reverse engineering – Is it possible to automatically extract the secret key into the compiled code?

If we have a program containing a secret key in its compiled code, is it possible to write a program that can automatically extract the secret key? Suppose the program containing a secret key is not hidden and the secret key is used to decrypt some messages. We can know that the extracted key is correct if we can use it to decrypt messages.

php – extract information from a Laravel form

Good friends,

I am new to Laravel and would like to know if you could help me in this situation.

I have a form created at laravel and I would like to know if it is possible after clicking on the "submit" button, it sends the email as it sends it, s & # 39; it can create a .txt file or more with the data already written in the form fields.

      @if (session (& # 39; step3 & # 39;)['pagamento-mensal'])
@if (session (& # 39; step3 & # 39;)['pagamento-pontual'])
Customer code {{session (& # 39; step2 & # 39;)['cliente'] }}
Name {{session (& # 39; step2 & # 39;)['nome'] }}
NIF {{session (& # 39; step2 & # 39;)['contribuinte'] }}
Phone {{session (& # 39; step2 & # 39;)['telefone'] }}
Related categories {{session (& # 39; step2 & # 39;)['email'] }}
Monthly value {{session (& # 39; step3 & # 39;)['pagamento-mensal'] }} €
Point value {{session (& # 39; step3 & # 39;)['pagamento-pontual'] }} €
Name of the fund {{explode (- #, session (# step3)['fundo'])[1] }}
IBAN PT50 {{session (& # 39; step3 & # 39;)['iban'] }}
Périocité {{(session (& # 39; step3 & # 39;)['pagamento-mensal'])? & # 39; MONTHLY: & # 39; POINT & # 39;}}
Start date {{session (& # 39; step3 & # 39;)['inicio'] }}

Thank you all.

if the potential function of the binary heap is of size c * (binary heap)), then insert will not take O (logn) and extract min will not take O (1) damped time

So, I want to prove that if I choose a potential function for the binary heap as any size * constant of the binary heap (n), my insert will not have the cost depreciated by O (logn) and will extract Max n + 39. will not have amortized cost.

So to insert:

amortized cost of the operation = actual cost + potential (Di) potential (Di-1)
= log (n) + cNorth Carolina(N-1)
= log (n) + c (n-n + 1)
= log (n) + c

So I'm not sure how to prove that this potential function does not get an amortized cost by inserting O (logn). O (logn) would mean all functions less than or equal to constantslog (n) .log (n) + c is greater than log (n) but is it less than constant(logn + c)? Any help would be appreciated.

Extract parts of an expression

I have lists with phrases like this one: {-DTMomentum2[{0, 0, 1}], DTMomentum2[{0, 0, 0}]}. DTMomentum2 is just an indefinite function such that the minus sign is not distributed in the {0, 0, 1} vector. What I want is -DTMomenta[{{0, 0, 1}, {0, 0, 0}}] in the end, I want to collect all the complex valued factors in a product, then the three vectors in a list.

I tried to use Cases, and it works for the first to extract the moments:

Cases[#, DTMomentum2[p_] -> p]& / @ @ -DTMomentum2[{0, 0, 1}], DTMomentum2[{0, 0, 0}]}

The exit is {{{0, 0, 1}}, {}}it did not work with the second for any reason.

I've tried it with a simple Replaces all, but the minus sign appears in my vector:

{-DTMomentum2[{0, 0, 1}], DTMomentum2[{0, 0, 0}]} /. DTMomentum2[p_] -> p

The exit is {{0, 0, -1}, {0, 0, 0}}.

As long as everyone DTMomentum2 the expressions come with a factor in front, the following function does what I want:

MomentumProductToMomenta2[factors_] : = Block[
{moment, scalar},
Moment = Flatten[Case[Cases[Cas[Cases[#, DTMomentum2[p_] -> p]& / @ factors, 1];
scalar = Time @@ (factors /. a_ DTMomentum2[p_] -> a);
scalar * DTMomenta @@ momenta];

But as soon as there are terms in the list of factorsit just gives an empty list. Change the pattern a_ DTMomentum2[p_] will absorb the minus sign, but this pattern will fail. The inclusion of both models gives strange results and more terms appear.

How can I get the coefficients I want?

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reinvent the wheel – Python: Extract the main components

First, I am aware that this can be done in sklearn – I intentionally try to do it myself.

I'm trying to extract the eigenvectors of np.linalg.eig to form main components. I am able to do it but I think there is a more elegant way. The part that makes the task difficult is that, according to the documentation, the eigenvalues ​​resulting from np.linalg.eig are not necessarily ordered. So, to find the first main component (and the second and so on), I sort the eigenvalues, then find their original index, and then use it to extract the proper eigenvectors. I intentionally reinvent the wheel a little to find eigenvalues ​​and eigenvectors, but not after. If there is an easier way out of e_vals, e_vecs = np.linalg.eig (cov_mat) to the main components I am interested.

import numpy as np

np.random.seed (0)
x = 10 * np.random.rand (100)
y = 0.75 * x + 2 * np.random.randn (100)

center_x = x - np.mean (x)
center_y = y - np.mean (y)

X = np.array (list (zip (centered_x, centered_y))). T

def covariance_matrix (X):
# I am aware of np.cov - intentionally reinventing
n = form X[1]
    return (X @ X.T) / (n-1)

cov_mat = covariance_matrix (X)

e_vals, e_vecs = np.linalg.eig (cov_mat)

# The part below seems inelegant - looking for improvement
Sort_vals = Sorted (e_vals, reverse = True)

index = [sorted_vals.index(v) for v in e_vals]

i = np.argsort (index)

sorted_vecs = e_vecs[:,i]

pc1 = sort_vecs[:, 0]
pc2 = sort_vecs[:, 1]

extract – Trying to edit content.php

I'm trying to tweak the basic theme of bootstrap in order to show examples. This is the case when you use the search, but not by default.

I'm trying to figure out what I need to change on the content.php file. Anyone could he please advise.

I've been trying for hours and I'm fighting. Code below.

<article id = "post-" >

<a href = ""rel =" bookmark ">

& # 39;& # 39 ;, & # 39; separator & # 39; => & # 39; )); ?>

7 zip – Download and extract parts containing a specific file from the 7z split archive?

There is a file I want that is part of a very large 7z split archive. Instead of downloading the entire 100gb archive, I wonder if it is possible to access the block / end header of compressed metadata by downloading the last parts of the archive and use it to locate, download and extract specific parts of my file. situated in? If so, how could I do it?

Thank you.

Is there a more concise way to extract part of a string in Postgres?

I'm using Postgres 9.5. I have a table with a column that records the URLs. Sometimes the URL contains a query string and sometimes not. I would like to extract the URL, minus any query string, so I came up with

select the substring (url, 0, case position (& # 39; in the URL) when 0, then length (url) +1 otherwise position (& # 39;? & In the URL) end)
of the article;

It sounds a bit verbose and I wondered if there was a more concise way to proceed. My table column is TEXT.

calendar – Extract the event / meeting / date from a web page (as does iMail for mails)

do you know how iMail identifies and allows you to extract dates and places to create an event in iCal?
Is the same thing possible for web pages? Maybe there is a service mapping to do? Of course, ask as much as possible for integrated solutions.

Thank you.