Does the .co.uk registry (Nominet) have a 60 day waiting period for domain transfer?

Nominet.uk (the registry behind .co.uk) do not have any explicit terms on transfers of .co.uk domains, unless the domain is “expired” or “suspended” (from 30 days after expiry, lasts for 60 days). Domains in these statuses would need to be renewed prior to them being transferred.

From the .UK Registry-Registrar Agreement 26 May 2020, section B.1.15:

You may not transfer a domain name during the expiry period, except as set out in paragraph E.3.6

However, some registrars do seem to enforce a 60 day limit on transfers, for example GoDaddy’s rules on transferring out state:

You won’t be able to transfer your domain away if it’s within 60 days of registration or a previous transfer, if a 60-day lock was applied after updating domain contact information, or if your domain has Ownership Protection.

and:

Note Option showing disabled? You can’t transfer your domain if it’s within 60 days of registration or a previous transfer, if a 60-day lock was applied after updating domain contact information, or if your domain has Ownership Protection.

Fasthosts also state:

You can transfer .co.uk, .uk, .org.uk, .ltd.uk, .me.uk and .plc.uk domain names away from Fasthosts, provided that the domain name has been registered for at least 60 days.

Which seems to imply that you can transfer a domain within 60 days of another transfer, but not from the initial registration.

However, other registrars, such as namecheap will follow the registry guidelines and allow for immediate transfers.

europe – Is it cheaper to book Dutch train tickets online in advance compared to paying on the day?

I am going to the Netherlands and might need to get a train. (Between Eindhoven and Amsterdam). On www.ns.nl (the large train operator that does that route), they list the price as €17.90ish. That’s for booking it online.

However, I’m not sure what price it’d be if I were to turn up on the day and buy a ticket for the next train going that way.

Here in Ireland if you book train tickets online in advance, it’s much cheaper than if you arrive in the train station and want to buy a ticket for the next train. (e.g. €20 online vs. €60 last minute in some cases). Is this the same in the Netherlands with NS or is it the same price regardless of when you book?

Update I don’t care what sort of train to take, I just want to get from Eindhoven to Amsterdam.

Money isn’t too much of an issue, I just don’t want to be asked to pay €50 per ticket when I could have got it for <€20 had I only booked online!

Pi Network – Free Crypto with just one click per day

Hi,

I just found out about the Pi app that let’s you produce the Pi cryptocoin with just one tap everyday. If you invite more friends to your network, the amount you produce every hour increases.
SEMrush

This is the link that will send you to where you can download your app for Android or iOS:
https://minepi.com/Skaritza

This is my refferal name: Skaritza
I will appreciate if you will include my name in the registering process when it appears, that will help me and you can also do that with the ones you will invite with your own code.

Good luck!

 

java – Calculate Date by adding Month, Week of month and day of week

When the customer selects months, week of month and day of week, I have to calculate the date depending on customer inputs and deliver the product at that particular date. How can I achieve it using java.
For example if todays date is 2021-01-01, and customer need product to be delivered after 1 month on First week of Monday i.e on 01 February, 2021(2021-02-01). How can I calculate this date “2021-02-01” in java

Add date

KLM refused luggage return during 3 day delay

It is understandable that it is diffcult for them to sort the luggage out and give it to you, but according to the usual rules, they should be responsible for paying for your necessities, as well as the hotels and food, as the delay is their fault. It should be cheaper for them to get your luggage out than to pay for you buying new items, but they may have the choice in that (meaning they probably can choose to give you money instead).

Either way, they are responsible for your cost during the forced stay, and they are legally required to inform you about it. Contact them to get what they owe you, and file a complaint if they don’t want to.

Worst case you can buy some new wardrobe on their nickel, and have some paid vacation in the three days.

battery – Should I carry extra batteries in the field or bring a solar charging unit for a 30 day trek in Nepal?

If having a solar charger, you should note the limitations of law of energy conservation.

Sunshine at best produces 1000 watts / square meter. However, best single junction solar panels are around 20% efficient so you get out 200 watts / square meter. Add 95% efficient charger (you need DC-DC converter somewhere, you can’t just plug a raw solar cell into a raw battery) you get 190 watt-hours of charge per square meter per hour.

