## google sheets – How do I transform raw time series data to a form that would suit a time series chart with lines named for values in the data itself?

Since your ultimate goal is to make a chart, you may want to pivot the data so that each fruit is in its own column.

Assuming the data is in `Sheet1!A2:B`, choose Insert > New sheet and enter this array formula in cell `A2` of the new sheet:

``````=query(
Sheet1!A2:C,
"select A, max(C)
where A is not null
group by A
pivot B",
0
)
``````

Then create a chart based on the data in the new sheet.

If you really need to expand the data so that every date and fruit has a value, and that value is zero when no value appears in the source data, insert yet another sheet and enter this array formula in cell `A2` of the new sheet:

`=arrayformula( query( split( flatten( unique(trim(Sheet1!A2:A)) & "µ" & transpose(unique(Sheet1!B2:B)) ), "µ" ), "where Col1 is not null and Col2 is not null", 0 ) )`

…and this formula in cell `C2`:

`=arrayformula( iferror( vlookup(A2:A & B2:B, { Sheet1!A2:A & Sheet1!B2:B, Sheet1!C2:C }, 2, false), if(Sheet1!A2:A, 0, iferror(1/0)) ) )`

## GAN LSTM Time Series

Does anyone know if it is possible to use LSTM or another RNN in GAN architecture as the generator? Here a reference: 1

Thx!

## polylogarithm – The rate of convergence of the reminder of the power series for the Polylog function

Let $$0 be a positive real number strictly smaller than one and $$q>0$$ be a positive real number. Consider the series
$$mathsf{Li}_{-q}(p) = sum_{ell=1}^{+infty}ell^{q}p^{ell}$$
which defines the polylogarithmic function. Is there any result on the rate at which the reminder
$$c_n=sum_{ell=n}^{+infty}ell^{q}p^{ell}$$
goes to zero? My guess is $$c_n=O(n^q,p^n)$$, but I cannot find anything on this topic.

## sequences and series – Closed form of \$sum_{z=1}^{infty}dfrac{z^n}{text{exp}(kz^m) – 1}\$

Recently while working on some problems, I came across this beautiful infinite series:

$$sum_{z=1}^{infty}dfrac{z^n}{text{exp}(kz^m) – 1}$$

where $$m,n in mathbb{N}$$. Does there exist a closed form for this infinite series? What happens if $$m = n$$? Can we find a closed form when $$m = 2, n = 4?$$ or when $$m = 5, n=6$$? What would be a general approach? Any idea? I’ve been working on this infinite series from quite some time.

Any help would be appreciated. Thanks.

## [Open-source CMS] Website for streaming Movies and TV Series | NewProxyLists

Hi friends, there is a working instruction on how to make money streaming movies and TV shows. As you know, all video hosting services pay money for views. There are many ways to create a WordPress streaming site, but here’s an alternative way. If everything is set up, then there will be almost complete automation, you just have to monitor the release of new films / TV series episodes and upload them via torrent to your accounts on video hosting.
The engine is on GitHub, the code is all open and completely free, you can make your commits and support the author with an asterisk.

If you want to visually watch the training video, then go to YouTube, but the video is in Russian, turn on subtitles and translate them into English.

I managed to understand everything from the subtitles, so in this one I will give you a transcript of this instruction in English.

Register the domain name of the site (any domain registrar);
Buy a Debian or Ubuntu VPS server, RAM > 2GB (any hosting);

Now connect via ssh to the server and install the streaming portal engine to the registered domain. Installation is very simple, you only need to fill in a few fields.

By default, about 1 thousand films from TMDb will be immediately added to the site. You can do even more, you just need to remove the page limitation in the section with the list of films and restart the parsing of the TMDb API. After the end, the number of films and TV series on the site became about 20 thousand. By default, a directory with films and series is created, since it will contain only trailers of films and series.
But nothing prohibits starting uploading movies and series to video hosting, the engine will automatically pick them up via API and add them to the site.

I went to a torrent tracker and downloaded the latest episode of the series. Then he started uploading the series through a browser to four video hosting sites. In my city, the Internet is very bad, so downloading one episode at a time is long and painful. But just to take a screenshot, I started uploading the file to all video hosting services through the browser.

Could you please tell me what other video hosting services are there that have an API and FTP upload is available?

