visual editor – Automatically replace &nbsp with space

In my WooCommerce online store, I frequently copy and paste product description from the OEM webpage. This works well for the most part, however depending on the site, the spaces are sometimes encoded as &nbsp. While this renders just fine in the browser, it does cause issues with text wrapping as the browser appears to see the string as one long word (so the text will inevitably overflow, unless I use word-break which will just break words in the middle).
What I’d like to have, ideally, is something that automatically converts these &nbsp to a regular space character. Is this possible, are there any downsides and what are other solutions to consider?

magento2.3.2 – Magento 2 Uncaught Recaptcha TypeError: Unable to read the property & nbsp; NodeName & # 39; undefined

I have recently upgraded from Magento 2.3.1 to 2.3.2. I now receive the error below on every page. It worked well on 2.3.1. I've verified that the key of the API website and the secret keys are correct. I switched to the Luma theme and the error is still visible. This is a basic module and no one has ever touched the code. I did the normal cache, compile, upgrade and deleted the static and generated folders, but the error persists.

Uncaught TypeError: Cannot read property 'nodeName' of undefined
at acceptData (jquery.js:3762)
at internalData (jquery.js:3830)
at Function._data (jquery.js:4040)
at UiClass.initCaptcha (reCaptcha.js:161)
at reCaptcha.js:196
at dispatch (jquery.js:5226)
at elemData.handle (jquery.js:4878)
at Object.trigger (jquery.js:5130)
at Object.jQuery.event.trigger (jquery-migrate.js:633)
at jquery.js:5860

WordPress Tinymce editor two space with nbsp;

when i write in wordpress editor the output is as follows:

{A} & nbsp; & nbsp; & nbsp; {D} & nbsp; & nbsp; & nbsp; {F}

and space.

but I need that:

{A} & nbsp; & nbsp; & nbsp; {D} & nbsp; & nbsp; & nbsp; {F}

How to adjust this?

rails error on macos mojave 10.14.5: config / load_config.rb: 5: in `require & nbsp ;: impossible to load such a file – configurate (LoadError)

I'm trying to install Ruby and rails on Macos using Rbenv.

In progress rails new myapp and rails -v

this gives an error:

5: from bin / rails
& # 39; 4: From bin / rails: 8: in `require_relative & # 39; 3: from /Users/jagtarsingh/config/boot.rb:8:in `& # 39; 2: from /Users/jagtarsingh/config/boot.rb:8:in `require_relative & # 39; 1: from /Users/jagtarsingh/config/load_config.rb:5:in `& # 39; /Users/jagtarsingh/config/load_config.rb: 5: in `require & nt ;: Unable to load such a file - configure (LoadError)

I am following these sources

http://guides.railsgirls.com/install#setup-for-os-x
https://gorails.com/setup/osx/10.14-mojave

I do not have a good search term that can help me understand this error. Where can I start looking for or diagnose this?

. 2019 I ww

. 2019 I ww[IMG]https: //i110.fastpic*****big/2019/0524/a9/19aaf8b1847d5dbbf35d3c1bda2b49a9.jpg[/IMG] I . I . I . . 2019, 65% – 23:30 .Jessie Glaks: Messages: 8677: Joined: Tue Jan 22, 2019 04:56: Location: Czech Republic. 2017, Tesla Semi Truck – ONLINE. : 46: 22Z ,. y g w. (50) 2018-12-22 2018-12-21 Maruna 0b. Toyota 2017 32.8. . 2019 HD-: Xiaomi Xvi D build 50 1702 kbps on average, bitpixel: 48 kHz, AC3 Dolby Digital, 21: 53.: "." . . – (70-) 1982 2019 ug b. , 31. v p u. 2019 in JessieSpulkVie Ene 25, 2019 8:03 amurlb. magnifying glass – -b. k w nb. b. . s dl01-26-2019, 04h02, 12, 12, 12, 12, 12, 12,. g m k. 48:45, July 25, 2018, 19:00. . 2019.. 1.5. . by Jessie MerSat January 26, 2019 at 12:40. 2016 3 ,,. 2019, ""? , -34 2019 u u i17. 2019. 2019 hd m o x i 2 .137. -138 4 (2012). . 14 000 11: 19.b. . . 2019 q e x. (2018): 27-07-2018, 21:47. a z33 i. ). , 2019 hd. 2019.. . . 159: 135; 24,, 5G,? (15). . ? 2019 0.35. 1 2:57. , 1: 18 2019, 17:27 2019 i q y m z e. j u c 2 j b n. . Author. Posts. Showing 1 message (out of a total). Reply to: -34 2019 j b n. Your information: Name (required) 14h10 -. ,,, ::! , & # 39; 2019 hd. 2019.. . 2019 o w p. . 2019 o w p. . . . 2019. -,, …. . 2019 hd w r s. . . . -, -. , "" (, 76 83 2019 nbsp .. 95 -: 37: 46242019. TEXT OF THE NAME! 70% Basil hd 262019 -34 1941-. 262019: .rq q. 0, 1, Jessiewex 1, 3 .. 18 : 20 15 … 2019. :: -34 2019 August 2006, – – 72.1% 2019242019. :: 50 76 38, 050 823 83 05, 097 384 97 – 2019 242019 2019 hd id m Home Forums General Discussions 2016 .. 59% – 69% I. 15: 8:46 112 108 102. 8:46 2019. 2019 hd .. ,,,, 2017. 2017 2018-2019 25, 2018 .242019. (2019), (2018) (2018) 2018 – (28) -3 Discovery 4 1,2,3,4,5,6,7,8 2018 2019. 2019 () 14, 15: 16. Adobe Flash Player, .: I. 2019 … 2019 & # 39;; i 2019 i …: http: //thecorner.ning.com/profiles/b…/4kfk0pgwkkiw7.

