Cursed Specter vs trapping the soul that would take priority?

I'm looking to find out which one wins or takes effect first.

The cursed Spector has no action type but traps the soul and is defined as a reaction.


mathematical programming – Why do we need / use operator priority for arithmetic operators?

As you can see, there is no need for operator priority. There are a number of other conventions that have been used in various contexts. Some programming languages ​​have implemented the left-to-right convention you mention in the question, and many have avoided the problem entirely by using Polish notation or its reverse.

the goal operator priority conventions is to reduce the number of parentheses necessary to communicate unambiguously the ideas that occur in practical mathematical use. The most important rules – that multiplication has higher priority than addition, and exponentiation has higher priority than multiplication – exist mainly for the convenience of writing polynomials. Without these rules, polynomial expressions would require much more parentheses. Polynomials are so central to mathematical practice that they bleed in notation, operator priority and elsewhere.

Operator priority rules beyond arithmetic and basic relational ($ = $, $ leq $, etc.) operators are domain specific, and article authors sometimes need to specify the convention they use in their notation section. Again, the purpose of having such rules is to improve communication in situations where it is better to specify a convention that the reader should remember than to write parentheses everywhere.

When priority rules are normalized across an entire mathematical field, it is often because the rules have a clear analogy with arithmetic or relational operators on numbers. For example, concatenation has higher priority than union in regular expressions because regular languages ​​form a semicircle, like all of your favorite numeric systems, and regular expressions are polynomial expressions in this semi- system.

How do I change the ISO and shutter speed settings in Aperture Priority mode on a Canon DSLR?

When you are in "Creative Zone" exposure modes (P, Tv, Av, M) you can select the ISO speed setting using the "ISO" button on the top of the camera photo or by going to & # 39; Menu → Shooting (red) Tab 2 → ISO speed & # 39 ;.

In the Creative Zone exposure modes (P, Tv, Av, M), you can select the maximum ISO speed limit by going to & # 39; Menu → Shooting (red tab) 2 → ISO Auto & # 39 ;, by pressing the "Set" button, scrolling to the desired maximum ISO value between 400-25600 and pressing the "Set" button again.

The EOS 77D does not have the ability to select a minimum shutter speed when shooting Aperture priority (Av) exposure mode, there is also no option to select the range of ISO speed settings that will be available when using the ISO button or option & # 39; Menu → Shooting (red tab) 2 → ISO speed & # 39; to set the ISO speed. Canon EOS superior models offer these features.

android – Firebase: Persistence – Priority in offline updating?

I have persistence enabled in my app, to keep the BD updated after disconnecting the device:


I performed the following test:
1º.- I have disabled the data and the wifi of the device.

2º.- I modified a BD register, from the Firebase console.

3º.- I modified the same register, but in the device, with another data different from that which I modified in the BD.

4º.- I activated the Wi-Fi and when entering the application, the device information was updated with data from the BD Firebase.

So far everything is okay because persistence has worked.

But I did the same test BUT I first updated the information on the device, then the BD. I assumed that now the BD information would be updated with that of the device, but this is not the case, the device has been updated with the modification of the BD. I assumed that Firebase would have a timestamp, or something similar, to determine which data is the most recent and which data can be updated and which is not.

So what criteria does Firebase follow to know which data is the most recent?

java – Priority queue with Max-Heap

I study with the book "Introduction to Algorithms" and I implemented PriorityQueue without an existing class.

I created a MaxHeap class with Array and created a PriorityQueue with my Heap class.

In fact, the code works and the refactored code did my best,

but I am a beginner so I need feedback for everyone.

Do you want to give me an opinion?

public class PriorityQueue {

    private Heap heap;

    public PriorityQueue(int() src){
        heap = new Heap(src);

    public int size() {
        return heap.size();

    public int extractMax() throws Exception {
        if(heap.size() < 1)
            throw new Exception("heap underflow");

        int max = heap.get(0);
        return max;

    public int getMaximum() throws Exception {
        return heap.get(0);

    private int getLastIndex(){
        return heap.size()-1;

    public void increaseKey(int idx, int key) throws Exception {
        if(idx >= heap.size())
            throw new IndexOutOfBoundsException();

        if(key < heap.get(idx))
            throw new Exception("new key is smaller than exist value");

        while(idx > 0 && heap.get(heap.getParentIndex(idx)) < heap.get(idx)){
            swap(idx, heap.getParentIndex(idx));
            idx = heap.getParentIndex(idx);

    public void add(int key) throws Exception {
        increaseKey(heap.size()-1, key);

    private void MaxHeapify(int idx) {

        if(idx < 0 || idx >= heap.size)
            throw new IndexOutOfBoundsException();

        int leftIndex = heap.getLeftIndex(idx);
        int rightIndex = heap.getRightIndex(idx);
        int size = heap.size();
        int largest = -1;
        int tmp = Integer.MIN_VALUE;

