linux – virt-install crashes, no apparent error in the logs, and the virsh list shows its execution after the ctrl c output, no domifaddr if

I was thrown into a management box that virtually the person before me was using virtually, so trying to upgrade. As a test, make a virtual installation of this:

virt-install --virt-type = kvm --name kosmos-icc --ram 1000 --os-variant = centos7.0 --cdrom = / var / lib / libvirt / boot / CentOS-7-x86_64-Minimal- 1810.iso --network = bridge = virbr0, model = virtio --graphics vnc - disk path = / var / lib / libvirt / images / centos7.qcow2, size = 8, bus = virtio, format = qcow2 --boot userserial = on

It works with this:

WARNING Charts requested but DISPLAY is not set. Do not run virt-viewer.
WARNING No console to launch for the guest, default --wait -1

Start the installation ...
Allocation of & centos7.qcow2 & # 39; | 8.0 GB 00:00:00
The installation of the domain is still in progress. Waiting for the end of the installation.

Then I block, I can press ctrl-c and get my prompt, make a list virsh shows that it is running, but do a virsh domifaddr kosmos-icc shows nothing (the other that is generic and which was installed with the mistletoe) shows the IP address (which I can ssh in) of the machine.

So, I do not know why it does not finish or if it is silent and if I miss a switch. I assumed virbr0 was the way to go with the network. So we must continue to learn virsh / virt and see if I can via a command line install a virtual machine and then replicate the process on an untested machine.

The installation logs in /root/.cache/virt-manager do not show any real errors … in fact, they indicate:

[Wed, 19 Jun 2019 11:28:38 virt-install 351]    DEBUG (guest: 441) XML retrieved from the libvirt object:

... the xml ...


[Wed, 19 Jun 2019 11:28:38 virt-install 351] DEBUG (virt-install: 744) State of the domain after installation: 1

This state after installation is the last line before the log shows the interruption of my ctrl-c keyboard.

Visual Studio – How to Fix the Error Downloading Images Using VisualBasic ASP.NET and Access

When you click Send in Database, the system returns the following error:

System.IndexOutOfRangeException: OleDbParameterCollection does not contain OleDbParameter with ParameterName & # 39; @image & # 39;. & # 39;

Here are the codes:

Protected Sub test_Inserting (sender as object and as SqlDataSourceCommandEventArgs) handles test.Inserting
Dim fu As FileUpload
fu = FormView1.FindControl ("fileupload1")
e.Command.Parameters ("@ image"). DbType = DbType.Binary
e.Command.Parameters ("@ image"). Value = fu.FileBytes ()
End Sub

Shipping screen:

insert the description of the image here

Banking modeling:

insert the description of the image here

Environment: Visual Studio 2019, Visual Basic, Access

network – Resetting an iPhone with the error "No Service & # 39;

A few days ago, my iPhone 7 began to display the "No Service" error in the upper left corner of the screen. I've tried several ways to solve this problem, but nothing is done there. When trying to reset it, I received the error message:


Title: iPhone requires service

body: You will not be able to configure this iPhone after erasing. A cellular update is necessary before it can be reactivated.


What does it mean? Is it safe to proceed?

Turing machines – If NP were closed under complement, then what would be the consequences for the error in terms of randomization algorithms?

I thought maybe we could run a random algorithm on the A problem, and then run a different algorithm on the A add-in.

Would it reduce the term of error anyway depending on the output of each? Since A and A do not intersect

settings.php – Get the PHP extension "gd" and the error disabled database support during the installation of Drupal 8

I'm trying to install Drupal 8.7.3 on my Windows machine via Xampp (PHP 7.3.6). But I receive the following errors:

Please see the screen capture:
https://snag.gy/06sMEa.jpg

I tried to do the following but I could not solve it:

1- I've copied php.ini to the root of my drupal folder and made sure the extensions are enabled. and I made sure that the default php.ini has the same extensions enabled.
Please see the screenshot: https://snag.gy/nN8BGA.jpg

2- I have also downloaded the php_gd2.dll and php_gd.dll files and have them also placed in the / ext folder. please see the screenshot: https://snag.gy/RHqrlI.jpg

My problem remains the same. Can you help me solve this problem.

Here is my result phpinfo () on the extensions:
https://snag.gy/ifsIjo.jpg

See also the path of the extension:
https://snag.gy/Jlcw01.jpg

sql server – Extended event file of system integrity corrupted with error Not a valid Win32 FileTime file

We are collecting data for monitoring extended system health events and few SQL servers have started to fail with the error below.

The conversion failed when converting the date and / or time of a character string. [SQLSTATE 22007] (Error 241).  

When checked manually from SSMS, I can not open the package.0.event file to view the target data with the error below.

Not a valid Win32 FileTime. Parameter name: fileTime (mscorlib)

—————————— Program location:

to System.DateTime.FromFileTimeUtc (Int64 fileTime) to
Microsoft.SqlServer.XEvent.Linq.Internal.XEventInteropMetadataManager.MarshalEvent (XEEventBufferHeader *
data, XEEvent * eventType,
XE_ISerializedEvent *
parser, XEventInteropMetadataAdapter * pMetadata,
XEventInteropMetadataManager interopMetadata, EventLocator position)
at
Microsoft.SqlServer.XEvent.Linq.Internal.XEventInteropBufferProcessor.get_Current ()
at
Microsoft.SqlServer.XEvent.Linq.Internal.XEventEnumerator.MoveNext ()
on Microsoft.SqlServer.XEventStorage.XEStorage.SerializeData ()

What is the cause above and how can I solve this problem.