A 20 cm x 20 cm square solar panel thus provides 7.6 watt-hours of charge per hour. A Canon LP-E6NH battery is 15.762 watt-hours. To charge it at 95% battery charging efficiency (which is a different thing than DC-DC converter efficiency) you need 16.592 watt-hours of energy. Your 20 cm x 20 cm solar panel produces it in 2 hours 11 minutes. So, not even 2 hours is enough to charge the battery!

If you think a smaller solar cell let’s say 15 cm x 15 cm is enough, it needs 3 hours 53 minutes of charging.

To make matters worse, this requires the solar cell placed at an optimal angle towards the sun. Most likely, the sun is at 45 degree angle on the average and your cell at 90 degree angle (you lay it flat on the ground) so the charging time is multiplied by 1/sin(45*pi/180) or the square root of 2. So your 15 cm x 15 cm panel now charges the battery in about 5 and half hours. That’s nearly half of the average sunlight hours of 12 hours (of course some seasons have more and some seasons have less sunlight hours).

Is that fast enough for you? Most likely you won’t want to spend half of your sunlight hours staying standstill charging one camera battery!

Also note that as is well-known among photographers, clouds can reduce the exposure by 2 stops. This means energy is one fourth of what it is without clouds. So the 5 and half hours in cloudy weather is 22 hours. The trouble is, there’s no 22 sunlight hours in a single day.

So, if selecting a solar charger, please do make sure the panel is large enough that the charging time is acceptable. I would say 20 cm x 20 cm is minimum, and even then you can only reasonably use it during sunny hours unless you consider it acceptable a charge takes the whole day. Clouds? No way.

Because you need to consider that there can easily be 5 consecutive cloudy days, you most probably need not just the solar charger but also few spare batteries.

My solution for Advent of Code 2020, Day 4, in C

Here is my solution for Advent of Code 2020, Day 4, Part 1 in C. I tried using fscanf or fgets, but couldn’t find a nice of doing it, so I ended up using getc. Is there a way of using fscanf or fgets that makes this code better? Also, how does the code look in general?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct keyValuePair
{
    char key(4);
    char value(20);
} KeyValuePair;

typedef struct passport
{
    KeyValuePair fields(8);
    int numberOfFields;
} Passport;

int main()
{
    FILE* f = fopen("../input.txt", "r");
    if (f == NULL)
    {
        printf("Fail opening filen");
        return -1;
    }

    Passport passports(1000);
    int currentPassport = 0;
    int currentField = 0;

    char key(4);
    char value(20);

    int c;
    while (!feof(f))
    {
        c = getc(f);
        if (c == 'n')
        {
            ++currentPassport;
            currentField = 0;
            continue;
        }
        else
        {
            // read key
            key(0) = (char)c;
            key(1) = (char)getc(f);
            key(2) = (char)getc(f);
            key(3) = ''; // place null terminator at the end

            // discard ':'
            c = getc(f);

            // read value
            int index = 0;
            while (c != ' ' && c != 'n')
            {
                c = getc(f);
                if (c == EOF) { break; } // at the last line, instead of a new line we have EOF
                else if (c != ' ' && c != 'n') { value(index++) = (char)c; }
            }
            value(index) = '';  // place null terminator at the end

            strcpy(passports(currentPassport).fields(currentField).key, key);
            strcpy(passports(currentPassport).fields(currentField).value, value);
            ++currentField;

            ++passports(currentPassport).numberOfFields;
        }
    }

    int numberOfValidPassports = 0;
    for (int i = 0; i <= currentPassport; ++i)
    {
        if (passports(i).numberOfFields == 8) { ++numberOfValidPassports; }
        else if (passports(i).numberOfFields == 7)
        {
            int cidFound = 0;
            for (int j = 0; j < passports(i).numberOfFields; ++j)
            {
                if (strcmp(passports(i).fields(j).key, "cid") == 0)
                {
                    // passport contains cid and has 7 fields, therefore invalid
                    cidFound = 1;
                    break;
                }
            }
            if (!cidFound) { ++numberOfValidPassports; }
        }
    }

    printf("Number of valid passports: %d", numberOfValidPassports);

    fclose(f);
    return 0;
}

Easiest method for 100$+ per day

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Event recurs day before 2nd Sunday?

Our church has Communion on 2nd & 4th Sunday of every month. Using Google Calendar, we need an appointment for the Saturday before to prepare things.