windows 10 – Blocking standard users (Win 10) from adding Chrome extensions

Use Group Policy. This is supported by chrome.

It's pretty well documented how to do that:

Allows you to specify extensions that users can NOT install. Extensions already installed will be disabled if they are blacklisted, without the user being able to activate them. Once an extension disabled due to the blacklist is removed, it will be automatically reactivated.

A value of & # 39; * & # 39; Blacklist means that all extensions are blacklisted unless they are explicitly listed in the whitelist.

You can define other settings, such as whitelisting or forcing specific extensions. Do not try to create your own schema using custom permissions on parts of the Chrome user profile directory.

url – how do i get html extensions

I am new to web development, I have a question, thanks to all for your answers.

I've created a website with HTML5 and CSS, I've published my website on my host using FTP (FileZilla Client), but when I open my pages, I mean when I'm 39; opens the About page or the homepage of my website, the URL is as follows:
www.mywebsite.com/index.html
www.mywebsite.com/about.html

Now I want to remove the html extensions from all the pages of my website.
What are the simple methods and the solution?

Thank you all!

.

Browser.runtime.onMessage.addListener / sendMessage error of Firefox extensions

A simple Firefox background extension script generates an error:

// test-bg.js
function test_callback (... args) {
console.log ("test_callback () args =", JSON.stringify (args));
}
async function test () {
browser.runtime.onMessage.addListener (test_callback);
var a = browser.runtime.onMessage.hasListener (test_callback);
console.log ("a =", a);
browser.runtime.sendMessage ("test of test_callback");
}
test();

The output of the console with an error is:

The Webconsole context has changed
a = true
Error: Can not connect. The end of reception does not exist. 

the manifest.json the file is:

{
"manifest_version": 2,
"name": "scoped-poller",
"Permissions": [
    ],
"version": "1.2.0",
"Background": {
"Scripts":[ "test-bg.js"]
    }
}

The DND documentation is here and here; it seems like it should work. (I could swear it worked yesterday).

My questions are:

  1. Is there something wrong with the code?
  2. I although I ran yesterday and it succeeded without error – to be honest, I doubt my thinking. I have tried various versions of Firefox (using separate profiles, etc.) to see if it was a version problem, but that does not seem to be the case. So I wonder if the Web API can be dynamically downloaded to apply the same behavior, regardless of the version of FF. It seems unlikely, but I still ask.

php – Crypto CPU Extensions for Server Tenants

How to use the encryption extensions (hardware acceleration) provided by the Intel / AMD processors in PHP? Maybe the underlying C code uses them when they are available automatically? As far as I know, there is no information about it on the Internet, and the only code snippets I could find were written in C.

privacy – If I create a program to monitor users using Chrome APIs, will it be displayed when users access chrome: // extensions?

You can answer most of your questions by reading the Chrome developer pages quickly.

  • "Extensions are small software that personalize the browsing experience." [1]
  • "Chrome API" refers to the APIs used to create a Chrome extension (in addition to those available directly for web pages). [2]
  • "By default, extensions do not work in incognito windows." [3]

Since the NPAPI plug-ins are no longer supported, there is no other type of "program" that you can use to modify Google Chrome, apart from distributing a modified version of Chromium.

Extensions must always be hosted on the Chrome Web Store, as loading from other sources has been disabled for security reasons.

The only exception seems to be the configuration for enterprise deployments on Windows, which allows for the installation, activation, and forced configuration of extensions. Such extensions will always be visible users, but can not be deleted or disabled without removing the domain or registry setting that installed them.

If the computer is associated with an Active Directory domain, it may be that the extension is not found on the Chrome Web Store, assuming that a managed PC in such an environment is already under the Full control of the network administrator and not the local user.

seo – Should I include file extensions in canonical links?

I sent a page to the Google search console and I received an error message "Duplicate without canonical selected by the user".

The full URL is https://vidalingua.com/french-english-translator-iphone-ipad.html but I want it to appear without the file extension in Google search results.

I have therefore included the canonical link in the tab below.

https://vidalingua.com/french-english-translator-iphone-ipad ">

I've seen several articles, especially in a blog on Moz, that showed canonical links without file extension.

So, should I include the file extension in the canonical link?

How can I tell Google that I do not want the .html to be displayed in Google search results?


Google has selected a URL with no file extension for another of my pages. So it seems the answer to my question is no.

However, in the new canonical URL chosen by Google, they added "www." before the URL. I do not include "www." in my URLs and I do not want Google to display "www." in the result of the search.

I thought that the purpose of canonical links was to tell Google the URL you used to access a page and display it in the search results. What is the point if Google assigns canonical URLs different from those you provide?

Parameterization of vector bundle extensions

assume $ M $ is a bundle of lines on a smooth projective curve $ C $ and $ N $ is a vector packet on $ C $. Suppose the degree of $ M $ is big enough for $ Hom (M, N) = $ 0 and $ Ext ^ 1 (N, M) = $ 0. assume $ x $ is a point of $ C $. Question: what are the vector packets $ X $ parameterized by, such that there is a short exact sequence $ 0 to M oplus N to X to O_x to $ 0, and $ X $ has the form $ M_1 oplus N $ or $ M_1 $ is a beam of lines of greater degree of $ 1 $ that the degree of $ M $? Are they set by $ Ext ^ 1 (O_x, M) $ or by something else?

Programming languages ​​- Can the H standard (without extensions) create a quine?

I am referring to the H standard that I copied on my user page; the official website has unclear documentation.

I have worked on Quine programs in H, and these programs have been implemented in an H extension very close to the H standard:

(From my user page)

def n = "def n = %%; print (n% n);"; print (n% n);

The new operator is x% y, which means replacing all occurrences of %% in the string x to the string y.

Here is another quine via the addition [], the operator for grouping long strings.

def x =["def x=["+x+"]; print ("+ x);]; print ("def x =["+x+"]; print ("+ x);

Here is another quine that adds almost nothing to H (note that the numbers here represent the ASCII value):

def = print (100 + 101 + 102 + 32 + 115 + 61 + 34 + s + 34 + 59 + s) "; "print (100 + 101 + 102 + 32 + 115 + 61 + 34 + s + 34 + 59 + s);

It is unclear, however, whether the H standard (without extension) can implement a Quine program.

Firefox marks all extensions as unsafe due to expiration of intermediate certifications

This is probably temporary because they have already applied a new certificate.

abstract algebra – Intersection of a Galois finite extension with simple extensions

$ f $ is an irreducible polynomial in $ mathbb Q[x]$, $ Q subset E $ is a finished extension of Glaois. $ alpha, beta $ are roots of $ f $. Show that if $ E $ is the $ n $the cyclotomic domain then $ mathbb Q ( alpha) cap E = mathbb Q ( beta) cap E $.

First of all, note that $ alpha in E $ Yes Yes $ beta in E $ because Galois extensions are normal. Then we can assume $ alpha $ and $ beta $ are both in $ E $. If I can show that, given $ sigma in Aut _ { mathbb Q ( beta)} (E) $, $ sigma $ must repair $ alpha $, so I can show that they are equal by Galois's correspondence, but it's not obvious.