Note @ problem so far, I've seen on SQL2012 SP3 and nothing about 2014 and above

android studio – Error in SQL Server INSERT

Buenas tardes tengo a problema with the estructura that supports INSERT in SQL Server ya que me marca el siguiente error.
The conexión if the está haciendo well.

Metodo INSERT

public int registrar () {
        int ideVenta = 0;
        Statement st = null;
        ResultSet rs = null;
        Conexion conn = new Conexion ();

        try {
            if (conn.conexionDB () == null) {
                Log.d ("--------------------- ACCESO", "Access Error");
            } else {
                DateFormat dateFormat = new SimpleDateFormat ("yyyy / MM / dd");
                Date date = new Date ();
                String fecha = dateFormat.format (date);

                String query = "INSERT INTO Ventas values ​​(0, 4011, '" + fecha + "', NULL, NULL, 'Abierta', 'Mayoreo', 0,80.00, 'Super Administrator', NULL, NULL, NULL)";
                st = conn.conexionDB (). createStatement ();
                rs = st.executeQuery (query);

// rs = st.getGeneratedKeys ();
// ideVenta = rs.getInt (1);

                st.close ();
                rs.close ();
// conn.close ();

            }
        } catch (SQLException e) {
            System.out.println ("Error: ClienteDaoImple, metodo registrar");
            e.printStackTrace ();
            ideVenta = 0;
        }
        return ideVenta;
    }

Error that manda

D / --------------------------------- CONEXION: Muy bien
I / System.out: Error: ClaseDaoImpleClient, metodo registrar
W / System.err: java.sql.SQLException: The executeQuery method must return a result set.
W / System.err: at net.sourceforge.jtds.jdbc.JtdsStatement.executeSQLQuery (JtdsStatement.java:516)
        at net.sourceforge.jtds.jdbc.JtdsStatement.executeQuery (JtdsStatement.java:1427)
        at com.example.pegasso.DAO.VentasDaoImpl.registrar (VentasDaoImpl.java:40)

How to debug an error during an APK installation error

I work in a project. We are in a test cycle and we have an experience that I do not know how to debug.

I've built the apk. I installed it in my phone (s9 +) and in many others without problem. Then we send the apk to some people to test it. 4 new Samsung S9s. Totally new. No previous version installed and even SDK and ONEUI and security patch of my own device.

When they try to install it, they get an error during the installation. I do not know what can cause this and I do not know how to know the error. How to generate a log or debug it.

Help me! Thank you

String error in java

I have a problem with a simple program in Java.
When I run and scan with String, it just goes to the end of the program, but when I put a tank, it does not run and runs normally, anyway I wanted to run with strings and not with charactersAn image of what is happening.
Here is the code:

public static void main (String[] args) {
// ALL the logic of applying the code here
Scanner in = new Scanner (System.in);

                Chain resp;
int op;

make {
System.out.println ("//////////////////////// BANK ////////////////// //////////// /////// ");
System.out.println ("What do you want?" +
" not[1]To create a new account "+
" not[2]To go out. ");
op = in.nextInt ();

switch (op) {
case 1:
System.out.println ("Do you want to create a new account? [s/n]");
resp = in.nextLine ();
if (resp.equals ("s")) {
Account c1 = new account ();
System.out.println (" n ---------------------------------------") ;
System.out.println ("Account Type:");
c1.abrirConta (in.nextLine ());

System.out.println (" n[1]To file, "+
" not[2]To go out; "+
" not[3]To pay monthly fees; "+
" not[4]To close the account "+
" not[5]To go out. ");
int op2 = in.nextInt ();

switch (op2) {
case 1:
System.out.println ("How much do you want to deposit?");
c1.deposit (in.nextFloat ());

pause
case 2:
System.out.println ("How much do you want to draw?");
c1.sacar (in.nextFloat ());
pause
case 3:
System.out.println ("Do you want to pay monthly fees? [s/n]");
String resp2 = in.nextLine ();
if (resp2.equals ("s")) {
c1.pagarMensal ();
} else if (resp2.equals ("n")) {
pause;}
pause
case 4:
System.out.println ("Do you want to close this account? [s/n]");
String resp3 = in.nextLine ();
if (resp3.equals ("s")) {
c1.CloseContact ();
} else if (resp3.equals ("n")) {pause;}
pause
case 5:
System.out.println ("Do you want to exit? [s/n]");
String resp4 = in.nextLine ();
if (resp4.equals ("s")) {
pause
} else if (resp4.equals ("n")) {
}
pause
}
}
pause
case 2:
System.out.println ("Do you want to exit? [s/n]");
String resp5 = in.nextLine ();
if (resp5.equals ("s")) {
pause
} else if (resp5.equals ("n")) {

}
}
} while (op == 2);
}

}

sharepoint online – Workflow startup via JS generates error "Value can not be null"

Hi, I'm trying to start an SP 2010 workflow with the help of Jquery SP Services, but it seems like I'm getting an answer. 500 The value can not be null. There is not supposed to be an initiation form when I manually start the workflow via a link. I get an Infopath form with just the Start Cancel buttons because I have no parameters. Can any one detect a problem?

    $ (). SPServices ({
operation: "StartWorkflow",
element: "https://mytenant.sharepoint.com" + fileRef,
templateId: "{463231b0-e608-44e1-ae9f-57af1832565d}",
workflowParameters: ""
});