The query in Mongo does not work when I have a compound property (one inside the other)

I'm trying to make a query in the mongo database, when I have a simple property such as:

About me

Works without problems

But if I have a composite property such as:

Product identifier:
{
PP: 2
M: 4
G: 10
}

The query returns no value, I try to deploy a query to return all the values ​​that are PP and less than 10 for example, but, unlike what happens in a simple query, I can not succeed.

Below the code

router.get (& # 39; / products & # 39; function (req, res) {

_product.paginate (
{quantity: {PP: {$ lt: 10}}},
{limit: 21, page: req.query.pag, sort: {name: asc},

(err, res) => {
if (! res.page) {
res.page = 1
res.nextPage = 2
res.hasPrevPage = false
res.hasNextPage = true
}
return res

}). then (function (product) {
res.render ('products', {product: product.docs, pag: product})
})
})

Below, the schema, the query works for all simple properties, only for composites in trouble, probably a failure

const mongoose = require ("mongoose")
const mongoosePaginate = require (-mongoose-paginate-v2 & # 39;)
const Schema = mongoose.Schema

const Product = new Schema ({
name: {
type: chain,
required: true
}
Mark: {
type: chain,
required: true
}
slug: {
type: chain,
required: true
}
category: {
type: chain,
required: true
}
amount: {
PP: {
type: number,
required: false
}
P: {
type: number,
required: false
}
M: {
type: number,
required: false
}
G: {
type: number,
required: false
}
GG: {
type: number,
required: false
}
_1: {
type: number,
required: false
}
_2: {
type: number,
required: false
}
_3: {
type: number,
required: false
}
_4: {
type: number,
required: false
}
_5: {
type: number,
required: false
}
_6: {
type: number,
required: false
}
_7: {
type: number,
required: false
}
_8: {
type: number,
required: false
}
9: {
type: number,
required: false
}
_10: {
type: number,
required: false
}
_12: {
type: number,
required: false
}
_14: {
type: number,
required: false
}
_16: {
type: number,
required: false,
}
}
season: {
type: chain,
required: true
}
description:
type: chain,
required: true
}
price: {
type: number,
required: true
}
kind: {
type: chain,
required: true
}
color: {
type: chain,
required: true
}
discount: {
type: number,
required: true
}
width: {
type: number,
required: true
}
height: {
type: number,
required: true
}
length: {
type: number,
required: true,
}
weight: {
type: number,
required: true
}
photos: {
photo1: {
type: chain,
required: false
}
photo2: {
type: chain,
required: false
}
photo3: {
type: chain,
required: false
}
photo4: {
type: chain,
required: false
}
photo5: {
type: chain,
required: false
}
}
inscription: {
type: date,
default: Date.now ()
}
})

Product.plugin (MangoosePaginate)

Mongoose.model ('product', Product)

I'm using mongoose next to paged mongoose

mysql – Compound key (Embeddable) generating an error while running DDL – Spring data JPA

I want to create a composite key in an entity, but when the table is going to be generated in mysql, the following error occurs:

org.hibernate.tool.schema.spi.CommandAcceptanceException: DDL runtime error via a JDBC statement

In the details, it is stated that a length of the key was not specified because it is a Blob / Text field as below:

Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: The "request" BLOB / TEXT column used in the key specification without key length

The code generated in the DDL is incorrect because the fields must be numeric and not those specified in the error:

create a table evaluation (
request tinyblob not null,
tiny non-zero seller,
varchar score (255),
primary key
) engine = MyISAM

The class is the following and has mapped a long key as the primary key:

@Entity
public class Request implements Serializable {

private static final long serialVersionUID = 1L;

id
private Long id;
private user;
private Date RequestDate;
private Date of shipment;
private date processing;
private date delivery;
private date of finalization;
private BigDecimal rateCompra;
status of private request status;
privatePaymentPaymentPaymentPayment;
private Endereco Delivery addressDelivery;
private user purchaser;
delivery by the private user;
private set items = new HashSet <> ();

... GetSet ... constrution ...

The provider entity class also inherits a long field as the id, specified in the PersonJuridica entity.

        public class Seller extends PersonJuridica {
private static final long serialVersionUID = 1L;

private phoneSAC channel;
private Boolean performs;
private segment segment;
private set Neighborhoods = New HashSet <> ();
private set itemsSeller = new HashSet <> ();
private Boolean vendaActive;
private BigDecimal rateSeller;

public seller () {
Great ();
}

public provider (long identifier, string pass, string name, email address, active boolean, TypePerson type, cnpj string, StringoSocial,
StringInteractiveString, String nameRepresentant, String phoneRepresentant,
EmailRepresenting String, StringSAC phone, Boolean performDelivery, Boolean saleActive, BigDecimal Merchant Rate) {
super (username, password, name, email, active, type, cnpj, rankSocial, enrollment, nameRepresentant,
emailReprésentant);
this.telephoneSAC = phoneSAC;
this.realizesDelivery = realizesDelivery;
this.vendaActive = sellAtiva;
this.TextSeller = RateSeller;
} ...

