Have you ever thought of a way to get paid without doing anything with your facebook ads account? There is a company that has paid instantly $ 5 when you qualify and $ 20 when you have completed your registration. To get, join my group on Messenger by visiting: https://m.me/join/AbYSr9-6f_JuVBfH
What the company does is rent out the business side of your Facebook and pay you for it! They do it using their adbox method. An advertising box is a computer used to promote ads. This is shipped to you for free! This box will not steal any information as it is only used to promote ads. PAYMENT payment details below: * You will be paid $ 5 instant after qualifying (takes about 15 minutes) * Another $ 15 payment in approx. one week after setting up your advertising box. * An additional $ 5 payment is added to it as a bonus when it is set up within 24 hours of receiving the ad box (* A total of $ 20 is so possible if it is configured within 24 hours of receiving via USPS) * Residual monthly income of $ 15 just to keep the box connected (check with an Ad Rentals Inc.) * Unlimited Payments of $ 25 to your PayPal Zelle or Cash application for each reference (paid 2 to 3 times a week)
100% LEGIT SO EASY … CONNECT AND BE PAID We pay you to rent your advertising space on your social media accounts. For Facebook, we will first go to your Facebook page to qualify the account, then to create what is called a professional page to place our ad. We monitor ads to see which ads are generating the most clicks on the website. The business page we create and your Facebook page have the same password. They must be able to access this page to create, monitor and pay for ads using the credit card of our company. Once the account qualified, we send you an advertising box that you connect to your modem (so that the technician can connect remotely without the connection name is reported), this advertising box is pre-programmed with your Facebook login information so that you In the dialog box, the technician can connect remotely to your Facebook page to create the ad. He then connects to monitor and pays for the announcement using the credit card of our company. So we must always have the right information to log in, no work is required from this little box and the technician does all the work. if you are qualified please let me know so I can keep you in a chat and get paid soon
What does the advertising box do? The billbox comes pre-programmed with your login information to Facebook. An advertising box is essentially a single-board computer the size of a credit card. All you need to do to start receiving payment is to connect it to your modem via an Ethernet cord and a micro USB charger (all these items are delivered to you for free). The ad box has only one purpose, manage the ad on your account. The unit will not expose or endanger the modem or computer to which it is connected, or access personal information and / or files from your computer. The advertising box will do all the leg work with the ads. This amazing little device will do all this work for you! We will only need one access once for you to qualify. This is what the Facebook advertising box can detect when someone logs in to your account from a different IP address (location) … Say it to Hawaii and I log in to your account at leave this place. Facebook will say "no way to be connected to Hawaii an hour ago and it is now in California" so that they stop ads and report advertising space thinking that someone is going to be there. A hacker your account … Basically, the box encourages Facebook to think that it is you log in to your account, while in reality it is us! The ads we publish do not affect your page at all You or your friends will not even see them. They are on a separate page called the company page that we create. You use your Facebook page as you would normally nothing changes
What kind of ads do we place? We have many customers who test test ads on social media sites. I would not know which advertisement EXACTLY will be posted on YOUR page (I can guarantee you that it will be a lawful company that we will publish for nothing, neither illegal nor explicit OR ILLICIT), we create a business page on your page for place the ad. You do not even see the announcement unless you access your ad manager. This does not appear in your news feed OR on your page. It's a completely separate page. And all ads come from legitimate and reputable companies, usually small health and beauty products companies that are just starting to figure out which ads work best for their marketing strategy. Join my group on Messenger by visiting: https: // m. me / join / AbYSr9-6f_JuVBfH
REQUIRED TO START How can I qualify? MUST be 18 years old or older, have a laptop or a preferred computer (not required) can also be qualified with a smartphone, must have a stable wifi connection !!!! MUST have a ROUTER with an additional Ethernet port / plug-in available. MUST HAVE MORE THAN 100 FRIENDS FACEBOOK (DO NOT HAVE 100 FRIENDS – NOT A PROBLEM, WE CAN FIND YOU FAST) MUST HAVE Facebook for MINIMUM 1 YEAR MUST BE ACTIVE EVERY DAY Blank ad account on Facebook It does not have to not have any pending ads on your account. MUST reside in the United States, Canada, United Kingdom, Austria, Belgium, Bulgaria, Croatia, Czech Republic, Denmark, Estonia, Finland, France, Germany, Greece, Hungary, Ireland, Italy, Latvia, Lithuania, Luxembourg, Malta, Netherlands, Poland, Portugal, Romania, Slovakia, Slovenia, Spain, Sweden, relocate within the next 4 months MUST PARTICIPATE in the study for at least 4 months without disconnecting the advertising area. the registration form
to get started, join my group on Messenger by visiting: https://m.me/join/AbYSr9-6f_JuVBfH
. (tagsToTranslate) earn money (t) win (t) payment
So I tackled the following problem:
And here is my job:
However, I'm not sure that my proof is complete, because I think the shape could still be a rhombus? So I'm just wondering if the evidence is satisfactory for part a.
Let $ a, b, n $ Z $ with $ n> $ 0 and $ a equiv b pmod n $.
CA watch $ gcd (a, n) = gcd (b, n) = d $.
I tried to rewrite $ b = a + ny $ for some people $ y in Z $. Now if I have $ d mid a $ and $ d mid n $then $ d mid b $. However, I do not know how to continue.