## Error syntax error, & # 39; \$ result & # 39; unexpected (T_VARIABLE)

Hello, I hope you can help me by clicking on the connection I get this error Error syntax error, & # 39; \$ result & # 39; unexpected (T_VARIABLE)

## magento2 – Get getTotalsAction result data

I have tried to update the basket using JS and the summary container is updating correctly. But I want to update the quantity of the item. So basically i added a custom button in `checkout/cart` page. When this button is clicked, I add a product to the cart. Now this product is fixed and the amount added per click is fixed. Now everything is working fine, including the summary container. But I want to update the Quantity field in the form container. But I don't know how to do this.

I discovered that `getTotalsAction` contains the total I want but I don't know how to get this result. I'm thinking of going through the result to update the value of the quantity. How can I do this?

Note: I do not wish to refresh the page.

Here is my code

``````define((
'jquery',
'Magento_Checkout/js/action/get-totals',
'Magento_Checkout/js/model/cart/cache',
'Magento_Checkout/js/model/cart/totals-processor/default',
'Magento_Checkout/js/model/quote',
'Magento_Customer/js/customer-data',
'jquery/ui'
), function (\$, getTotalsAction, cartCache, totalsProcessor, quote, customerData) {
'use strict';

\$.widget('mage.poundToCart', {
_create: function () {
},
formData = new FormData(form(0));
\$.ajax({
url: form.attr('action'),
data: formData,
type: 'post',
dataType: 'json',
cache: false,
contentType: false,
processData: false,
success: function (res) {
var deferred = \$.Deferred();
getTotalsAction((), deferred); // <--- I want to retrieve this value
return false;
}
});
}
});
``````

How can I do this?

I have tried this link but this does not apply in my situation as there is no validation response that I get. So, I just want to refresh the cart form page like the picture below

So basically I want to update the quantity field since adding the product is done via Ajax

## magento2 – Result of the action of the administration menu of Magento 2 Invalid security key or form. Please refresh the page. on click

Forgive me for my question. Still new with magento 2.

So I managed to add a new admin menu. But the problem is that every time I click on the admin menu button, I receive an invalid security or form key. Please refresh the page.

Here are some of my codes.

This is my menu.xml

``````
``````

And here are my directories.

## dnd 5th – When using the Augury spell, how good or bad must the course result be to warrant a Weal / Woe response?

My players are considering using Augury to decide whether to enter a dungeon, and I'm trying to decide what the outcome of the spell should be.

I can see that some extremes should be obvious: for example, if the dungeon contains four ancient dragons that will wipe them out, that’s Woe. If the dungeon contains a platinum stack and no danger, it's Weal.
But what if it is a "typical" dungeon with monsters and traps but also a treasure? Does this count as Weal, Woe, Weal and Woe, or neither? And if, again, as is often the case, there is first a danger before there is a treasure? What happens if there is a difficult puzzle that could make them leave after having suffered damage but before finding a treasure?

If it makes a difference, what I think it could be, I would like them to explore this dungeon, and I think they have the skills to survive there and find the treasure. I've seen people suggest that Augury is really a way for PCs to communicate with the DM, and if it is, I would be tempted to say Weal, as code for “ yes , please, do it & # 39; & # 39 ;. But I don't want them to feel betrayed when they are injured (non-lethally).

As noted in the comments, Augury only covers events for the next 30 minutes. I would be interested in answers for the following two situations:

1) It is a very short dungeon which can be cleaned in less than thirty minutes; or

2) Players only ask if they should enter the first room in the dungeon – I think that exacerbates the problem as it is even less clear whether it will be good or bad.

## real analysis – The inverse of a Poincaré result on regular limit points

Let $$V$$ be a delimited open set $$mathbb {R} ^ n$$ with $$n> 1$$. According to a well-known result due to Poincaré, if $$x$$ is a point in the border $$partial V$$ and there is a ball $$B$$ such as $$x in partial B$$ and $$B cap V = emptyset$$, then $$x$$ is a regular point for the Dirichlet problem.

