equipment protection – Are microwave ovens dangerous for digital cameras?

No, there is no danger. All EM fields on the outside the microwaves are very weak. There is no danger or risk.

Microwaves look like visible light waves, with the exception of the larger ones (the "micro" is in comparison with other radio waves). Both are non-ionizing radiation; they do not have the energy needed to move the electrons in the atoms. And, just like visible light, microwave radiation follows the law of inverse squares and decreases dramatically as you move away from it.

Microwaves use exactly the same radio waves as Wi-Fi, except with higher power and concentration. However, the microwave box keeps this confined. In the United States, federal regulations limit microwave leakage to 5 milliwatts per square centimeter to 5 centimeters from the box for microwave leakage throughout the life of the device (ie not only if they are new). For comparison, the FCC limits WiFi routers to 1,000 mW (or, you know, one watt). And you should not worry either.

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How is it monetized?

It has not been monetized yet. It is possible to start earning money by requesting a post paid publication, there have already been many requests for this (currently, free of charge, because of DR 11)

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Yes, twitter with 712 subscribers.
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Digital Marketing, SEO and Web Lab

Digital integration of the damped wave equation

I'm trying to solve the equation

$$ frac {d ^ 2u} {dt ^ 2} – frac {d ^ 2} {dx ^ 2} left (c_s ^ 2u + nu frac {of} {dt} right) = 0 $ $

with initial conditions

$$ u (x, 0) = 0 $$

$$ frac {du} {dt} | _ {t = 0} = 0 $$

and boundary conditions

$$ frac {d ^ 2u} {dt ^ 2} – frac {d ^ 2} {dx ^ 2} left (c_s ^ 2u + nu frac {of} {dt} right) = 0 $ $

My code is

ClearAll((ScriptC), (Nu), (Rho), (ScriptL), (ScriptN), (Kappa), (Omega), (ScriptCapitalV), A, u, v);

(ScriptC) = 1489; 
(Nu) = 1.004;
(Rho) = 998.21;
(ScriptL) = 2*10^-2;
(ScriptN) = 8; 
(Kappa) = 2*Pi*(ScriptN)/(ScriptL);
(Omega) = (ScriptC)*(Kappa);
(ScriptCapitalV) = (Omega)*10^-8;

A = ((Rho)*(Omega)*(ScriptCapitalV)/((ScriptC)^4+(Nu)^4*(Omega)^2));

(Tau) = 10^-9;
f(t_) := (1-Exp(-t/(Tau)));
(*f(t_) := If(t < 10^-9, 0, 1);*)
pde = {D(v(t, x), t) - ((ScriptC)^2)*D(u(t, x), x, x) - (Nu)*D(v(t, x), x, x) == 0, 
   v(t, x) == D(u(t, x), t)};
ics = {u(0, x) == 0, v(0, x) == 0};
bcs = {(D(u(t, x), x) /. x -> 0) == A*(((ScriptC)^2)*Sin((Omega)*t) - ((Nu)*(Omega))*Cos((Omega)*t)) f(t),
       (D(u(t, x), x) /. x -> 1) == A*(((ScriptC)^2)*Sin((Omega)*t) - ((Nu)*(Omega))*Cos((Omega)*t)) f(t)};
bcs1 = {(D(v(t, x), x) /. x -> 0) == (Omega)*A*(((ScriptC)^2)*Cos((Omega)*t) + ((Nu)*(Omega))*Sin((Omega)*t)) f(t),
        (D(v(t, x), x) /. x -> 1) == (Omega)*A*(((ScriptC)^2)*Cos((Omega)*t) + ((Nu)*(Omega))*Sin((Omega)*t)) f(t)};

{U, V} = NDSolveValue({pde, ics, bcs, bcs1}, {u, v}, {x, 0, (ScriptL)}, {t, 0,1},
Method -> {"IndexReduction" -> Automatic, "EquationSimplification" -> "Residual", "PDEDiscretization" -> {"MethodOfLines", "SpatialDiscretization" -> {"TensorProductGrid", "MinPoints" -> 500, "MaxPoints" -> 500,"DifferenceOrder" -> 2}}});

{DensityPlot(U(t, x), {x, 0, 1}, {t, 0, 10}, ColorFunction -> "Rainbow", PlotLegends -> Automatic, FrameLabel -> Automatic, PlotLabel -> "u"), 
 DensityPlot(V(t, x), {x, 0, 1}, {t, 0, 10}, ColorFunction -> "Rainbow", PlotLegends -> Automatic, FrameLabel -> Automatic, PlotLabel -> "v")}

Manipulate(Plot(U(t, x), {x, 0, 1}), {t, 0, 10})

where I had to multiply at boundary conditions a sigmoid function, otherwise these are inconsistent with the initial conditions. A step function does not work well because it makes the system rigid (or singular).

