Error syntax error, & # 39; $ result & # 39; unexpected (T_VARIABLE)

enter description of image hereHello, I hope you can help me by clicking on the connection I get this error Error syntax error, & # 39; $ result & # 39; unexpected (T_VARIABLE)
enter description of image here

magento2 – Get getTotalsAction result data

I have tried to update the basket using JS and the summary container is updating correctly. But I want to update the quantity of the item. So basically i added a custom button in checkout/cart page. When this button is clicked, I add a product to the cart. Now this product is fixed and the amount added per click is fixed. Now everything is working fine, including the summary container. But I want to update the Quantity field in the form container. But I don't know how to do this.

I discovered that getTotalsAction contains the total I want but I don't know how to get this result. I'm thinking of going through the result to update the value of the quantity. How can I do this?

Note: I do not wish to refresh the page.

Here is my code

define((
    'jquery',
    'Magento_Checkout/js/action/get-totals',
    'Magento_Checkout/js/model/cart/cache',
    'Magento_Checkout/js/model/cart/totals-processor/default',
    'Magento_Checkout/js/model/quote',
    'Magento_Customer/js/customer-data',
    'jquery/ui'    
), function ($, getTotalsAction, cartCache, totalsProcessor, quote, customerData) {
'use strict';

 $.widget('mage.poundToCart', {
     _create: function () {          
       this.processAddCart();       
    },
    processAddCart: function(form) {
        formData = new FormData(form(0));
        $.ajax({
            url: form.attr('action'),
            data: formData,
            type: 'post',
            dataType: 'json',
            cache: false,
            contentType: false,
            processData: false,
            success: function (res) {  
              var deferred = $.Deferred();
              getTotalsAction((), deferred); // <--- I want to retrieve this value
              return false;
            }
       });
    }
 });

How can I do this?

I have tried this link but this does not apply in my situation as there is no validation response that I get. So, I just want to refresh the cart form page like the picture below

enter description of image here

So basically I want to update the quantity field since adding the product is done via Ajax

magento2 – Result of the action of the administration menu of Magento 2 Invalid security key or form. Please refresh the page. on click

Forgive me for my question. Still new with magento 2.

So I managed to add a new admin menu. But the problem is that every time I click on the admin menu button, I receive an invalid security or form key. Please refresh the page.

Here are some of my codes.

This is my menu.xml

     

And here are my directories.

enter description of image here

enter description of image here

dnd 5th – When using the Augury spell, how good or bad must the course result be to warrant a Weal / Woe response?

My players are considering using Augury to decide whether to enter a dungeon, and I'm trying to decide what the outcome of the spell should be.

I can see that some extremes should be obvious: for example, if the dungeon contains four ancient dragons that will wipe them out, that’s Woe. If the dungeon contains a platinum stack and no danger, it's Weal.
But what if it is a "typical" dungeon with monsters and traps but also a treasure? Does this count as Weal, Woe, Weal and Woe, or neither? And if, again, as is often the case, there is first a danger before there is a treasure? What happens if there is a difficult puzzle that could make them leave after having suffered damage but before finding a treasure?

If it makes a difference, what I think it could be, I would like them to explore this dungeon, and I think they have the skills to survive there and find the treasure. I've seen people suggest that Augury is really a way for PCs to communicate with the DM, and if it is, I would be tempted to say Weal, as code for “ yes , please, do it & # 39; & # 39 ;. But I don't want them to feel betrayed when they are injured (non-lethally).

As noted in the comments, Augury only covers events for the next 30 minutes. I would be interested in answers for the following two situations:

1) It is a very short dungeon which can be cleaned in less than thirty minutes; or

2) Players only ask if they should enter the first room in the dungeon – I think that exacerbates the problem as it is even less clear whether it will be good or bad.

real analysis – The inverse of a Poincaré result on regular limit points

Let $ V $ be a delimited open set $ mathbb {R} ^ n $ with $ n> $ 1. According to a well-known result due to Poincaré, if $ x $ is a point in the border $ partial V $ and there is a ball $ B $ such as $ x in partial B $ and $ B cap V = emptyset $, then $ x $ is a regular point for the Dirichlet problem.

Is there a reciprocal for this result? More generally, on what condition (s) can we say that if $ x in partial V $, there is a ball $ B $ such as $ x in partial B $ and
$ B cap V = emptyset $?

maximum result – Forex Training

TopGold Forum is rapidly becoming the number one online finance destination for the Internet.