Is there a reciprocal for this result? More generally, on what condition (s) can we say that if $$x in partial V$$, there is a ball $$B$$ such as $$x in partial B$$ and
$$B cap V = emptyset$$?

## maximum result – Forex Training

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## how to make sure that vulnerability management doesn't result in reduced security compromised

Take your example Node.js. You are using a version of with a known vulnerability. Therefore, you have two options:

1. Stay on the version you know is vulnerable
2. Upgrade to a version that may to be vulnerable.

The only correct choice is # 2. Is it possible that you are upgrading to a version that also has vulnerabilities? Absolutely! In fact, this is probably the case, since there is rarely any software without bugs.

However, the potential presence of unknown vulnerabilities is a misstep here. When you know there is a vulnerability (especially when the vulnerability is known to the public), it is important to correct it. Obviously, you don't want to release a half-baked patch, but staying on a known vulnerable version just because you're afraid the upgrade will have its own vulnerabilities is definitely a bad idea.

## angular6 – Get the result of subscribing to an observable http, before the rest of the code. Angular 6

I'm doing angular development work, it turns out that I need to initialize certain variables with the results of a subscription, but that gets the result when the rest is already executed. How can I make the code wait until the subscriber receives the response from the server?

``````this.solicitudesArrendamiento2Service.retomarSolicitudArrendamiento(formConsultaSolicitudArrendamientoPN('codigo_form'),
.pipe(finalize(() => {
}))
.subscribe(
data => {
this.solicitudArrendamiento = data(0);

if (this.solicitudArrendamiento.dias_registro_solicitud > 30 || this.fecha_caducidad < new Date()) {
} else {
if (data.length === 0) {
this.modalErrorConsultaCodigoForm = true;
} else {
this.solicitudesArrendamiento2Service.setUserData(data);
this.router.navigate(('solicitudes_arrendamiento/actualizar_solicitud' + this.solicitudArrendamiento.tipo_solicitante),
{
queryParams: {
tipo_persona: this.solicitudArrendamiento.tipo_persona,
valor_canon: this.solicitudArrendamiento.Valor_Canon
}
});
}
}
},
error => {
log.error(`Consulta SA get error: \${error.message}`);
}
);
``````

Service with the function that requests the server

``````retomarSolicitudArrendamiento(codigo_formulario: string, nro_identificacion: string): Observable {
return this.httpClient.get(`\${routes.base}get/\${codigo_formulario}/\${nro_identificacion}/`);
}
``````

Thanks for the help you can give me.

## Link the result without content in copyscape using wordpress

I have a problem in my wordpress site that when i try to add a new page and publish it even without content when i check it in copyscape, it has a duplicate result. The result is http://www.cptcode.se/applying-for-a-license.html here is the resulting link. I don't know how to delete or where the code resides. No matter which pages I add or on my previous page, they always arrive in the results in copyscape. This gives me a problem for my pages. Thanks for your advices.

## algorithms – If I have an STD and add an edge to create a cycle, will removing the heaviest edge from that cycle result in an STD?

Let's say I have an STD, $$T$$. I take an edge not in it $$T$$ and change its weight, and add it to $$T$$ to create a cycle. Will removing the heaviest edge from this cycle cause an STD?

MST stands for minimum tree covering a graph. I came across these two posts:

and I'm both up just in case $$w_ {old}> w$$ and $$e notin T$$. They both say that removing the heaviest edge will guarantee an STD, but I don't see how to prove it. The cycle property simply indicates that IF you have an STD, it cannot have an edge which is the heaviest edge of a cycle of the original graph $$G$$; this does NOT mean that IF you have a tree which does not contain an edge which happens to be the heaviest edge of a cycle in the original graph $$G$$, you are an STD.

To make the question more explicit in relation to the problem she was trying to solve, I will copy part of the first link:

If its weight has been reduced, add it to the original STD. This will create a cycle. Scan the cycle, looking for the heaviest edge (this could select the original edge again). Remove this edge.

I don't understand why this guarantees that we find an STD. Sure, we get a spanning tree, but why does removing this heavier edge result in a MINIMUM spanning tree?