sharepoint online – Running SPFx gulp bundle in Docker container takes extremely long to start – why?

I’m running SPFx builds in a Docker container which works well. The approach is described here: https://github.com/waldekmastykarz/docker-spfx I’m using WSL2 and Ubuntu.

But unfortunately running gulp build --ship takes extreemely long to start. After running the command in the Docker container there is a delay of more than 60 seconds here:

enter image description here

After this long pause the build starts. Where is this pause coming from?

Running the command locally makes a pause for about 10 seconds before it starts.

I tested with a newly created SPFx project and here are the results:

gulp bundle --ship run locally:

enter image description here

gulp bundle --ship in the Docker container:

enter image description here

The bundling takes 38s longer in the container which would be fine (I guess). But apart from bundling the container spends 1 minute and 18 seconds doing something else. But what?? Any hints are appreciated.

Manyvendor – eCommerce & Multi-vendor CMS Bundle

Manyvendor is a Laravel based CMS application especially to develop eCommerce or multivendor websites. This CMS Application is unique, totally business-oriented, customer-friendly, seller-friendly, and easy to use. Admin has full control over the seller activities and customer activities.

Manyvendor has been developed based on Laravel 7 and some other advanced technologies so that the user of this application can install, configure, and…

.

remove minimum and maximum price of product bundle magento 2

I’m configuring the bundle products, and I needed to configure it in an exact way, and the minimum and maximum value kept appearing, how can I leave only one value like in normal products? below I’ll put a picture of what’s happening.

enter image description here

Set bundle quantity size Woocommerce

I have a webshop and people can order from the moment they have selected a minimum of 6 items.
Now I have a bundle package item that contains 12 items. However Woocommerce sees this as one item. How can I define that this bundle contains 12 items?

Kind regards,

Stijn

ag.algebraic geometry – Why is this $ mathbb{G}_{a} $ bundle trivial

Please tell me why the following example of a principal $ mathbb{G}_{a} $-bundle over an affine ring is trivial. Let $ {x_{1},x_{2},x_{3}} $ a basis of $ mathbf{V}^{ast} $, $ c_{1}(t),c_{2}(t) $ two non-zero, linearly independent, additive polynomials such that the only common root is zero, and $ beta: mathbb{G}_{a} to operatorname{GL}(mathbf{V}) $ be the representation whose co-action is the following one:
begin{align*}
beta^{sharp}(x_{1}) &= x_{1} \
beta^{sharp}(x_{2}) &= x_{2} \
beta^{sharp}(x_{3}) &= x_{3}+c_{2}(t)x_{2}+c_{1}(t)x_{1}.
end{align*}

The stabilizer of any closed point $ y in D(x_{1}x_{2}) $ is equal to $ 0 $. Therefore $ D(x_{1}x_{2}) $ is a principal $ mathbb{G}_{a} $-bundle over its image in $ operatorname{Spec}(k(x_{1},x_{2},x_{3})^{mathbb{G}_{a}}) $. By a theorem of Demazure, Gabriel, and others it is a trivial $ mathbb{G}_{a} $-bundle.

If a variety $ X $ is a trivial $ mathbb{G}_{a} $-bundle over $ Y $, then there is clearly a separable $ mathbb{G}_{a} $-equivariant map from $ X $ to $ mathbb{G}_{a} $. If there is a separable $ mathbb{G}_{a} $-equivariant map $ phi: X to mathbb{G}_{a} $, then let $ Y $ be the fibre over $ 0 $. There is an isomorphism $ psi: mathbb{G}_{a} times Y to X $ which sends $ (t,y) $ to $ t ast y $. The inverse to $ psi $ is the map which sends $ x $ to $ left(phi(x), left(-phi(x)right) ast xright) $. This shows that a variety $ X $ is a trivial $ mathbb{G}_{a} $-bundle over $ X//mathbb{G}_{a} $ if and only if there is a separable, $ mathbb{G}_{a} $-equivariant morphism $ phi: X to mathbb{G}_{a} $.

If $ D(x_{1}x_{2}) $ is a trivial $ mathbb{G}_{a} $-bundle over $ operatorname{Spec}(k(x_{1},x_{2},x_{3})_{x_{1}x_{2}}^{mathbb{G}_{a}}) cong operatorname{Spec}(k(x_{1},x_{2})_{x_{1}x_{2}}) $, then there is a $ mathbb{G}_{a} $-equivariant morphism $ phi: D(x_{1}x_{2}) to mathbb{G}_{a} $.