We are a leading authority and forum destination for professional investors, forex traders, affiliates and individuals who want to make a living online or make more money.

If this is your first visit, be sure to check out the FAQ by clicking on the link above. You must register before you can post: click on the registration link above to continue.

how to make sure that vulnerability management doesn't result in reduced security compromised

Take your example Node.js. You are using a version of with a known vulnerability. Therefore, you have two options:

  1. Stay on the version you know is vulnerable
  2. Upgrade to a version that may to be vulnerable.

The only correct choice is # 2. Is it possible that you are upgrading to a version that also has vulnerabilities? Absolutely! In fact, this is probably the case, since there is rarely any software without bugs.

However, the potential presence of unknown vulnerabilities is a misstep here. When you know there is a vulnerability (especially when the vulnerability is known to the public), it is important to correct it. Obviously, you don't want to release a half-baked patch, but staying on a known vulnerable version just because you're afraid the upgrade will have its own vulnerabilities is definitely a bad idea.

angular6 – Get the result of subscribing to an observable http, before the rest of the code. Angular 6

I'm doing angular development work, it turns out that I need to initialize certain variables with the results of a subscription, but that gets the result when the rest is already executed. How can I make the code wait until the subscriber receives the response from the server?

this.solicitudesArrendamiento2Service.retomarSolicitudArrendamiento(formConsultaSolicitudArrendamientoPN('codigo_form'),
    this.maskUtilsService.unmaskNumber(formConsultaSolicitudArrendamientoPN('identificacion_arrendatario')))
    .pipe(finalize(() => {
      this.isLoading = false;
    }))
    .subscribe(
      data => {
        this.solicitudArrendamiento = data(0);

        this.fecha_caducidad = new Date(this.solicitudArrendamiento.fecha_caducidad);
        if (this.solicitudArrendamiento.dias_registro_solicitud > 30 || this.fecha_caducidad < new Date()) {
          this.modalSaCaducada = true;
        } else {
          if (data.length === 0) {
            this.modalErrorConsultaCodigoForm = true;
          } else {
            this.solicitudesArrendamiento2Service.setUserData(data);
            this.router.navigate(('solicitudes_arrendamiento/actualizar_solicitud' + this.solicitudArrendamiento.tipo_solicitante),
              {
                queryParams: {
                  tipo_persona: this.solicitudArrendamiento.tipo_persona,
                  valor_canon: this.solicitudArrendamiento.Valor_Canon
                }
              });
          }
        }
      },
      error => {
        this.modalDataConsultadaNoExiste = true;
        log.error(`Consulta SA get error: ${error.message}`);
      }
    );

Service with the function that requests the server

retomarSolicitudArrendamiento(codigo_formulario: string, nro_identificacion: string): Observable {
    return this.httpClient.get(`${routes.base}get/${codigo_formulario}/${nro_identificacion}/`);
}

Thanks for the help you can give me.

Link the result without content in copyscape using wordpress

I have a problem in my wordpress site that when i try to add a new page and publish it even without content when i check it in copyscape, it has a duplicate result. The result is http://www.cptcode.se/applying-for-a-license.html here is the resulting link. I don't know how to delete or where the code resides. No matter which pages I add or on my previous page, they always arrive in the results in copyscape. This gives me a problem for my pages. Thanks for your advices.

algorithms – If I have an STD and add an edge to create a cycle, will removing the heaviest edge from that cycle result in an STD?

Let's say I have an STD, $ T $. I take an edge not in it $ T $ and change its weight, and add it to $ T $ to create a cycle. Will removing the heaviest edge from this cycle cause an STD?

MST stands for minimum tree covering a graph. I came across these two posts:

and I'm both up just in case $ w_ {old}> w $ and $ e notin T $. They both say that removing the heaviest edge will guarantee an STD, but I don't see how to prove it. The cycle property simply indicates that IF you have an STD, it cannot have an edge which is the heaviest edge of a cycle of the original graph $ G $; this does NOT mean that IF you have a tree which does not contain an edge which happens to be the heaviest edge of a cycle in the original graph $ G $, you are an STD.

To make the question more explicit in relation to the problem she was trying to solve, I will copy part of the first link:

If its weight has been reduced, add it to the original STD. This will create a cycle. Scan the cycle, looking for the heaviest edge (this could select the original edge again). Remove this edge.

I don't understand why this guarantees that we find an STD. Sure, we get a spanning tree, but why does removing this heavier edge result in a MINIMUM spanning tree?