I want to build an evaluation entity as below, where the id is a composite key using @EmbeddedId annotation:

@Entity
public class Evaluation implements Serializable {

private static final long serialVersionUID = 1L;

@EmbeddedId
private EvaluatePK id = new EvaluatePK ();

@Enumerated (EnumType.STRING)
Private score EvaluationAum;
...

The class that represents the composite key is the APK evaluation below:

@ Embeddable
The public class EvaluationPK implements Serializable {

private static final long serialVersionUID = 1L;

@ManyToOne
private demand request;

@ManyToOne
private seller;
...

I do not identify the cause of the generation of the wrong DDL file in the composite key, which prevents you from creating the table.

Here is the configuration of the spring date to access the database tables and create them in Application.properties.

spring.jpa.hibernate.ddl-auto = update
spring.datasource.url = jdbc: mysql: // localhost: 3306 / voucompreidb? useSSL = false
spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQL5Dialect

spring.datasource.username = user
spring.datasource.password = 12345

spring.jpa.show-sql = true
spring.jpa.properties.hibernate.format_sql = true

Films on social justice compound the problem! | Promotion Forum

about us

Forum Promotion is a webmaster forum that focuses on internet marketing to help webmasters and administrators make their website perform.

On Forum Promotion, you can expand your website by posting ads on our directory, by buying free ads or by trading. You can also ask the help of experienced webmasters in our discussion section.

logarithms – How to calculate compound interest annually?

I have some difficulty understanding this topic of interest rates.

For example, if I invest 1 dollar at a continuous compound rate of 11%, my end-of-year value is 0.11 e = 1.116 dollars. From there, it is stated that investing at 11% per year without interruption corresponds to an investment of 11.6% per year.

Now, where does this 11.6 come from? Does it come from the value of 1. (116) dollars? So, I just take the 0.116 decimal and turn it into a percentage?

Another question that I have concerns this problem:

Suppose the compound annual rate is 18.5%. The current value of a 100 USD in perpetuity, with each cash flow received at the end of the year, is 100 / 0.185 = $540.54. If the cash flow is received continuously, we must divide $ 100 by 17% because 17% compounded continuously equals 18.5% compounded annually (stating that e = 0.17 = 1.185).

What is the relationship between the annual compound rate and the permanently compounded rate? How to use one to calculate the other? I am very confused.

ssh – Does Pageant voluntarily apply a compound password to a few keys in a row?

In another thread, I asked a question about passwords and its mechanism to avoid being compromised in case of large amount of data example – https://unix.stackexchange.com/questions/ 500845 / is-using-the-one-passphrase-for-many-safes

What brought me here is Pageant, which recalls the secret phrase entered on one key and applies it to the other key. So, if I have two keys with the same passphrase in Pageant, I have to enter the passphrase once – is this the desired behavior?

google sheets – compound interest, current value

How can I calculate the present value of a sum deposited in a past date, with a fixed interest rate.

For example, if $ 1,000 was deposited on 1/1/2000 in an account that pays an annual rate of 3%, what would be their value today?

Looking for a formula that can be used in Google Sheets of Excel

construction of the function – Obtaining a non-zero output of all parts of a compound expression

I decided to post this question and this personal answer as this could be helpful to other people wishing to do the same thing.

I was wondering how to get a non-zero output of all parts of a compound expression. By default, only the result of the last part of a compound expression is generated, for example:

fun1[expr_] : = (expr + x; expr + y; expr + z)
fun1[a]

a + z

fun1p: = (# + x; # + y; # + z) &
fun1p[a]

a + z

We could use Print (or Echo) …

fun2[expr_] : = (Print[expr + x]; Impression[expr + y]; Impression[expr + z])
out2 = fun2[a]

a + x

a + y

a + z

… but the output has Null content:

out2

(no output)

The same result is obtained using Print with a pure function.

There are workarounds, but sometimes I find it very convenient to get the outputs directly.

NOTE: There is no duplication of compound statements and previous results returned in parentheses () because the PO was trying to print the results (which displays the results, but the content is Null), whereas I (as explained above) want to: actually get the results (such as I can assign them to variables).

output format – Combination of pure functions containing compound expressions

For display, I sometimes find it desirable to undo the canonical order of the Mathematica variables and to make it display the terms in the order in which I type them. For example, instead of this:

b-a
v = v0 + t
a8 + a9 + a10

-A + b

a t + v0

a10 + a8 + a9

… I would prefer this:

b – a

v0 + t

a8 + a9 + a10

This can be easily accomplished by removing the Orderless attributes from Plus and Times, entering the expression, and immediately restoring these attributes (it is important to do so because their absence alters the basic functionality; for example, without Orderless, Plus does not work, recognize that a + b is mathematically identical to b + a).

