## sharepoint online – Running SPFx gulp bundle in Docker container takes extremely long to start – why?

I’m running SPFx builds in a Docker container which works well. The approach is described here: https://github.com/waldekmastykarz/docker-spfx I’m using WSL2 and Ubuntu.

But unfortunately running `gulp build --ship` takes extreemely long to start. After running the command in the Docker container there is a delay of more than 60 seconds here:

After this long pause the build starts. Where is this pause coming from?

Running the command locally makes a pause for about 10 seconds before it starts.

I tested with a newly created SPFx project and here are the results:

`gulp bundle --ship` run locally:

`gulp bundle --ship` in the Docker container:

The bundling takes 38s longer in the container which would be fine (I guess). But apart from bundling the container spends 1 minute and 18 seconds doing something else. But what?? Any hints are appreciated.

## Manyvendor – eCommerce & Multi-vendor CMS Bundle

Manyvendor is a Laravel based CMS application especially to develop eCommerce or multivendor websites. This CMS Application is unique, totally business-oriented, customer-friendly, seller-friendly, and easy to use. Admin has full control over the seller activities and customer activities.

Manyvendor has been developed based on Laravel 7 and some other advanced technologies so that the user of this application can install, configure, and…

.

## remove minimum and maximum price of product bundle magento 2

I’m configuring the bundle products, and I needed to configure it in an exact way, and the minimum and maximum value kept appearing, how can I leave only one value like in normal products? below I’ll put a picture of what’s happening.

## Set bundle quantity size Woocommerce

I have a webshop and people can order from the moment they have selected a minimum of 6 items.
Now I have a bundle package item that contains 12 items. However Woocommerce sees this as one item. How can I define that this bundle contains 12 items?

Kind regards,

Stijn

## ag.algebraic geometry – Why is this \$ mathbb{G}_{a} \$ bundle trivial

Please tell me why the following example of a principal $$mathbb{G}_{a}$$-bundle over an affine ring is trivial. Let $${x_{1},x_{2},x_{3}}$$ a basis of $$mathbf{V}^{ast}$$, $$c_{1}(t),c_{2}(t)$$ two non-zero, linearly independent, additive polynomials such that the only common root is zero, and $$beta: mathbb{G}_{a} to operatorname{GL}(mathbf{V})$$ be the representation whose co-action is the following one:
begin{align*} beta^{sharp}(x_{1}) &= x_{1} \ beta^{sharp}(x_{2}) &= x_{2} \ beta^{sharp}(x_{3}) &= x_{3}+c_{2}(t)x_{2}+c_{1}(t)x_{1}. end{align*}
The stabilizer of any closed point $$y in D(x_{1}x_{2})$$ is equal to $$0$$. Therefore $$D(x_{1}x_{2})$$ is a principal $$mathbb{G}_{a}$$-bundle over its image in $$operatorname{Spec}(k(x_{1},x_{2},x_{3})^{mathbb{G}_{a}})$$. By a theorem of Demazure, Gabriel, and others it is a trivial $$mathbb{G}_{a}$$-bundle.

If a variety $$X$$ is a trivial $$mathbb{G}_{a}$$-bundle over $$Y$$, then there is clearly a separable $$mathbb{G}_{a}$$-equivariant map from $$X$$ to $$mathbb{G}_{a}$$. If there is a separable $$mathbb{G}_{a}$$-equivariant map $$phi: X to mathbb{G}_{a}$$, then let $$Y$$ be the fibre over $$0$$. There is an isomorphism $$psi: mathbb{G}_{a} times Y to X$$ which sends $$(t,y)$$ to $$t ast y$$. The inverse to $$psi$$ is the map which sends $$x$$ to $$left(phi(x), left(-phi(x)right) ast xright)$$. This shows that a variety $$X$$ is a trivial $$mathbb{G}_{a}$$-bundle over $$X//mathbb{G}_{a}$$ if and only if there is a separable, $$mathbb{G}_{a}$$-equivariant morphism $$phi: X to mathbb{G}_{a}$$.

If $$D(x_{1}x_{2})$$ is a trivial $$mathbb{G}_{a}$$-bundle over $$operatorname{Spec}(k(x_{1},x_{2},x_{3})_{x_{1}x_{2}}^{mathbb{G}_{a}}) cong operatorname{Spec}(k(x_{1},x_{2})_{x_{1}x_{2}})$$, then there is a $$mathbb{G}_{a}$$-equivariant morphism $$phi: D(x_{1}x_{2}) to mathbb{G}_{a}$$.

