hosts file – Pulse Secure VPN change the hostname on macOS. How and why does it do it? Is this a security concern?

Once I connect to Pulse Secure 9 VPN on macOS, my host name on Terminal changes. Checking on System Preferences > Network > Advanced... > WINS > NetBIOS Name this is where it’s being set. Why does and how does that happen? Is this a security concern?

Their KB19294 article says

Hosts file is modified/accessed when a VPN Tunneling client is launched
[…]
to ensure that the PCS hostname resolves to the same IP which it resolved to before the tunnel was launched

And it seems like my /etc/hosts gets over written and a /etc/pulse-hosts.bak gets created, but the host name is not set there.


Notes

  • Maybe my question already contains the partial answer, but it still doesn’t make sense to me.

Hilbert Transform Calculation of a pulse

Can anybody help me with the Hilbert transform of the following pulse:
$$
p(t) = frac{8Brho cos(2pi Bt+2pi Brho t)+frac{sin(2pi Bt-2pi Brho t)}{t}}{pisqrt{2B}(1-64(Brho t)^2)}
$$

I tried by convolution of the above signal with $h(t) = 1/pi t$ but I am not able to simplify it.
Can anyone suggest an approach?

backup – How to actually delete SMS/MMS messages using third-party SMS applications like Pulse SMS?

A while back, I switched from Samsung’s default SMS app (Samsung Messages) to Pulse SMS.

For many months, I’ve been using Pulse SMS to delete old SMS and MMS messages. After deleting almost all MMS messages and thousands of SMS messages, I backed up Android’s SMS/MMS database using Epistolaire. Much to my surprise, the backup was over 500GB.

Given that SMS messages are tiny, I immediately knew something was wrong. So I loaded up Samsung’s default SMS app, and sure enough, every one of my supposedly-deleted SMS and MMS messages are still technically on the Android device (even though thousands of them had supposedly been deleted by the Pulse SMS app).

Besides going through tens of thousands of SMS and MMS messages again, how can I remove all the supposedly-deleted SMS/MMS messages from Android without removing the thousands of messages I want to keep?

Also, how do I prevent this mess from happening in the future?

Pulse 9 – pulse9.io – HYIPs

I Am Not Admin/Owner Of  The Project! !!!

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Pulse 9 – Pulse9.io

I Am Not Admin/Owner Of The Project! !!!

Reduced Size Image

Online Date : 2020-05-15

Investment Plans: 7% Daily for 30 Days, 9% Daily for 45 days, 11% Daily for 60Days , 14% Daily for 120 Days

Min Spend : 50$

Referral Commission : 9-2%

Withdrawal Type Instant

Licensed Script

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Accpet Payment : Bitcoin, Litecoin, Bitcoin Cash, Dash, Ethereum, Perfect Money, Payeer.
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About Project :

QUOTE

PULSE9 is focused on crypto-currency markets and tokenized assets. The systems can be applied to anything, for example, commodities, art, real estate, weather metrics, social media trend data and so forth. PULSE9 will be simple to use for everyone.

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This post has been edited by viking88hp: Jun 3 2020, 12:32 PM

sierra – How do I cleanly remove old Juniper Pulse installation from Mac OSX?

The Console application on the Mac is continuously throwing log messages presumably because fragments of a previous install are still in place. I have tried Goggling around for a solution and using grep to search through plist files for obvious strings. No luck so far.

Getting recurring error messages per the below:

May 26 19:12:53 MacBook-Pro com.apple.xpc.launchd(1) (net.juniper.AccessService(73727)): Service could not initialize: Unable to set current working directory. error = 2: No such file or directory, path = /Applications/Junos Pulse.app/Contents/Plugins/JUNS: 16G2136: xpcproxy + 11215 (1386)(C3C8A771-3847-30E4-BE12-7941C4A2924D): 0x2
May 26 19:12:53 MacBook-Pro com.apple.xpc.launchd(1) (net.juniper.AccessService): Service only ran for 0 seconds. Pushing respawn out by 10 seconds.

