## combinatorial – Prove that among any set of 34 different positive integers that are at most 99, there is always a pair of numbers that differs by at most 2.

Okay, so I'm pretty new to this. I think this should be a pretty simple solution, but I do not know how to start.

So here's where I was going

if we have a set {1,2, … 99}, then I start creating groups that have an integer pair other than 2 at most.

group 1 = (1,2)

group 2 = (3,4)

group 49 = (97.98)

Now, I know I do not use 99 but it says at most 99. Another thing I could do is make sure that the groups

group 1 = (1,3)

group 2 = (2,4)

group 3 = (5,7)

group 4 = (6.8)

group 48 = (94.96)

group 49 = (95.97)

group 50 = (98.99)

and I think it works better.

Now, from here, I do not know how to progress, in fact, I think it's a bad way to go, but I do not know how to solve this problem differently. Maybe I could use the pigeon trap principle but I do not know how.

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## Trump's speech in prime time on the government's closure

President Donald Trump will hold court in court tonight as he delivers the speech of the Oval Office of

hope to convince the American public and skeptical lawmakers that there is a crisis on the southern border. latest avant-garde news

His goal: to get billions of dollars of funds to build the "big, beautiful" wall he promised in a context of partial closure of the government that has no end.

.

## c ++ – Largest chain lexicographically among authorized exchanges

Problem: Given a string str and a pair array that indicates which string
the indexes of the chain can be inverted, returns the lexicographer
the largest chain resulting from authorized exchanges. You can exchange
indices any number of times.

Example

For str = "abdc" and peers = [[1, 4], [3, 4]], the output should be
swapLexOrder (str, peers) = "dbca".

By exchanging the given indices, you get the strings: "cbda", "cbad",
"dbac", "dbca". The lexicographically largest chain of this list is
"Dbca".

My comments: My program has passed all the tests of the CodeSignal website, but since I am relatively new to algorithms, there is probably a more efficient way to solve it. In addition, I am looking for a general revision of the code: does my code indicate that I look like a beginner? Thank you.

``````#understand
#understand
#understand
#understand
#understand
#understand

std :: string swapLexOrder (std :: str string, std :: vector <std :: vector> pairs
{
if (pairs.size () == 0) returns str;
std :: vector <std :: set> pairpool; // pairpool: contains interchangeable index sets
std :: vector <std :: vector> stringpool; // stringpool: contains interchangeable character vectors

// create a pair structure
for (std :: size_t i = 0; i <couples.size (); i ++)
{
bool alrExists = false;
std :: set newset;
for (auto & p: pairpool)
{
for (auto ele: p)
{
if ((pairs[i][0]    == ele) || (pairs[i][1]    == ele))
{
if (! alrExists)
{
alrExists = true;
p.insert (pairs[i][0])
p.insert (pairs[i][1])
newSet = p;
}
other
{
if (p == newSet) pause;
p.insert (newSet.begin (), newSet.end ());
pairpool.erase (std :: remove (pairpool.begin (), pairpool.end (), newSet), pairpool.end ());
Pause; // really needed this breakout statement
}
}
}
}
if (! alrExists)
{
newSet.insert (pairs[i][0])
newSet.insert (pairs[i][1])
pairpool.push_back (newSet);
}
}

// create a sorted string pool structure
for (auto p: pairpool)
{
std :: vector newset;
for (auto ele: p)
{
newset.push_back (str.substr (ele - 1, 1));
}
std :: sort (newset.begin (), newset.end ());
stringpool.push_back (newset);
}

// use stringpool and pairpool to change the string only once
int counter = 0;
for (auto p: pairpool)
{
for (auto ele: p)
{
str.replace (ele - 1, 1, stringpool[counter].return());
stringpool[counter].pop_back ();
}
counter ++;
}

back str;
}

int main ()
{
std :: cost << swapLexOrder ("acxrabdz", {{1, 3}, {6, 8}, {3, 8}, {2, 7}}) << " n";
std :: string STR = "lvvyfrbhgiyexoirhunnuejzhesylojwbyatfkrv";
std :: vector <std :: vector> PAIR =
{
{13, 23},
{13, 28},
{15, 20},
{24, 29},
{6, 7},
{3, 4},
{21, 30},
{2, 13},
{12, 15},
{19, 23},
{10, 19},
{13, 14},
{6, 16},
{17, 25},
{6, 21},
{17, 26},
{5, 6},
{12, 24}
};
std :: cost << swapLexOrder (STR, PAIR) << " n";
returns 0;
}
``````

.

## Among the javascript code snippet below, which one is considered the most appropriate?

Scenario 1:

``````                                                                    try{
elements.personWrapper.getElement (& # 39; span[name=personClass]& # 39;) .set (& # 39; innerHTML & # 39;; & # 39;);
} catch (TypeError) {
elements.personWrapper.getElement (& # 39; input[name=personClass]& # 39;) .set (& # 39; innerHTML & # 39;; & # 39;);
}
``````

Scenario 2:

``````                                                                                var span_element = elements.personWrapper.getElement (& # 39; span[name=personClass]& # 39;);
var input_element = elements.personWrapper.getElement (& # 39; input[name=personClass]& # 39;);
if (span_element) {
span_element.set (& # 39; innerHTML & # 39;; & # 39;);
}
else if (input_element) {
input_element.set ('value', & # 39;); & # 39;);
}
``````

The above code fragment serves the same purpose (please disregard legibility and naming conventions, they have been changed). So, I would like to know which one is the best. Anyone please provide your valuable suggestions.

Please note that one of the two is defined while the page is loading. The span and input elements are dynamically created. The goal is therefore to define innerHTML if it is an extent or value if it is an input type element.

I want to know which code snippet is the most efficient in terms of code execution and less prone to errors, thanks!

## 5 awards are spread among 20 students What is the probability that a particular student will receive 3 awards?

There are 5 prizes to be distributed to 20 students. What is the probability that a particular student will receive 3 awards?

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## Which search engine is the best among Google, Yahoo and Bing?

Just remember that online research is no longer limited to interactions in search engine websites. Cards are also essential, especially for stores.

Google takes the cake here too, but Here Maps are the most commonly used maps for in-dash GPS navigation systems. A good list can make all the difference.