If $$Delta_{mathbb{G}_{a}}: mathbb{G}_{a} times mathbb{G}_{a} to mathbb{G}_{a}$$ is the multiplication morphism of $$mathbb{G}_{a}$$, then the existence of the morphism $$phi$$ means that
$$begin{equation*} Delta_{mathbb{G}_{a}} circ (operatorname{id}_{mathbb{G}_{a}}, phi) = phi circ beta end{equation*}$$
A consequence of this is that if $$phi^{sharp}(t) = g(X)/(x_{1}x_{2})^{e}$$, then
begin{align*} beta^{sharp}(g(X)/(x_{1}x_{2})^{e}) &= beta^{sharp} circ phi^{sharp}(t) \ &= (operatorname{id}_{k(t)} otimes phi^{sharp}) circ Delta^{sharp}(t) \ &= (operatorname{id}_{k(t)} otimes phi^{sharp})(t otimes 1 + 1 otimes t) \ &= t+g(X)/(x_{1}x_{2})^{e} end{align*}
Assume that $$g(X) = sum_{j=0}^{d} x_{3}^{j} g_{j}(x_{1},x_{2})$$. Since
begin{align*} beta^{sharp}(g(X)-g_{0}(x_{1},x_{2})) &= beta^{sharp}(g(X))-g_{0}(x_{1},x_{2}) \ &= g(X)+t(x_{1}x_{2})^{e}-g_{0}(x_{1},x_{2}) \ &= g(X)-g_{0}(x_{1},x_{2})+t(x_{1}x_{2})^{e} end{align*}
the pair of polynomials $$(g(X)-g_{0}(x_{1},x_{2}),(x_{1}x_{2})^{e})$$ has the same property as the pair $$(g(X),(x_{1}x_{2})^{e})$$. As a result, we may assume for the next part that $$x_{3}$$ divides $$g(X)$$. Because $$c_{1}(t),c_{2}(t)$$ are additive polynomials, the following identities hold:
$$begin{multline*} beta^{sharp}left( x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1} right) \ = beta^{sharp}(x_{3})+c_{2}(beta^{sharp}(-g(X)/(x_{1}x_{2})^{e}))x_{2}+c_{1}(beta^{sharp}(-g(X)/(x_{1}x_{2})^{e}))x_{1} \ = x_{3}+c_{2}(t)x_{2}+c_{1}(t)x_{1}+c_{2}(-g(X)/(x_{1}x_{2})^{e}-t)x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e}-t)x_{1} \ = x_{3}+(c_{2}(t)-c_{2}(t))x_{2}+(c_{1}(t)-c_{1}(t))x_{1}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1} \ =x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1}. end{multline*}$$
This shows that if $$beta^{sharp}(g(X)) = g(X)+t(x_{1}x_{2})^{e}$$, then $$x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1}$$ is an invariant rational function. However, by our assumption that $$x_{3}$$ divides $$g(X)$$, we know that
begin{align*} x_{3} & mid left(x_{3}+c_{2}(-g(X)/(x_{1}x_{2})^{e})x_{2}+c_{1}(-g(X)/(x_{1}x_{2})^{e})x_{1}right)\ & in k(x_{1},x_{2},x_{3})_{x_{1}x_{2}}^{mathbb{G}_{a}} \ & = k(x_{1},x_{2})_{x_{1}x_{2}}. end{align*}
This is a contradiction. What is the error here?

## entities – How to alter entity -> bundle ->add form with custom form mode programatically Drupal 8

I have created a custom entity type called custom_enitity and new bundle scores, using UI. Also got custom form display called score to add score via custom route. I keep getting the following error message.

DrupalCoreEntityEntityStorageException: Missing bundle for entity
type custom_entity in
DrupalCoreEntityContentEntityStorageBase->doCreate() (line 108 of
core/lib/Drupal/Core/Entity/ContentEntityStorageBase.php)

my_module.routing.yml

``````custom_entity.score:
path: '/entry/{entry_id}/score'
defaults:
_entity_form: custom_entity.score
requirements:
options:
parameters:
entry:
type: entity:entry
``````

In my folder I have this structure:

custom_entity/src/Form/CustomEntityScoreForm.php

and the name of the class in the file is

class CustomEntityScoreForm extends ContentEntityForm

How do I add bundle (scores) to the routing file, or what am I missing here?

## differential geometry – Local coordinates of one form on a principal bundle

I am reading Natural and Gauge Natural Formalism for Classical Field Theory by Lorenzo Fatibene and I am really confused by his definition of a connection in local coordinates.

