Simplifying the boolean expression xy + (!x)z + yz with boolean algebra?

So using K-maps I was able to simplify xy + (!x)z + yz to xy + (!x)z, and I double-checked that the truth tables are the same.

I’m having trouble understanding how I would have used boolean algebra to get this result. I tried my usual tricks of adding zero, letting addition distribute over multiplication, etc., without avail.

Any thoughts appreciated.

Thanks.