The Fourier transform of the pulse train, from the Fourier transform of the unit pulses, causes a contradiction

I am a little confused as to the definition of the Fourier transform of the pulse train function. Concretely, when I derive it from the Fourier transform of the unit impulse function, using the linearity of the Fourier transform, I find a contradiction when I compare my result with the proposed result.

Here is my derivation

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enter description of image here

Am i wrong somewhere Or is there something wrong with the original definition of the Fourier transform of the pulse train function, that is to say
$$ { cal {F}} {s _ { Delta T} (t) } ( mu) = frac {1} { Delta T} sum_ {n = – infty} ^ infty delta ( mu – frac {n} { Delta T}) $$

physical – Apply a pulse in the direction line tip with a force proportional to the length of the line

I have a line perpetually pointing to the mouse and coming from the player, but the length is limited to a certain value.

    line and player

I can also create a circular object on demand in Box2D (in particular love2d binders). I would like to apply an impulse to the new object which will send it to fly in the direction of the line, with a force proportional to the length of the line (this specific proportion is not important).
The object must not roll along this line like a cannon ball in a cannon, but it must start its journey in the direction of the line, so that a user can intuitively direct the projectile ( all my attempts * to solve this problem have led to some angles (45/135) having projectile directions similar to flat angles (0/180), which means that the angle is not functional in as a targeting mechanism). I guess a successful implementation might look like this:
arcs along the line

I have watched tutorials and I have not found an answer. I see whispers on how to do it by just providing the angle (if I read the pages correctly) but the Love2D function doesn't support that.

The way Love2D applies a linear pulse is Body:applyLinearImpulse( ix, iy, x, y ) with ix and iy being the x and y components of the impulse, and x and y being the position to apply the impulse (default at the origin of the body).


* The best I have tried is to apply the line distance as x / y components applyLinearImpulse. This creates the terrible failure that I mentioned earlier where the angle of the line doesn't make much difference in the angle of the projectile (but it produces a tiny quantity, with extremely decreasing yields when the line approaches a 90 degree angle / vertical line).

Summary of rules and guidelines for pulse waves

Summary of rules and guidelines for impulse Waves

From a theoretical point of view, care must be taken not to confuse Elliott waves with their measurements, which are like a thermometer to be heated. A thermometer is not designed to measure short-term rapid fluctuations in air temperature and no index of 30 stocks is constructed so as to be able to record all short-term fluctuations in social mood. Although we fully believe that the listed rules govern Elliott waves as a collective mental phenomenon, the recordings of actions induced by Elliott waves – such as buying and selling selling some stock lists – may not perfectly reflect these waves. Therefore, the recording of such actions could deviate from a perfect expression of the rules simply due to the imperfection of the chosen gauge. That being said, we have found that the Dow Jones Industrial Average has followed Elliott's rules perfectly to a minor degree and above and almost always to lower degrees as well. Below is a summary of known rules and guidelines (except Fibonacci relationships) for the top five patterns, variations, and combinations of waves.

golden signals

Motivated Waves

Impulse

Rules

· An impulse is always subdivided into five waves

· Wave 1 is always subdivided into pulse or (rarely) diagonally.

· Wave 3 is always subdivided into pulse

· Wave 5 is always subdivided into pulse or diagonal.

· Wave 2 is always subdivided into a zigzag, flat or combination.

· Wave 4 is always subdivided into a zigzag, flat, triangle or combination.

· Wave 2 never exceeds the start of wave 1.

· Wave 3 always travels past the end of wave 1.

· Wave 3 is never the shortest wave.

· Wave 4 never exceeds the end of wave 1.

· Waves 1, 3 and 5 are never all extended.

· توصيات الفوركس

Guidelines

golden signals

· Wave 4 will almost always have a different corrective pattern from Wave 2.

· Wave 2 is usually a zigzag or a combination of zigzag.

· Wave 4 is generally a flat, triangular or flat combination.