If $ Delta_{mathbb{G}_{a}}: mathbb{G}_{a} times mathbb{G}_{a} to mathbb{G}_{a} $ is the multiplication morphism of $ mathbb{G}_{a} $, then the existence of the morphism $ phi $ means that
begin{equation*}
Delta_{mathbb{G}_{a}} circ (operatorname{id}_{mathbb{G}_{a}}, phi) = phi circ beta
end{equation*}

A consequence of this is that if $ phi^{sharp}(t) = g(X)/(x_{1}x_{2})^{e} $, then
begin{align*}
beta^{sharp}(g(X)/(x_{1}x_{2})^{e}) &= beta^{sharp} circ phi^{sharp}(t) \
&= (operatorname{id}_{k(t)} otimes phi^{sharp}) circ Delta^{sharp}(t) \
&= (operatorname{id}_{k(t)} otimes phi^{sharp})(t otimes 1 + 1 otimes t) \
&= t+g(X)/(x_{1}x_{2})^{e}
end{align*}

Assume that $ g(X) = sum_{j=0}^{d} x_{3}^{j} g_{j}(x_{1},x_{2}) $. Since
begin{align*}
beta^{sharp}(g(X)-g_{0}(x_{1},x_{2})) &= beta^{sharp}(g(X))-g_{0}(x_{1},x_{2}) \
&= g(X)+t(x_{1}x_{2})^{e}-g_{0}(x_{1},x_{2}) \
&= g(X)-g_{0}(x_{1},x_{2})+t(x_{1}x_{2})^{e}
end{align*}

the pair of polynomials $ (g(X)-g_{0}(x_{1},x_{2}),(x_{1}x_{2})^{e}) $ has the same property as the pair $ (g(X),(x_{1}x_{2})^{e}) $. As a result, we may assume for the next part that $ x_{3} $ divides $ g(X) $. Because $ c_{1}(t),c_{2}(t) $ are additive polynomials, the following identities hold:
begin{multline*}
beta^{sharp}left( x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1} right) \
= beta^{sharp}(x_{3})+c_{2}(beta^{sharp}(-g(X)/(x_{1}x_{2})^{e}))x_{2}+c_{1}(beta^{sharp}(-g(X)/(x_{1}x_{2})^{e}))x_{1} \
= x_{3}+c_{2}(t)x_{2}+c_{1}(t)x_{1}+c_{2}(-g(X)/(x_{1}x_{2})^{e}-t)x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e}-t)x_{1} \
= x_{3}+(c_{2}(t)-c_{2}(t))x_{2}+(c_{1}(t)-c_{1}(t))x_{1}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1} \
=x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1}.
end{multline*}

This shows that if $ beta^{sharp}(g(X)) = g(X)+t(x_{1}x_{2})^{e} $, then $ x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1} $ is an invariant rational function. However, by our assumption that $ x_{3} $ divides $ g(X) $, we know that
begin{align*}
x_{3} & mid left(x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1}right)\
& in k(x_{1},x_{2},x_{3})_{x_{1}x_{2}}^{mathbb{G}_{a}} \
& = k(x_{1},x_{2})_{x_{1}x_{2}}.
end{align*}

This is a contradiction. What is the error here?

entities – How to alter entity -> bundle ->add form with custom form mode programatically Drupal 8

I have created a custom entity type called custom_enitity and new bundle scores, using UI. Also got custom form display called score to add score via custom route. I keep getting the following error message.

DrupalCoreEntityEntityStorageException: Missing bundle for entity
type custom_entity in
DrupalCoreEntityContentEntityStorageBase->doCreate() (line 108 of
core/lib/Drupal/Core/Entity/ContentEntityStorageBase.php)

my_module.routing.yml

custom_entity.score:
  path: '/entry/{entry_id}/score'
  defaults:
    _entity_form: custom_entity.score
  requirements:
    _role: 'administrator+judge'
  options:
    parameters:
      entry:
        type: entity:entry

In my folder I have this structure:

custom_entity/src/Form/CustomEntityScoreForm.php

and the name of the class in the file is

class CustomEntityScoreForm extends ContentEntityForm

How do I add bundle (scores) to the routing file, or what am I missing here?

differential geometry – Local coordinates of one form on a principal bundle

I am reading Natural and Gauge Natural Formalism for Classical Field Theory by Lorenzo Fatibene and I am really confused by his definition of a connection in local coordinates.

Let’s say we have a principal bundle $mathcal{P}=(P, M, pi ; G)$ and the isomorphism $T_{e} L_{p}: mathfrak{g} longrightarrow V_{p}(pi): T_{A} mapsto lambda_{A}(p)$. He fixes a point $p=(x, g)_{(alpha)}$. $theta_{(L)}^{A}=bar{L}_{a}^{A}(g) mathrm{d} g^{a}$ is the local basis of left invariant 1-forms dual to $lambda_{A}=L_{A}^{a}(g) partial_{a}$ where the two matrices are inverse of each other. Then the connection one form can be written as
begin{equation}
bar{omega}_{p}=left(theta_{(L)}^{A}(p)+mathrm{Ad}_{B}^{A}left(g^{-1}right) omega_{mu}^{B}(x) mathrm{d} x^{mu}right) otimes T_{A}
end{equation}

Pulling back with a section, he gets
begin{equation}sigma^{*} bar{omega}=left(bar{L}_{a}^{A}(g) partial_{mu} g^{a}(x)+mathrm{Ad}_{B}^{A}left(g^{-1}right) omega_{mu}^{B}(x)right) mathrm{d} x^{mu} otimes T_{A}
end{equation}

