## Obtain the vector potential and the magnetic vector of infinite wire load?

I am working on the above issue, but I am really stuck for days. my goal is to implement the following problem in Mathematica. Any help would be appreciated.

## Obtain iPad / iPhone information using only their UDID?

Is it possible to get information on an iOS device by just using its UDID?
Information such as iPad model, operating system, etc.

I have a developer account where I register Apple devices using its UDID, but how can I extract information for these devices?

## automatic learning – How to automatically obtain the longest line on the dendrogram?

Instead of manually guessing the longest vertical line, is there any way to automate it? Or to highlight it clearly on the graph itself?

p.s:
I know the Elbow method but I need this information on the dendrogram.

My code

``````# Importing the libraries
import numpy as np
import matplotlib.pyplot as plt
import pandas as pd

# Importing the dataset
X = dataset.iloc(:, (3, 4)).values

# Using the dendrogram to find the optimal number of clusters
import scipy.cluster.hierarchy as sch
dendrogram = sch.dendrogram(sch.linkage(X, method = 'ward'))
plt.title('Dendrogram')
plt.xlabel('Customers')
plt.ylabel('Euclidean distances')
plt.show()
``````

dendrogram

## Theme – Can I use the view filter without using the Twig Tweak module, I want to obtain the content of the referenced field

``````  {% for entity in node.my_content_type_field %}
{{ node.my_content_type_field[loop.index0].entity.my_paragraph_field.entity.my_reffernced_content_type_title_field|view }}
{{ node.my_content_type_field[loop.index0].entity.my_paragraph_field.entity.my_reffernced_content_type_image_field|view }}
{% endfor %}
``````

This is my code, it works fine, I am using this view filter, coming from the twig tweak module, but if I don't want to use the twig tweak module, then how to use the view filter,
and if I tried to get values ​​without using the view filter, I can get all the values, the only value I can't get is the value of the image field, give me a solution.

## Analysis successful, but cannot obtain ANY SharePoint 2016 search result

We finish creating a new solution on site SharePoint 2016. Everything works except the search, which seems completely broken.

As far as we can say that all of the service account permissions are correct for research, but we can never get results.

Exploration is successful, all websites are affected, but nothing comes out of the search regardless of the search term.

The only thing I can think of is an obscure permissions issue or even if the websites are crawled, their content is not indexed and somehow is not available for most research elementary or the research itself is just badly wired.

The
I loaded the ULS viewer and searched and two things jumped. The query seems to come in, but never has any results.

"Microsoft.Office.Server.Search.Query.Ims.ImsQueryInternal: number of tables in the result: 4, relevant results: 0 (total: 0, total, including duplicates: 0), refinement results: 0"

How can I verify that there is searchable content after a scan? In addition, I now have 2 search service apps and I'm not sure how to connect them to the different search areas.

## Obtain a clear image for a paper with a 7.62 mm hole located at 50 m

I'm going to assume that you only want to count the holes on a paper target and know their approximate location.

7 mm at 50 meters is 0.008 degrees.

Then we have to make some assumptions about the camera. I will be using my equipment, a Canon 7D, APS-C (1.6 crop sensor), of around 5000 pixels on the long side.

I would like the holes to be around 10 pixels wide, this is an estimate of how important you need the holes in the camera frame.

10 pixels / 5000 pixels = 1/500 of the frame

0.008 degrees * 500 = 4 degree field of view

You can achieve this with a 400mm lens, these are fairly common and a decent good is \$ 1,000 to \$ 2,000. See this calculator.

Note that your field of vision will be 2.8 x 1.8 meters. It’s probably bigger than your goal. If you want the target to fill the camera frame, the calculation will be different.

Edit: test the image. 3.5 mm hole at 25 meters. I can't easily walk 50 meters.

Canon 7D, zoom 100-400 f5.6 M1 @ 400 mm, f8, remote flash.

Zoomed to display the actual pixels:

## How to efficiently obtain the rational solution of a linear system?

Suppose I have a linear system $$AX = b$$ with $$A in mathbb {Z} ^ {n times m}$$ and $$b in mathbb {Z} ^ {n}$$. Suppose that $$AX = b$$ has exactly a rational solution. How can I get this solution effectively?

I know that the LU decomposition is a choice for this purpose. But it seems that integers can develop in the process of calculating an LU decomposition, which I hope to avoid.

If I have a digital solution of $$AX = b$$, Does it help?

## magento2 – Obtain a correct configurable product image on my order page

I want to show the correct product image on my order details page:

I use it as:

``````\$_item = \$block->getItem();

\$objectManager = MagentoFrameworkAppObjectManager::getInstance();

\$imageHelper  = \$objectManager->get('MagentoCatalogHelperImage');

\$image_url = \$imageHelper->init(\$_product, 'product_page_image_small')->setImageFile(\$_product->getImage())->resize(100, 100)->getUrl();
``````

but showing the main product image, it does not show the child product image. here i want to show the correct configurable product image.

Thank you

## gr.group theory – How to obtain a profine group from its normal open subgroups?

Let $$Delta$$ be a collection of professional groups. In what conditions $$Delta$$, there is a profine group $$G$$ who has $$Delta$$ like the collection of its normal open subgroups? By that I mean, an open normal subgroup of $$G$$ is topologically isomorphic to an element of $$Delta$$?

## Obtain a clear image for a paper with a set of 7.62 mm located at 50 m

I'm going to assume that you only want to count the holes on a paper target and know their approximate location.

7 mm at 50 meters is 0.008 degrees.

Then we have to make some assumptions about the camera. I will be using my equipment, a Canon 7D, APS-C (1.6 crop sensor), of around 5000 pixels on the long side.

I would like the holes to be around 10 pixels wide, this is an estimate of how important you need the holes in the camera frame.

10 pixels / 5000 pixels = 1/500 of the frame

0.008 degrees * 500 = 4 degree field of view

You can achieve this with a 400mm lens, these are fairly common and a decent good is \$ 1,000 to \$ 2,000. https://www.pointsinfocus.com/tools/depth-of-field-and-equivalent-lens-calculator/#{%22c%22:({%22f%22:9,%22av%22:%228% 22,% 22fl% 22: 400,% 22d% 22: 50000,% 22cm% 22:% 220% 22}),% 22m% 22: 1}

Note that your field of vision will be 2.8 x 1.8 meters. It’s probably bigger than your goal. If you want the target to fill the camera frame, the calculation will be different.

Edit: test the image. 3.5 mm hole at 25 meters. I can't easily walk 50 meters.

Canon 7D, zoom 100-400 f5.6 M1 @ 400 mm, f8, remote flash.

Zoomed to display the actual pixels: