Mockingbird c++ mocking framework – Code Review Stack Exchange

I have developed Mockingbird a mocking framework for c++, it depends on function injection, and here is an example on how it works:

Assume you have the following class Foo and you need to mock:

struct MyStruct{
    int x, y;
};

class Foo{
public:
    virtual const MyStruct CreateMyStruct(int x, int y) { return MyStruct{ x,y }; }
}; 

Then you write a testing fixture only once for the whole project:

const MyStruct CreateMyStructDummy(int x, int y) { return MyStruct{0,0}; }

START_MOCK(FooMock, Foo)
FUNCTION(CreateMyStruct, const MyStruct, (int x, int y), &CreateMyStructDummy, x, y)
END_MOCK(FooMock)

Then in the tests you write the desired substitute for example:

const MyStruct CreateMyStructSubstitute(int x, int y) { return MyStruct{ x + 10, y + 10 }; }

and inject it like:

FooMock fooMock;
fooMock.InjectCreateMyStruct(CreateMyStructSubstitute); // Mocking function injection.
auto created = fooMock.CreateMyStruct(5,5);
EXPECT_EQ(created.x, 15);
EXPECT_EQ(created.y, 15);

The code is in the file Mockingbird.hpp and totally depends on macros, it is short and straightforward, I ask for reviewing the code on github here, thanks.

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java – Modulo Algorithm – Code Review Stack Exchange

I want this function to find the closest value to n such that 32 % n = 0 in Java. I’m trying to make this more efficient / functional. Here is what I have tried, but I’m sure their is a better way. I’m using Java 8

Question: Is their a better way to implement this function that is more efficient?

private static double nearestMod(double n) {
        // Check if n already satisfies the condition
        if (32 % n == 0) {
            return n;
        }
        
        // Check if the solution can't be reasonably obtained
        if (n > 32) {
            return -1;
        }
        
        double increment;
        
        int numsAfterDecimalPoint = String.valueOf(n).split("\.")(1).length();
        
        if (n % 1 == 0) {
            // If n is a whole number
            increment = 10;
        } else {
            increment = 1d / Math.pow(10, numsAfterDecimalPoint - 1);
        }

        double result = Double.MAX_VALUE;
        
        double multiplier = increment == 10 ? 1 : Math.pow(10, numsAfterDecimalPoint);
        
        for (double i = n - increment * multiplier; i < n + increment * multiplier; i += increment / 10d) {
            double check = 32 / i;
            
            if (Math.abs(Math.round(check) - check) < increment / 10d && Math.abs(i - n) < Math.abs(result - n)) {
                result = i;
            }
        }

        return result;
    }

Example: nearestMod(0.26) should return 0.25