Where can i buy bitcoin with lowest fees? | NewProxyLists


I’m looking for any tip on where to buy bitcoin with the lowest fee. I tried https://www.bestchange.com/?p=936130 and couldn’t find a way without giving a lot of info.

I already tested with
http://coinbase.com – In coinbase the method of payment was denied.
http://xapo.com – Xapo, they stop offering credit cards.
http://paxful.com – Paxful wants $60 for each $100 which makes $160 just for $100.
http://paypal.com – They have been announced that users can buy bitcoin but i don’t know where to buy.

Did anyone tested this?

Or recommend a easy way to buy bitcoin…

dnd 5e – What is the lowest level character that can unfailingly beat the Lost Mine of Phandelver starting encounter?

This question uses the first encounter of LMOP as (what I thought was) a fun framing device for an optimization question. Four downvotes in one minute makes me question that decision.

Tone is hard to convey in text, so I’ll make it explicit: this is just a fun optimization problem, not an attempt to ruin anyone’s game.

For a lot of players, Lost Mine of Phandelver from the D&D Starter Set was their first 5e adventure. The first encounter from that adventure is rather swingy, like many level 1 combats. PCs may end up victorious without a scratch, or unconscious without getting a turn.

Bad luck

What if you were really unlucky, though? Really, really unlucky. Can a single character unfailingly beat the encounter, despite all the dice being against them? What is the lowest level that you could pull this off?

Whatever can go wrong for the PC, will go wrong. In general, this means that they will roll a 1 on all dice rolls (attacks, saving throws, ability checks, damage, etc.) If a low roll is beneficial to them (Divine Intervention, for example), then that roll may be a higher roll.

Whatever can go right for the enemies, will go right. In general, this means that they will roll the maximum value on all dice rolls. If a high roll is harmful to them, then that roll may be a lower roll.

Encounter specifics

Four goblins. Two will use a scimitar and shield, and two will use shortbows. They use the average value for hit points.

  • When combat begins, the enemies are exactly 30 feet away from the PC. Any PC-controlled creatures start as close to the PC as possible. All participants start on the ground.
  • Two of the enemies (one melee and one ranged) are on each side of the road.
  • The enemies have a chance to gain surprise. There is sufficient cover to try to hide on both sides of the road.
  • The two melee enemies will close in. If it becomes clear that they can’t get into range, they may use an Action to doff their shields and switch to bows.
  • Ranged enemies will try to stay within 80 feet (the normal range of their weapons).
  • The PC has beat the encounter if they are alive when combat ends and all of the enemies are dead.

Character specifics

  • LMOP takes place in the Forgotten Realms, so I’m going to limit sources to FR-specific and setting-agnostic official hardcover books: Player’s Handbook, Monster Manual, Dungeon Master’s Guide, Sword Coast Adventurer’s Guide, Volo’s Guide to Monsters, Xanathar’s Guide to Everything, and Mordenkainen’s Tome of Foes.
  • Customizing ability scores, variant human, multiclassing, feats, and playing on a grid are allowed. All other variant rules are not.
  • No magic items or magic item-like things granted by the DM (boons, blessings, charms, etc.)
  • Spells/abilities you use before combat may only target you or creatures you control. Only spells/abilities whose effects last 8 hours or longer will still be active when combat starts. You do not get a rest between using any spells/abilities and combat starting.

python – Lowest Common Ancestor in Binary Tree (Iterative)

In the below code I’ve implemented a method to find the lowest common ancestor of a binary tree.

This is an iterative approach using this pseudocode.

Please suggest any improvements that can be made.

class Node:
    def __init__(self, data=None, left=None, right=None):
        self.data  = data
        self.left  = left
        self.right = right

def lowest_common_ancestor(root, node1, node2):
    parent = {root: None}
    stack = (root)

    while node1 not in parent or node2 not in parent:
        node = stack(-1)
        if node.left:
            parent(node.left) = node
        if node.right:
            parent(node.right) = node

    ancestors = set()
    while node1:
        node1 = parent(node1)
    while node2 not in ancestors:
        node2 = parent(node2)

    return node2.data

def main():
    Construct the below binary tree:

        11      29
       /      /  
      8   12  25  14

    root = Node(30)
    root.left  = Node(11)
    root.right = Node(29)
    root.left.left  = Node(8)
    root.left.right = Node(12)
    root.right.left  = Node(25)
    root.right.right = Node(14)

    print(lowest_common_ancestor(root, root.left.left, root.left.right))       # 11
    print(lowest_common_ancestor(root, root.left.left, root.left))             # 11
    print(lowest_common_ancestor(root, root.left.left, root.right.right))      # 30

if __name__ == '__main__':

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mining theory – Lowest numbered Bitcoin hash?

I was thinking about which bitcoin block has the lowest numbered hash. What I mean by a hash as a number is that. For example, the number “1” has a lower hash than “2” in SHA256. Their values are 6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b and d4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35. Which bitcoin block, as of me asking, has the lowest number?

To be clear, I mean by “lowest number” as the smallest hexadecimal hash. An example of a number would be block #651520 which is numbered 0000000000000000000d1f8cf49fe57d034214693cd7f7678abec20427355c82. Interestingly, the lower the number, the more work tends to be required to generate it.

I kind of like this question because the Bitcoin network is basically an extremely large SHA256 brute force machine. This hash would likely be from after the all time high in 2017 in price.

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