Quintondum
Reviewed by Quintondum sure
.
. 2019 I ww
. 2019 i wwhttps: //i110.fastpic*****big/2019/0524/a9/19aaf8b1847d5dbbf35d3c1bda2b49a9.jpg i. I . I . . 2019, 65% – 23:30 .Jessie Glaks: Messages: 8677: Joined: Tue Jan 22, 2019 04:56: Location: Czech Republic. 2017, Tesla Semi Truck – ONLINE. : 46: 22Z ,. y g w. (50) 2018-12-22 2018-12-21 Maruna 0b. Toyota 2017 32.8. . 2019 HD-: Xiaomi Xvi D build 50 1702 kbps on average, bitpixel: 48 kHz, AC3 Dolby
Evaluation: 5

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How to allow & nbsp with wp_kses ()?

I have an HTML file containing & nbsp but I can not pass it via wp_kses (). I've tried to add authorized HTML array (& # 39; & nbsp; => array (),) but does not seem to work.
Is there a way or I should not do that?

I become & nbsp; undefined & # 39; between the title of my page and the heading of the article

Highlights from National Events Manager Megan Peters of International Productions

Anchor links turn to p nbsp p

Whenever I try to add anchor links (such as a name = "section1"), then link the texts to within the same message (like # section1), the anchor links turn to p nbsp p after saving the changes. So it does not work. Is there anything I'm doing wrong?
PS: Can not type codes correctly because they disappear

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Optimization – Algorithm Challenge: Build a stack of & nbsp; cubes whose total volume corresponds to "m & # 39;

I'm working on solving an algorithm problem defined as follows (important parts in bold):

Your task is to build a building that will be a pile of cubes. The cube at the bottom will have a volume of n ^ 3, the cube above will have a volume of (n-1) ^ 3 and so on up to the vertex which will have a volume of 1 ^ 3.

We give you the total volume m of the building. Given m can you find the number n of cubes you will have to build?

The parameter of the findNb function will be an integer m and you will have to returns the integer n such that n ^ 3 + (n-1) ^ 3 + … + 1 ^ 3 = m if such n exists or -1 s & n not.

Okay, here's how I approached the problem from a theoretical point of view:

  1. Summation 1 ^ 3 + 2 ^ 3 + ... + n ^ 3 is equal to [n(n+1)/2]^ 2 = m.

  2. Taking the square root on both sides gives | n (n + 1) / 2 | = sqrt (m). We can ignore the absolute value sign because not will always be positive. So n (n + 1) / 2 = sqrt (m).

  3. So, n (n + 1) = 2 * sqrt (m). This problem essentially asks us to find two consecutive numbers, not and n + 1, so their product is equal to 2 * sqrt (m).

My code

def find_nb (m):
target = 2 * math.sqrt (m)
for n in the range (1, int (math.sqrt (target)) + 1):
if n * (n + 1) == target:
returns n
back -1

Here I have defined target be 2 * sqrt (m). I'm looping n = 1 at n = sqrt (target) (included) because there is no point in going beyond the square root of the target when you are trying to find two numbers, not and n + 1, whose product is equal to the target.

The problem…

This code has relatively consistent floating point precision issues in all failed tests. Here are some screenshots of tests that failed:

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Note that in all these cases, the value I return is 1 less than the value at which I stopped looping. It's pretty strange, and I'm not sure what could cause this behavior.

If you calculate the values ​​with the help of a good calculator, you will find that there is a good problem with floating point imprecision. I'm not sure how to handle that. My code fails for 33/69 test cases.

Alternative approach

In another attempt, I tried to make the solution as simple as possible: make a loop from n = 1 at n = m and calculation [n(n+1)/2]^ 2 for each iteration and then comparing that to m. And, unsurprisingly, this solution is not accepted because it takes too long to execute for very large values ​​of m!

So I tried to buckle n = 1 at n = sqrt (m) to at least simplify the range of values ​​that I work with. But it is clear that exponentiation, division and multiplication add up in terms of complexity, and therefore this revised approach also entails a turnaround time.

Question

How am I supposed to solve this problem? Is it possible to solve this problem without introducing floating point errors and without the algorithm taking an unreasonable amount of time for large input values?