Google for the exact phrase (and no, quotation marks don’t help)

Simple question. How can I google for the exact phrase match?

Making a simple google of this, it says “use quotation marks”.

Well I did that just now. I searched for this: "accuracy map" and I get a lot of results for map accuracy which is not what I am looking for.

Is there a way to google for the exact phrase with the exact order?

plotting – Why does Mathematica import data with quotation?

I am importing data from ParallelTable as dat file and then export it again for visualization. However, the exported data contains a quotation " " and can not use ListPlot, here is an example

Y=ParallelTable[{x},{x,-20,20,2}]//AbsoluteTiming;
Export["...\Hello3.dat",Y];
data=Import["...\Hello3.dat"];   

the imported data has this form

{{0.0326645}, {"{-20}", "{-18}", "{-16}", "{-14}", "{-12}", "{-10}", 
  "{-8}", "{-6}", "{-4}", "{-2}", "{0}", "{2}", "{4}", "{6}", "{8}", 
  "{10}", "{12}", "{14}", "{16}", "{18}", "{20}"}}   

If I use ListPlot[data[[2]]] it does not give output. So how can I avoid these quotations from the beginning with keeping AbsoluteTiming?

How to change third column of a variable so it is encased with single quotation marks using AWK or SED

I have a variable $out:

out=1,2,3,4,5

I want to change the third column so the value gets single quotation marks as in (I talk of columns here as $out represents the values of an insert statement for a database entry):

out=1,2,'3',4,5

Does anyone know how this could be done using awk or sed?

SQL Server – How to get the query result separated by quotation marks and commas in SQL

Hello everyone, I have the following request:

SET @NotesByTherapy = (Select NotesIDs from MdNotesByTherapy Where TherapyCode = 'ADM') 

It makes me:

433603037646,142

I would like him to come back this way:

'433603037646','142'

That is, with the quotes someone knows how to do this in SQL

Quotation marks in quotation marks

I have a list of words that I am looking for in CSV. I want to save all the lines that contain Said rope in a file called Said rope but i have problems with the ""

data = open(""list(x)".csv","w+")

x is an index in the list

postgresql – How to display string values ​​in single quotation marks?

I'm trying to convert the values ​​stored in a JSON into a string representation.

the #>> The operator works for this purpose for numbers, for example:

SELECT '{"a":(1,2,3),"b":("4","5","6")}'::json#>>'{a,2}';

given

 ?column? 
------
 3
(1 row)

But for string values, textual representation (6 in the example below) does not have single quotation marks, so that we can not say that the stored value was a string:

SELECT '{"a":(1,2,3),"b":("4","5","6")}'::json#>>'{b,2}';
 ?column? 
----------
 6
(1 row)

How to use a function or expression to leave the PostgreSQL output '6' instead of 6 in the second example above (and exit 3 in the first example)?

(This is with PostgreSQL 12)

In a Windows command file, how to FOR / F with a command having multiple strings in quotation marks

The following command works well:

"C:Program Files (x86)KeePass Password Safe 2KPScript.exe" -c:GetEntryString "C:UsersMeDocumentsKeePass Database.kdbx" -useraccount -field:Password -ref-Title:"Data Partition" -FailIfNotExists -FailIfNoEntry

It returns a password on a KeePass database. In a batch file, I want to put the result of it in a variable in order to be able to transmit it to another program.

I have tried the following in a batch file:

@ECHO OFF
SETLOCAL EnableDelayedExpansion
FOR /F "tokens=* usebackq" %%F IN (`"C:Program Files (x86)KeePass Password Safe 2KPScript.exe" -c:GetEntryString "C:UsersMeDocumentsKeePass Database.kdbx" -useraccount -field:Password -ref-Title:"Data Partition" -FailIfNotExists -FailIfNoEntry`) DO SET pw=%%F
ECHO %pw%
ENDLOCAL

But calling this command file returns:

& # 39; C: Program & # 39; It is not recognized as an internal or external command, a usable program or a batch file.

I've tried putting quotation marks around the command in FOR:

@ECHO OFF
SETLOCAL EnableDelayedExpansion
FOR /F "tokens=* usebackq" %%F IN (`""C:Program Files (x86)KeePass Password Safe 2KPScript.exe" -c:GetEntryString "C:UsersMeDocumentsKeePass Database.kdbx" -useraccount -field:Password -ref-Title:"Data Partition" -FailIfNotExists -FailIfNoEntry"`) DO SET pw=%%F
ECHO %pw%
ENDLOCAL

And this time I had:

KeePass was unexpected at that time.

What is the correct syntax for this to work? Thank you.

conversion – How to convert an expression into a string while keeping the quotation marks of the strings that are part of the expression?

ToString[{"a", "b"}, InputForm]
(*    "{"a B"}"    *)

(thanks @kglr for golf!)

If you need to get rid of the space between the chains in the chain (according to your specifications), use a StringDelete[" "] operator:

ToString[{"a", "b"}, InputForm] // StringDelete[" "]
(*    "{"a B"}"    *)

18.04 – Ubuntu network manager swanstrong VPN – how to enter a double quotation mark in the pre-shared key?

I have two strongswan VPNs (or l2tp / ipsec) and I can not connect to the second one that uses a pre-shared key that contains quotation marks, that is to say. "

I can connect to the first without a double quote in the pre-shared key. When I intentionally change the pre-shared key to an erroneous key, the output in syslog describing the error is very similar to the output of the second VPN connection attempt.

So, I think I have to escape the double quote in the pre-shared key to make it work, but it did not help:

An idea?

I'm using Ubuntu 18.04 Bionic Beaver

Attack xss on a value field ignoring the quotation marks

Consider a website that handles the search query like this:


if i try to inject this script, it does not work …

"onerror =" alert (0)

This is probably because the website codes the double quote as & quot. I even tried double coding by coding the double quotation mark % 2522but the website seems to make this as "% 22 onerror% 22alert (0)" and for whatever reason, the % 22 is no longer decoded

Is there a way around this?