However, then he goes on saying “We remark that the local gauge $sigma$ also induces a local trivialization of $mathcal{P}$. In the induces local trivialization, the section $sigma$ has the expression $sigma: x^{mu} mapstoleft(x^{mu}, eright)$ and the vector potential is of the form”

begin{equation}
sigma^{*} bar{omega}=omega_{mu}^{A}(x) mathrm{d} x^{mu} otimes T_{A}
end{equation}

He also states that the induces connection is of the form
begin{equation}
omega=mathrm{d} x^{mu} otimesleft(partial_{mu}-omega_{mu}^{A}(x) rho_{A}right)
end{equation}

  1. My first question is how one can derive the expression of $bar{omega}_{p}$?
  2. My section question is why every other book on the subject I know uses $sigma^{*} bar{omega}=omega_{mu}^{A}(x) mathrm{d} x^{mu} otimes T_{A}$ as the definition of a form in local coordinates even this seems not to be true for a general section.
  3. I am also not sure how one can derive the form of the induced connection.

at.algebraic topology – $pi_{2n-1}(operatorname{SO}(2n))$ element represents the tangent bundle $TS^{2n}$, not torsion and indivisible?

Question: Is the element $alpha$ in $pi_{2n-1}(operatorname{SO}(2n))$ representing the tangent bundle $TS^{2n}$ of the sphere $S^{2n}$ indivisible and not torsion?

My understanding so far —

An $operatorname{SO}(2n)$ bundle over $S^{2n}$ corresponds to an element in $pi_{2n}operatorname{BSO}(2n) =pi_{2n-1}operatorname{SO}(2n)$.

Not torsion: There does not exist any integer $m > 0$ such that $malpha$ is a trivial element.

Indivisible: There does not exist any integer $k > 1$ and any element $beta$ in $pi_{2n-1}operatorname{SO}(2n)$ such that $alpha=kbeta$.

Ref: Mimura, Toda: Topology of Lie groups. Chapter IV Corollary 6.14.

big sur – Mounting Sparse Bundle on NFS Share

Background

I have a Seagate BlackArmor NAS220 running Debian. I would like to use the NAS as a target for Time Machine backups from my Mac (2020 Mac mini M1). I have used disk utility to create a 500 GB sparse bundle disk image (HFS+J). I can mount the sparse bundle on my computer no problem when it is stored locally. I then copy the sparse bundle to my NAS.

Problem

When I try to mount the sparse bundle on my Mac while it is stored on the NAS (by double-clicking on it) I get the following error:

error1

When I double click on it again I get this error:

error2

Attempting to mount via the Terminal using,

sudo hdiutil attach -verbose /path-to-network-share/MacminiTM.sparsebundle/

results in,

Mac-mini:Time Machine Backups christopher$ sudo hdiutil attach -verbose /path-to-network-share/MacminiTM.sparsebundle/
Initializing…
CBSDBackingStore::newProbe directory, not a valid image file.
DIBackingStoreInstantiatorProbe: interface  0, score    -1000, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score     1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
DIBackingStoreInstantiatorProbe: interface  0, score      100, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score    -1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
CBSDBackingStore::newProbe directory, not a valid image file.
DIBackingStoreInstantiatorProbe: interface  0, score    -1000, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score     1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
DIBackingStoreInstantiatorProbe: interface  0, score      100, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score    -1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
Attaching…
Error 5 (Input/output error).
Finishing…
DIHLDiskImageAttach() returned 5
hdiutil: attach failed - Input/output error

I can’t figure out why the sparse bundle mounts fine when it’s stored on my Mac locally, but not when on the network share.

Is This Good Copy? Patience Is Key (A pitch to sell my 3-in-1 devotional bundle)

Are you impatient? Are you constantly hard on yourself for not living up to social norms? You are not alone. As a young Christian in my 20s, I often feel like I have to prove my maturity to my family and the world.

Last year I felt like a total failure because I didn’t live up to the goal I set to make a living off poetry. Having my Godmother scold me about it on Thanksgiving Day only made matters worst, and I fell into a deep depression; I was so depressed I have didn’t feel like eating on a day that’s about eating.

Fast-forward to a few months later, I started my blog, and I began to learn what it means to wait on God. Now, I’m one of the top-rated Christian bloggers on Google with over 35 5-stars reviews (at only age 24), and I build a tiktok following of over 5,000 followers. God has used my mess and turn it into a message.

It’s hard being patient when you’re young, especially in this F.O.M.O (Fear Of Missing Out) society. That is why I created a devotional titled Patience is Key To Happiness to help Young Christians to be content in every season of life.

If you buy my devotional, you will get two other devotionals titled (Peace Beyond Understanding and Confidence In Jesus) bundled together for $20. If you buy my devotional, you’ll also get an opportunity to video chat with me on Youtube. If you are tired of being miserable and stressed out buy my devotional Peace Beyond Understanding today at https://payhip.com/b/wLjt.
SEMrush