· Sometimes wave 5 does not move past the end of wave 3 (in which case it is called truncation).

· Wave 5 often ends when it meets or slightly exceeds a line drawn from the end of wave 3 which is parallel to the line connecting the ends of waves 2 and 4, on the arithmetic scale or semi-log.

· The center of wave 3 almost always has the steepest slope of any equal period in the parent impulse, except that sometimes an early part of wave 1 (the "kickoff") will be steeper .

· Waves 1, 3 or 5 are generally extended. (An extension appears "stretched" because its corrective waves are small compared to its impulse waves. It is significantly longer and contains larger subdivisions than non-extended waves).

· Often the extended sub-wave is the same number (1, 3 or 5) as the parent wave.

· It is rare for two sub-waves to extend, although it is typical for waves 3 and 5 to extend when they are of Cycle or Supercycle degree and in a fifth wave of A higher degree.

· Wave 1 is the least extensive wave.

· When wave 3 is extended, waves 1 and 5 tend to have tied gains or Fibonacci ratio.

· When wave 5 is extended, it is often proportional to Fibonacci relative to the net course of waves 1 to 3.

· When wave 5 is extended, it is often proportional to Fibonacci relative to the net course of waves 1 to 3.

· Wave 4 generally ends when it falls within the price range of sub-wave four of 3.

· Wave 4 often subdivides the entire pulse in proportion to Fibonacci in time and / or price.

Diagonal

توصيات الذهب

Rules

· A diagonal is always subdivided into five waves.

· An ending diagonal always appears as wave 5 of an impulse or wave C of a zigzag or flat.

· A diagonal of the head always appears as wave 1 of an impulse or wave A of a zigzag.

· Waves 1, 2, 3, 4 and 5 on an ending diagonal, and waves 2 and 4 on a leading diagonal, are always subdivided into zigzags.

· Wave 2 never exceeds the start of wave 1.

· Wave 3 always exceeds the end of wave 1.

· Wave 4 never exceeds the end of wave 2.

· Wave 4 always ends in the price territory of wave 1. *

· In time, a line connecting the ends of waves 2 and 4 converges towards (in the contracting variety) or diverges (in the expanding variety) a line connecting the ends of waves 1 and 3.

· In a leading diagonal, wave 5 always ends beyond the end of wave 3.

· In the contracting variety, wave 3 is always shorter than wave 1, wave 4 is always shorter than wave 2 and wave 5 is always shorter than wave 3.

· In the expanding variety, wave 3 is always longer than wave 1, wave 4 is always longer than wave 2 and wave 5 is always longer than wave 3.

· In the expanding variety, wave 5 always ends beyond the end of wave 3.

· توصيات الذهب

Guidelines

· Waves 2 and 4 generally retrace from 0.66 to 0.81 of the previous wave.

· The waves 1, 3 and 5 of a diagonal of the head generally subdivide into zigzags but sometimes seem to be impulses.

· Within a pulse, if wave 1 is a diagonal, wave 3 is likely to extend.

· In an impulse, wave 5 is unlikely to be a diagonal if wave 3 is not extended.

· In the contracting variety, wave 5 generally ends beyond the end of wave 3. (Failure to comply with this rule is called truncation.)

· In the contracting variety, wave 5 generally ends at or slightly beyond a line that connects the ends of waves 1 and 3. (The end beyond this line is called a reversal.)

·

· توصيات العملات

· In the expanding variety, wave 5 usually ends slightly before reaching a line that connects the ends of waves 1 and 3.

https://www.gold-pattern.com/

Summary of rules and guidelines for impulse Waves

openssl – Pulse request TLS and Heartbleed how?

How can an attacker send a fake Heartbeat request according to the TLS extension discussed in RFC 6520 without completely diverting the TLS connection? RFC 6520 States:

The Heartbeat protocol is a new protocol working at the top of the recording
Layer.

How can an attacker insert a Heartbeat request to take advantage of the OpenSSL bug causing Heartbleed vulnerability?