StrongSwan – double password Windows

I needed to use a single virtual IP pool per peer config (identity). Clients would connect with the help of a default Windows VPN client and each connected client should get the virtual IP address of a different pool. Multiple clients can use the same credentials to obtain a virtual IP address from the pool configured with the peer configuration. However, customers using different credentials will get the IP of different virtual pools.

For windows, matching identity-based (connections) between peers does not work, so I followed the indicated approach on the link below (see the answer)

Strongswan Customer Access Rights

Although the solution works well, but the challenge is that the use of right groups The configuration causes an additional password prompt on Windows (using the default VPN client). I think this happens because of the dummy connection switch that occurs due to the right handed with identity =% none (eap-init).

Is there a way to solve the problem of double password prompt?

forms – Study on password Double entry by registration

I do not think you need to refer to studies / articles for that. Repetition during registration is used to avoid errors when setting the password. A simple typo may cause the user to reset his password but

Would the user really know why the password is incorrect?

A typo, by nature, is an error that is overlooked. This is why entering the password twice eliminates such errors. In addition, "forgotten password" is used to help the user when he "forgets" the password. Nobody likes to follow this feed, especially if they just created their account.

Passwort Double Entry Studies by Registration

Are there any usability / UX studies and recent conversions on how double-entry passwords when registering a user account in an online store slows down the conversion rate ?
We try to get rid of the password entry twice. There is still a flow of "forgotten password".

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c – How can I fix this error when I try to delete a specific node from a double chained list?

In my project, I create a double padlock list in C, in which it has simple goals, like adding at the beginning or end, delete a specific item or set to zero.

I had a shallow code and I added the modules I needed, using the code blocks.

Dai in the addition of the option to delete the specific item, began to appear errors that could no longer solve.

#include 
#include 

struct Bank {
int numero_conta;
char client_name[30];
float balance;
struct * Bank back;
struct * Bank now;
struct Bank * prox;
struct Bank * ant;
};
typedef struct Bank Node;

void starts (node ​​* LIST);
int menu (void);
void option (node ​​* LIST, int op);
node * createNo ();
void insertFim (node ​​* LIST);
void insertInitial (node ​​* LIST);
empty displays (node ​​* LIST);
void libes (node ​​* LIST);
void delete (node ​​* LIST);


int main (void)
{
node * LIST = (node ​​*) malloc (sizeof (node));
if (! LIST) {
printf ("More memory!  n");
output (1);
}
begins (LIST);
int opt;

make {
opt = menu ();
option (LIST, opt);
} as long as (opt);

free (list);
returns 0;
}

void starts (node ​​* LIST)
{
LIST-> prox = NULL;
}

int menu (void)
{
int opt;

printf ("Choose the option  n");
printf ("0 output  n");
printf ("1. See the list  n");
printf ("Add a client at startup  n");
printf ("3. Add a client at the end  n");
printf ("4. Zero List  n");
printf ("5. Exclude a specific client  n");
printf ("Option:"); scanf ("% d", & opt);

return opt;
}

Void option (node ​​* LIST, int op)
{
switch (op) {
case 0:
discards (LIST);
pause

case 1:
displays (LIST);
pause

case 2:
InsertStart (LIST);
pause

case 3:
insertFin (LIST);
pause

case 4:
begins (LIST);
pause


default:
printf ("Invalid command  n  n");
}
}

int empty (node ​​* LIST)
{
if (LIST-> prox == NULL)
returns 1;
d & # 39; other
returns 0;
}


void insertFim (node ​​* LIST)
{
node * new = (node ​​*) malloc (sizeof (node));
if (!) {
printf ("More memory!  n");
output (1);
}
// start the teacher's edition
printf ("Account number:"); scanf ("% d", & new-> account_number);
printf ("Name:"); scanf ("% s", new-> clientname);
printf ("Balance:"); scanf ("% f", & new-> balance);
new-> prox = NULL;
// End of the teacher's edition

if (empty (LIST))
LIST-> prox = new;
if not {
node * tmp = LIST-> prox;

while (tmp-> prox! = NULL)
tmp = tmp-> prox;

tmp-> prox = new;
}
}

void insertInitial (node ​​* LIST)
{
node * new = (node ​​*) malloc (sizeof (node));
if (!) {
printf ("More memory!  n");
output (1);
}
printf ("Account number:"); scanf ("% d", & new-> account_number);
printf ("Name:"); scanf ("% s", new-> clientname);
printf ("Balance:"); scanf ("% f", & new-> balance);

node * oldHead = LIST-> prox;

