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I have a SharePoint online list where I have a People Picker field (“PeoplePickerColumn”).
I want to create a new text column (“PeopleTextColumn”) in the list that populates based on the “PeoplePickerColumn” value.
I’m fairly new to SharePoint and do not know JSON.
I want to convert password field to required from optional. I didn’t found any settings to do that. Is any code available to do that?
Please help.
So I am trying to full understand how to decode transactions. In the dev docs it discusses a raw transaction: https://developer.bitcoin.org/reference/transactions.html
in the paragraph “TxOut: A Transaction Output” there is an example. Near the bottom of that example it decodes the bitcoin script. It shows you pushing 20 bytes labeled as the public key has onto the stack.
cbc20a7664f2f69e5355aa427045bc15e7c6c772
That value is autogenerated from “createrawtransaction” cli function which comes from the public key. It specifically references the example here
https://developer.bitcoin.org/examples/transactions.html#simple-raw-transaction
where it says
NEW_ADDRESS=mz6KvC4aoUeo6wSxtiVQTo7FDwPnkp6URG
how are they going from
mz6KvC4aoUeo6wSxtiVQTo7FDwPnkp6URG
to
cbc20a7664f2f69e5355aa427045bc15e7c6c772
? It doesn’t say anywhere in the documentation. Is this just a read the source code situation? I should say I have tried plugging the address into many different hashing calculators. I never get the same result.
I am using CryptoJS AES 256 encryption:
CryptoJS.AES.encrypt(string, secret);
The secret is generated through:
function generateKey(str) {
const salt = CryptoJS.lib.WordArray.random(128 / 8);
const key512Bits = CryptoJS.PBKDF2(str, salt, {
keySize: 512 / 32,
iterations: 100000
});
return key512Bits.toString(<-- base64 or hex -->);
}
But it seems like the returned secret string doesn’t contain any special character if hex or only ‘/,+’ and wierd ending ‘==’ if base64
Is there any way to make the string much more unpredictable?
Thanks!
I have been lately an intensive Notion user which means that I love databases
So I’m trying to extrapolate that workflow to Finder and I am confident it’s possible via smart folders although I don’t know how to apply it
Could somebody show me how to set the filters inside a smart folder in order to show all the files inside without the ‘structural folders’
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I have a mid-size tcl/tk application. No external dependencies. I am thinking about converting it to python/tkinter. I can only find about 10 years old comments about this topic. I am asking for more modern views. I do not want to use tcl code inside python.
The main motivation is that all my current coworkers are young python-based programmers who never wrote a line in tcl. I want that they take care of the application in the future. Is this a right motivation?
Basicaly, I have to rewrite all tcl logic (variables, arrays, if, while, for, etc.) from tcl to python, while all tk commands and widgets (canvas, button, pack, ttk, BWidgets) can be used exactly in the same way. Is this true?
Is there any documentation? Are there any tools to help you?
The converted app could have the same efficiency? It could be even faster? It could consume less RAM?
asked 6 hours ago
992 bronze badges
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lang-py
Use three entry columns — pounds, ounces, kilograms — and two formula columns like this:
=ifs(
(E2 + F2) * G2,
"enter lb+oz, or kg, not both",
E2 + F2,
sum( convert(E2, "lbm", "ozm"), F2 ),
G2,
convert(G2, "kg", "ozm"),
true,
iferror(1/0)
)
=ifs(
(E2 + F2) * G2,
"enter lb+oz, or kg, not both",
E2 + F2,
convert(H2, "ozm", "kg"),
G2,
G2,
true,
iferror(1/0)
)
The formula columns let you see the result in both ounces and kilograms for every entry.
See the new Solution sheet in your sample spreadsheet.
I am coming from old Adobe Fireworks, where converting any shape into a bitmap is as simple as selecting it and click menu Modify -> Flatten Selection, and that’s it.
Unfortunately I have found out there is nothing like that in Photoshop (well, at least nothing I would know of).
Can anyone explain to me how to do this simple task in Photoshop (Google search did not help with this at all)?
As I discovered in researching this question, converting a column from varchar(100)() to text() requires a table rewrite and rebuilding indexes.
Is there a way to manage this conversion without the locking and rewriting through some catalog trickery like that used in this question? Particularly interested in version 10 if possible
Soy nuevo en Pandas todavía, estoy analizando un código utilizando Jupyter.
Estoy analizando el siguiente DataFrame:
Estoy aplicando el siguiente código:
df_empty = pd.DataFrame(columns = ('Horário', 'Temperatura', 'Potência'))
def Fill_df(df_e, df_c):
'''
Função que preenche o dataframe(df_e) com a soma dos power e medias das temperaturas para
um respectivo tempo.
Parametros
df_e: Dataframe vazio para armazenamento dos valores.
df_c: Dataframe usado para calcular o que queremos.
Return
df_e completo
'''
for i in df_c('Horário').unique():
soma = sum(df_c.loc(df_c('Horário') == i)('Potência').astype(float)) # Sum Power
media = np.mean(df_c.loc(df_c('Horário') == i)('Temperatura').astype(float)) # Mean Temp
#Append
df_e = df_e.append({'Horário': i, 'Temperatura': media,'Potência': soma}, ignore_index=True)
return df_e
Y estoy obteniendo el siguiente error:
ValueError: could not convert string to float: ‘Potência’
Honestamente no veo problemas en mi columna Potencia, o probablemente sea problemas en los espacios vacíos que estoy rellenando.
Agradezco unos consejos, para saber que es lo que estoy entendiendo mal.