ClearAttributes[Plus, Orderless]
ClearAttributes[Times, Orderless]
c (b-a)
SetAttributes[Plus, Orderless]
SetAttributes[Times, Orderless]

c (b – a)

How can I implement the above as a function? That is, I would like to define a function such as:

func[c (b-a)]
c (b-a) (* confirms that Orderless is restored on both Plus and Times *)

c (b – a)

(-A + b) c

Up to now, I have managed only the following, which allows to obtain the desired result, but requires that I enter a function, then the expression, then another function:

func1: = (ClearAttributes[Plus, Orderless]; ClearAttributes[Times, Orderless]) &;
func2: = (SetAttributes[Plus, Orderless]; SetAttributes[Times, Orderless]) &;
func1[_]; c (b-a)
func2[_]
c (b-a)

c (b – a)

(-A + b) c

How do I combine them into one function that takes expression as an argument?

EDIT: Note that I only want to change the display format, not any other feature. For example, the MMA should always recognize that e1 and e2 are mathematically equivalent:

func1[_]
e1 = c (b - a)
e2 = (-a + b) c
func2[_]
e1 == e2

c (b – a)

(-a + b) c

True

[get] compound | Black Hat Forum on SEO and Affiliate Marketing

The hidden 3-digit method by DayOnline PROVEN PROFIT

Do not take our word for it

This is what real people

Are about Compoundly:

Rash Wine

Wow! Honestly, I can not believe that these guys are releasing this system at the price that they are. I saw Paul and Anthony quietly crush him with this method for a while. I was not sure if they were going to publish it or not. Well done guys, this will help a lot of people and create success stories for sure.

Andrew Speers

Hello is Andy Speers from Bangkok, AKA Bangkok-Blacksmith. Long-time friend and promoter of Anthony Mancuso's award-winning products. Do not forget the EZ Passive pay days, full of training. On the verge of launching another mortgage repayment program for Christmas.

About 10 packaged information videos. Get early for the sale of dimes a blue print that earns between $ 5 and $ 10,000 a month. Dive deeper into OTO 1 and get ready for funnels. It does not end there. I recommend Anthony, he is a winner.

Steven Banks

What an incredible training guys. This is precisely what the industry needs now: a surefire way to make money online, with which even the little guy can succeed. Good game!

Warning Price increases in:

Forget the competition, the experience or the payment of announcements – This UNTAPPED system works for everyone.

[proof inside]

  • Untapped and proven method for fast and consistent cash balances in ANY time slot
  • Suitable for beginners at 100% – no technical or technical experience required
  • Be active, on the go and make money in 24 hours or less
  • Totally free traffic – never pay for ads again!
  • BUILT-IN Scale – Stay Seated and Watch Your Profits Rise to Achieve Critical Income
  • Do more for less – free traffic and 30 minutes a day, that's all it takes to accumulate money
  • BATTERY PROOF – results for over 3 years and complete beginners crushing with this method

link to the sales page

ACCESS

member space link

ACCESS

link to the bonus page

ACCESS

java – Is a setter with a compound object as a parameter a better parameter or separate parameters for each parameter of the compound object?

I have two ideas on how to proceed with an availability class, but I'm not sure which one is the best.

Public class TimeRange {
private time stamp startTime;
private endTime timestamp;

public TimeRange () {
// set default values
}
// appropriate getters
// setters
public void setStartTime (Timestamp startTime) {
this.startTime = startTime;
}

public void setEndTime (Timestamp endTime) {
this.endTime = endTime;
}
// a code that validates the object is in a valid state.
}

First idea:

public class WeeklyAvailabilities {
private TimeRange mondaySlot;
private TimeRange tuesdaySlot;
Private TimeRange Wednesday to Wednesday;
private TimeRange thursdaySlot;
private TimeRange fridaySlot;
private TimeRange saturdaySlot;
private TimeRange sundaySlot;

public WeeklyAvailabilities () {
// set default values
}
// getters and others
public void setMondayStartTime (Start timestamp) {
mondaySlot.setStartTime (start);
}

public void setMondayEndTime (end of timestamp) {
mondaySlot.setEndTime (end);
}
// continue the pattern for all slots
}

Second idea:

public class WeeklyAvailabilities {
private TimeRange mondaySlot;
private TimeRange tuesdaySlot;
Private TimeRange Wednesday to Wednesday;
private TimeRange thursdaySlot;
private TimeRange fridaySlot;
private TimeRange saturdaySlot;
private TimeRange sundaySlot;

public WeeklyAvailabilities () {
// set default values
}
// getters and others
public void setMondaySlot (TimeRange mondaySlot) {
this.mondaySlot = mondayaySlot;
}

// continue the pattern for all slots
}

I am in conflict because the first idea does not require the creation of a new object each time, while the second idea would require something of that kind. Really, I wondered if I could know which one is the best or if there could be a third option that I completely ignore.