        // compare with leftNode
        if(leftIndex < size && heap.get(leftIndex) > heap.get(idx))
            largest = leftIndex;
            largest = idx;
        // compare with rightNode
        if(rightIndex < size && heap.get(rightIndex) > heap.get(largest))
            largest = rightIndex;

        // swap if parentNode is bigger than child.
        if(largest != idx){
            // recursive call

    private void swap(int from, int to) {
        int tmp;
        tmp = heap.get(from);

    public String toString(){
         return Arrays.toString(heap.array);

    public class Heap {
        int() array = {};
        int size;

        public Heap(int() src){
            array = src;
            size = array.length;

        public Heap(){
            array = new int(10);
            size = array.length;

        public int getLeftIndex(int idx){
            return 2*idx+1;

        public int getRightIndex(int idx){
            return 2*idx+2;

        public int getParentIndex(int idx){return idx/2;}

        // heap's size
        public int size(){
            return size;

        // array's size
        public int length(){
            return array.length;

        public void incrementSize(){ size++; }

        public void decrementSize(){

        public int get(int idx) {
            return array(idx);

        // if heap's size is bigger than array's length, grow array's size;
        private void checkCapacity() {
            int oldCapacity = length();
            if(size >= oldCapacity){
                int newCapacity = oldCapacity + 10;
                array = Arrays.copyOf(array, newCapacity);

        public int() getHeap(){
            return array;

        public boolean isValid(int idx){
            return size-1 >= idx ? true : false;

        public void set(int idx, int value) {
                array(idx) = value;
            throw new IndexOutOfBoundsException();

Does Google really give priority to quality content?


Does Google really give priority to quality content?
Because I have often seen the ranking of websites on position # 10 … | Read the rest of

How to use multiple sources of priority repositories in NPM?

I know that it is possible to use local records with the command

npm config set registry 

But as I understand it, this command changes NPM to fetch only in this repository.

I've also read about scoped packages, but if I understand correctly, it will only use my repository when I expressly declared that this package is in my repository and that, if it were not found, it could not be installed. But what I wanted to do is try searching in my local repository and, if it does not find it, in the NPM repository (

I wonder if it is possible to make a npm install with this order of priority, where will he get the parcels?

navigation – Should users know the advanced and low priority features of the application?

Of course, you can tell users that the feature exists – at a place where it is relevant to show that it is available.

Change the PIN code usually resides somewhere in the settings, so show it in the entire view of the settings page. If it is something that is rarely used, make sure you respect that hierarchy and not place it at the top. This way, you do not hide its existence, nor take up space for features that are used more often.

Users who are looking for obscure functionality will imagine under what main subject they could logically find it, then go for it. If the structure of your application is healthy, they will find it intuitively. If you have a menu item called dashboard or transactions, they will look for a reporting feature.

If your users are mainly using what you have already pushed as main features, then your application seems to be doing what it should do. If they are complaining that you have not yet added some features, while it is available, then you should consider changing the hierarchy and visibility of the features. Then, it is clear that your presentation structure makes things difficult to find.

Frequently used actions / features should be easy to see and navigate; items used sparingly or considered advanced may be placed further down the hierarchy.

co.combinatorics – Number of permutations with priority constraints

I have two sets of balls (black and white), each game is numbered from $ 1 $ at $ n $and all are put in a jar. My precedence constraint is expressed as follows: choose a black ball with index $ i $, its corresponding white ball (with the same index $ i $) must be chosen before. How many permutations of black and white balls can we count? I've tried to express this number recursively with the following function,

## EQU1 ## + (n-3) …) big) Big), $ and $ f (1) = $ 1,

with $ g (n-k) $ is the number of permutations involving k $ black balls, for which their whites have already been chosen, and the rest $ 2 (n-k) $ balls. I know it $ g (n-k) $ is according to $ f (n-1) $but I'm still looking for its correct expression, and in case we could find a simpler formulation for $ f (n) $. If you have a pointer, thank you in advance. I hope you find this fun counting problem to solve.

Priority fields of the contact form

Is it safe not to use the message field at the beginning in a contact form?

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