With the code above, I always get the following errors and I do not know how to get rid of it:

NDSolveValue :: nderr: failure of the error test at t == 0.`; unable to continue.

InterpolatingFunction :: dmval: The input value {0.000714286.0.0000714286} is outside the data range of the interpolation function. The extrapolation will be used.

Note: This is the continuation of my previous question Solving an attenuated wave equation. I am now trying to use parameter values ​​with physical meaning.

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Restoration Suite 2 – a giant step in audio quality. Restoration Suite 2 is a suite of four advanced plug-ins for audio restoration and noise reduction.

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DeClip 2 restores distorted audio recordings by analog or digital clipping with an improved algorithm.
Required configuration:
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A host application compatible with VST, VST3 (32-bit or 64-bit) or AAX (Pro Tools 11 or higher)
Intel Core i3 or AMD multicore processor (Intel Core i5 or higher recommended)
Display resolution of 1366 x 768 (1920 x 1080 or higher recommended)
1 GB of RAM (4 GB or more recommended)
1 GB of free disk space
Home page

Recommend the download link | Please tell me Thank you Keep the topic live

What combination of digital printer / ink / paper provides the highest DMAX currently available for a reasonably archival print?

Having recently read claims that dye transfer prints would approach DMAX 3.0, I am curious to know what is the state of the art of inkjet in this regard

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Digital – Abs[]^ 2, conjugate[], ComplexExpand[]and simplify

I think it's a digital problem, but I'd like to see where it's happening. I create a complex rational polynomial as follows and put it according to f

 bf = ButterworthFilterModel({"Lowpass", 2, 2 (Pi) 500.});
  a = bf(I 2 (Pi) f)((1, 1))

(*
 9.8696*10^6/(((2221.44 - 2221.44 I) + 
   2 I f (Pi)) ((2221.44 + 2221.44 I) + 2 I f (Pi)))
*)

Now I use two methods to calculate the square module.

b1 = ComplexExpand(Re(a Conjugate(a))) // Simplify
b2 = ComplexExpand(Abs(a)^2) // Simplify

Why do I have two different answers?

(*

(0. + 0. I) + 3.90625*10^21/(6.25*10^10 + 1. f^4)^2 - (
 3.58535 f^2)/(6.25*10^10 + 1. f^4)^2 + (
 6.25*10^10 f^4)/(6.25*10^10 + 1. f^4)^2

(0. + 0. I) + 6.25*10^10/(6.25*10^10 + 1. f^4)
*)

I think it has to do with digital because if I repeat with exact numbers

bf = ButterworthFilterModel({"Lowpass", 2, 2 (Pi) 500});
a = bf(I 2 (Pi) f)((1, 1));
b1 = ComplexExpand(Re(a Conjugate(a))) // Simplify
b2 = ComplexExpand(Abs(a)^2) // Simplify

I get two identical results.

(* 
62500000000/(62500000000 + f^4)

62500000000/(62500000000 + f^4)
*)

The problem is that I can not necessarily work with exact numbers. So, why do I have different answers? The problem is it in ComplexExpand or Simplify? Is there a preferential approach (I note that Abs()^2 gives simpler answers)? Thank you

Focus on analog and digital cameras

Why is a subject that is not clear in the viewfinder of an analog camera perceived as two half-circles misaligned, while that of a digital camera is uniformly blurred?

Transactions – Where can I get a good overview of the technical differences between different digital currencies?

There are many digital / encrypted currencies, and probably new ones appear from time to time. I just started out on the field, finding it interesting only by technological curiosity. However, I quickly reached a threshold where most of the information I find is either:

  • to project investments in cryptocurrency, or
  • giving a very popular scientific introduction of concepts such as blockchain to the masses, which do not tell me anything new

I am mainly looking for articles / books / other resources which dive deeper into the technical differences between the main crypto-currencies, in terms of security and implementation. Are there any good resources on can read about?

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