LIST-> prox = new;
new-> prox = oldHead;
}

empty displays (node ​​* LIST)
{
if (empty (LIST)) {
printf ("Empty List!  n  n");
return
}

node * tmp;
tmp = LIST-> prox;
// Edit the teacher ("% d% s% f  n", tmp-> account_number, tmp-> client_name, tmp-> balance)
while (tmp! = NULL) {
printf (" n");
printf ("Account number:% d  n", tmp-> account_number);
printf ("Name:% s  n", tmp-> clientname);
printf ("Balance:% f  n", tmp-> balance);
printf (" n");
tmp = tmp-> prox;
}
printf (" n  n");
}

void libes (node ​​* LIST)
{
if (! empty (LIST)) {
node * proxNode,
* current;

current = LIST-> prox;
while (current! = NULL) {
proxNode = current-> prox;
free (current);
current = proxNode;
}
}
}

The first mistake is when I add the:

case 5:
delete (LIST);
pause

undefined reference to `delete & # 39;

I've seen a lot of tutorials, but none have made me useful, unfortunately.

Could someone help me?
How would it add a specific client Delete the system in my code?

python 3.x – How to put list values ​​with single and double quotation marks to the Postgressql selection query

I execute the selection query in the postgresql database and, after retrieving these results, I add them to the list, and then I give this list as input to another postgresql selection query.
But because of the conversion of these values ​​into a list, it converts the values ​​with apostrophe (special character) cats double quotation marks "Cats". when running the second selection query, the value with the double quotation marks is not extracted because the value with the double quotation marks is not present in the database, it is without quotation marks cats.
And there, it gives me the error that this value is not present.

I tried the JSOn dumps method but it does not work because I can not convert a JSON list to tuple and give it as input a postgresql selection query

select_query = "" "select" Unique_Shelf_Names "from" unique_shelf "where category =" Accessory & # 39; " ""
cur.execute (select_query)
count = cur.fetchall ()

query_list = []
for co account:
for c in co:
query_list.append (c)

query_list output: –

query_list = ['parrot', 'dog', "leopard's", 'cat', "zebra's"]

Now this query list is converted to tuple and given as input to another selection query

list2 = tuple (query_list)

query = "" "selects the category" unique_shelf "where" Unique_Shelf_Names "in {}" "" .format (list2)

cur.execute (request)

It's there that it gives me the error "the leopard" does not exist but in the database the leopard exists

I want all query_list values ​​to be double quotation marks so that this error does not occur.

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How to make a double query in the same MySql table?

Below, I explain what I do and what I need, I now leave a statement of the goal table and the query I am using.

Target table (line_count_fact):

product_id | unds | achat_sales
10517931 | 2 | Purchase
10517929 | 4 | Sale
10517929 | 2 | Sale
10517939 | 6 | Purchase
10517931 | 3 | Sale 

This is my request:

SELECT
fact_line_contability.product_id,
SUM (fact_contabilidad_lineas.unds) as unds,
fact_contabilidad.compra_venta

DE fact_contabilidad, fact_contabilidad_lineas

WHERE fact_line_contability.series = concat_ws (& # 39; - & # 39 ;, fact_contabilidad.id_serie, fact_contabilidad.serie_num)
AND fact_line_contability.iduser = 98
AND fact_contability.iduser = 98
AND fact_contabilidad.compra_venta = & # 39; Venta & # 39;
AND fact_line_contractability.product_id> 10517927

GROUP BY fact_line_contability.product_id

Result:

product_id | unds | achat_sales
10517929 | 6 | Sale
10517931 | 3 | Sale 

I have not shown the table (fact_contabilidad) because it is not necessary, it does not influence my question and in this way, the question is a little cleaner. The query works well, but it only removes the lines compra_venta = Venta.

What I need to go out is:

1 column sum of products grouped by product_id and compra_venta = Sale.

1 column sum of products grouped by product_id and compra_venta = Purchase.

Expected result:

product_id | Sale | Purchase
10517929 | 6 | 6
10517931 | 3 | 2

Can you guide me? I can not think of how to do it.

c ++ – Converting the Single Reading List to a Double Link List Using Class Inheritance

I managed to create the unique linked list using the class node:

        class node {protected:
int info;
the length;
next node *;
knot * head;

(In public I have work duties). And the other class double_node:

double_node class: public node {
node * prev;

My problem here is using the add function in the double_node class, where I have two problems (modified at least 10 times but I'll post the one with all the errors I've had because I'm not sure that the other versions have corrected these errors.):

void add (int x) {
double_node * p = new double_node (x); // constructor makes next = NULL & info = x
if (head == NULL)
{
p-> prev = NULL;
head = p;
}
other
{
double_node * q = head; // # 1st number, no idea how to initialize a pointer with head
while (q-> next! = NULL)
{
q = q-> next; // # 2nd number
}
q-> following = p;
p-> prev = q;
}
}

The two errors are: invalid conversion of & # 39; node & quot; in & # 39; double_node * & # 39; [-fpermissive].

Any ideas to solve this problem? Thanks in advance!

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