Let’s say we have a principal bundle $$mathcal{P}=(P, M, pi ; G)$$ and the isomorphism $$T_{e} L_{p}: mathfrak{g} longrightarrow V_{p}(pi): T_{A} mapsto lambda_{A}(p)$$. He fixes a point $$p=(x, g)_{(alpha)}$$. $$theta_{(L)}^{A}=bar{L}_{a}^{A}(g) mathrm{d} g^{a}$$ is the local basis of left invariant 1-forms dual to $$lambda_{A}=L_{A}^{a}(g) partial_{a}$$ where the two matrices are inverse of each other. Then the connection one form can be written as
$$begin{equation} bar{omega}_{p}=left(theta_{(L)}^{A}(p)+mathrm{Ad}_{B}^{A}left(g^{-1}right) omega_{mu}^{B}(x) mathrm{d} x^{mu}right) otimes T_{A} end{equation}$$
Pulling back with a section, he gets
$$begin{equation}sigma^{*} bar{omega}=left(bar{L}_{a}^{A}(g) partial_{mu} g^{a}(x)+mathrm{Ad}_{B}^{A}left(g^{-1}right) omega_{mu}^{B}(x)right) mathrm{d} x^{mu} otimes T_{A} end{equation}$$
However, then he goes on saying “We remark that the local gauge $$sigma$$ also induces a local trivialization of $$mathcal{P}$$. In the induces local trivialization, the section $$sigma$$ has the expression $$sigma: x^{mu} mapstoleft(x^{mu}, eright)$$ and the vector potential is of the form”

$$begin{equation} sigma^{*} bar{omega}=omega_{mu}^{A}(x) mathrm{d} x^{mu} otimes T_{A} end{equation}$$
He also states that the induces connection is of the form
$$begin{equation} omega=mathrm{d} x^{mu} otimesleft(partial_{mu}-omega_{mu}^{A}(x) rho_{A}right) end{equation}$$

1. My first question is how one can derive the expression of $$bar{omega}_{p}$$?
2. My section question is why every other book on the subject I know uses $$sigma^{*} bar{omega}=omega_{mu}^{A}(x) mathrm{d} x^{mu} otimes T_{A}$$ as the definition of a form in local coordinates even this seems not to be true for a general section.
3. I am also not sure how one can derive the form of the induced connection.

## at.algebraic topology – \$pi_{2n-1}(operatorname{SO}(2n))\$ element represents the tangent bundle \$TS^{2n}\$, not torsion and indivisible?

Question: Is the element $$alpha$$ in $$pi_{2n-1}(operatorname{SO}(2n))$$ representing the tangent bundle $$TS^{2n}$$ of the sphere $$S^{2n}$$ indivisible and not torsion?

My understanding so far —

An $$operatorname{SO}(2n)$$ bundle over $$S^{2n}$$ corresponds to an element in $$pi_{2n}operatorname{BSO}(2n) =pi_{2n-1}operatorname{SO}(2n)$$.

Not torsion: There does not exist any integer $$m > 0$$ such that $$malpha$$ is a trivial element.

Indivisible: There does not exist any integer $$k > 1$$ and any element $$beta$$ in $$pi_{2n-1}operatorname{SO}(2n)$$ such that $$alpha=kbeta$$.

Ref: Mimura, Toda: Topology of Lie groups. Chapter IV Corollary 6.14.

## big sur – Mounting Sparse Bundle on NFS Share

Background

I have a Seagate BlackArmor NAS220 running Debian. I would like to use the NAS as a target for Time Machine backups from my Mac (2020 Mac mini M1). I have used disk utility to create a 500 GB sparse bundle disk image (HFS+J). I can mount the sparse bundle on my computer no problem when it is stored locally. I then copy the sparse bundle to my NAS.

Problem

When I try to mount the sparse bundle on my Mac while it is stored on the NAS (by double-clicking on it) I get the following error:

When I double click on it again I get this error:

Attempting to mount via the Terminal using,

`sudo hdiutil attach -verbose /path-to-network-share/MacminiTM.sparsebundle/`

results in,

``````Mac-mini:Time Machine Backups christopher\$ sudo hdiutil attach -verbose /path-to-network-share/MacminiTM.sparsebundle/
Initializing…
CBSDBackingStore::newProbe directory, not a valid image file.
DIBackingStoreInstantiatorProbe: interface  0, score    -1000, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score     1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
DIBackingStoreInstantiatorProbe: interface  0, score      100, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score    -1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
CBSDBackingStore::newProbe directory, not a valid image file.
DIBackingStoreInstantiatorProbe: interface  0, score    -1000, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score     1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
DIBackingStoreInstantiatorProbe: interface  0, score      100, CBSDBackingStore
DIBackingStoreInstantiatorProbe: interface  1, score    -1000, CBundleBackingStore
DIBackingStoreInstantiatorProbe: interface  2, score    -1000, CRAMBackingStore
DIBackingStoreInstantiatorProbe: interface  3, score    -1000, CDevBackingStore
DIBackingStoreInstantiatorProbe: interface  4, score    -1000, CCURLBackingStore
DIBackingStoreInstantiatorProbe: interface  5, score    -1000, CVectoredBackingStore
Attaching…
Error 5 (Input/output error).
Finishing…
DIHLDiskImageAttach() returned 5
hdiutil: attach failed - Input/output error
``````

I can’t figure out why the sparse bundle mounts fine when it’s stored on my Mac locally, but not when on the network share.

## Is This Good Copy? Patience Is Key (A pitch to sell my 3-in-1 devotional bundle)

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