algorithm to find the top $N$ unique sums, namely where the sum of elements is different. What I have done is using the same approach described in the linked post. The problem is that for some inputs there are lots of duplicate sums, so the research for the unique ones gets slower and slower. I post the implementation in python

import time

def top_solutions_2(N,lists):

    N_best = ()
    k, len_k_lists = len(lists), (len(x) for x in lists)
    init_sol = (sum(x(0) for x in lists),tuple(0 for x in range(k)))
    comp_list, new_vals = ((init_sol)), ()
    seen = {init_sol(1)}

    for _ in range(N) :

        curr_best = (float('-inf'))
        for x in comp_list :
            if x and x(-1)(0) > curr_best(0) : curr_best = x(-1)

        N_best.append(curr_best)

        inds = ()

        for arr in comp_list : 

            while arr :
                
                comp_val = arr.pop()
                
                if curr_best(0) > comp_val(0) : arr.append(comp_val); break
                
                inds.append(comp_val(1))

        comp_list.append(())
        
        for ind in inds :
            
            for x in range(k) :

                if len_k_lists(x) > ind(x)+1 : r = tuple(c if i != x else c+1 for i,c in enumerate(ind))
                else : continue

                if r not in seen :
                    curr_sum = curr_best(0)+lists(x)(r(x))-lists(x)(r(x)-1)
                    comp_list(-1).append((curr_sum,r))
                    seen.add(r)                
                
        comp_list(-1).sort()

    return N_best
        
for N in range(10,60,10) :

    lists = ( (23,5,3,2,1),
              (19,9,8,7,0),
              (17,12,4,2,1),
              (15,13,11,9,2),
              (21,17,13,9,4),
              (16,13,12,11,1),
              (27,23,21,18,4),
              (31,25,24,12,1),
              (27,22,14,7,3),
              (9,8,7,6,5))

    a = time.time()
    top_solutions_2(N,lists)
    b = time.time()
    print("Top {} in {} sec".format(N,b-a))

where the output is

Top 10 in 0.0 sec
Top 20 in 0.07787561416625977 sec
Top 30 in 0.5308513641357422 sec
Top 40 in 2.2048890590667725 sec
Top 50 in 7.203002452850342 sec

How can a more efficient algorithm with a lower complexity and/or a lower running time be made?And also, how can my approach be improved in efficiency?

Thank you in advance