After successfully uploading the video file, I added an API line to the top of the list in the admin panel. These are the lines you must add, first replace them with your own API keys:

Code:

``````# --------------- DOODSTREAM (INFO) ---------------

1 ~ https://doodapi.com/api/folder/list?key=DOOD_KEY ~ result.folders.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ movie_results.0.title <> title_en! <> 1 ~ movie_results.0.poster_path <> poster <> 1 ~ movie_results.0.id <> custom.tmdb_id <> 1 ~ "movie" <> type

1 ~ https://doodapi.com/api/folder/list?key=DOOD_KEY ~ result.folders.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ tv_results.0.name <> title_en! <> 1 ~ tv_results.0.poster_path <> poster <> 1 ~ tv_results.0.id <> custom.tmdb_id <> 1 ~ "tv" <> type

# --------------- NINJASTREAM (INFO) ---------------

1 ~ POST>https://api.ninjastream.to/api/folder/get?apiId=NINJA_ID&apiSecretId=NINJA_SECRET ~ result.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ movie_results.0.title <> title_en! <> 1 ~ movie_results.0.poster_path <> poster <> 1 ~ movie_results.0.id <> custom.tmdb_id <> 1 ~ "movie" <> type

1 ~ POST>https://api.ninjastream.to/api/folder/get?apiId=NINJA_ID&apiSecretId=NINJA_SECRET ~ result.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ tv_results.0.name <> title_en! <> 1 ~ tv_results.0.poster_path <> poster <> 1 ~ tv_results.0.id <> custom.tmdb_id <> 1 ~ "tv" <> type

# --------------- STREAMSB (INFO) ---------------

1 ~ https://streamsb.com/api/folder/list?key=STREAMSB_KEY ~ result.folders.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ movie_results.0.title <> title_en! <> 1 ~ movie_results.0.poster_path <> poster <> 1 ~ movie_results.0.id <> custom.tmdb_id <> 1 ~ "movie" <> type

1 ~ https://streamsb.com/api/folder/list?key=STREAMSB_KEY ~ result.folders.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ tv_results.0.name <> title_en! <> 1 ~ tv_results.0.poster_path <> poster <> 1 ~ tv_results.0.id <> custom.tmdb_id <> 1 ~ "tv" <> type

# --------------- STREAMTAPE (INFO) ---------------

1 ~ https://api.streamtape.com/file/listfolder?login=STREAMTAPE_KEY&key=brqG3jwO4KixkB ~ result.folders.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ movie_results.0.title <> title_en! <> 1 ~ movie_results.0.poster_path <> poster <> 1 ~ movie_results.0.id <> custom.tmdb_id <> 1 ~ "movie" <> type

1 ~ https://api.streamtape.com/file/listfolder?login=STREAMTAPE_KEY&key=brqG3jwO4KixkB ~ result.folders.0.name <> custom.imdb_id ~ https://api.themoviedb.org/3/find/(imdb_id)?language=en&external_source=imdb_id&api_key=9e43f45f94705cc8e1d5a0400d19a7b7 ~ tv_results.0.name <> title_en! <> 1 ~ tv_results.0.poster_path <> poster <> 1 ~ tv_results.0.id <> custom.tmdb_id <> 1 ~ "tv" <> type

# --------------- DOODSTREAM ---------------

1 ~ https://doodapi.com/api/folder/list?key=DOOD_KEY ~ result.files ~ (url) <> result.folders <> fld_id <> "https://doodapi.com/api/file/list?key=DOOD_KEY&fld_id=_VALUE_" ~ file_code <> custom.player1 <> <> <> "DOODSTREAM https://dood.to/e/_VALUE_" ~ title <> custom.season ~ title <> custom.episode ~ additional_info.name <> custom.imdb_id

# --------------- NINJASTREAM ---------------

1 ~ POST>https://api.ninjastream.to/api/folder/get?apiId=NINJA_ID&apiSecretId=NINJA_SECRET ~ result.data ~ (url) <> result <> id <> "POST>https://api.ninjastream.to/api/file/get?apiId=NINJA_ID&apiSecretId=NINJA_SECRET&folder=_VALUE_" ~ hashid <> custom.player2 <> <> <> "NINJASTREAM https://ninjastream.to/watch/_VALUE_" ~ name <> custom.season ~ name <> custom.episode ~ additional_info.name <> custom.imdb_id

# --------------- STREAMSB ---------------

1 ~ https://streamsb.com/api/folder/list?key=STREAMSB_KEY ~ result.files ~ (url) <> result.folders <> fld_id <> "https://streamsb.com/api/file/list?key=STREAMSB_KEY&per_page=200&fld_id=_VALUE_" ~ file_code <> custom.player3 <> <> <> "STREAMSB https://sbembed1.com/e/_VALUE_.html" ~ title <> custom.season ~ title <> custom.episode ~ additional_info.name <> custom.imdb_id

# --------------- STREAMTAPE ---------------

1 ~ https://api.streamtape.com/file/listfolder?login=STREAMTAPE_KEY&key=brqG3jwO4KixkB ~ result.files ~ (url) <> result.folders <> id <> "https://api.streamtape.com/file/listfolder?login=STREAMTAPE_KEY&key=brqG3jwO4KixkB&folder=_VALUE_" ~ linkid <> custom.player4 <> <> <> "STREAMTAPE https://streamtape.com/e/_VALUE_" ~ name <> custom.season ~ name <> custom.episode ~ additional_info.name <> custom.imdb_id``````

The episode automatically appeared on my website in the player (the engine checks new episodes by API once an hour).

It is possible to download series for full seasons and send them to several video hosting services from the server at once. Configuration for all FTP video hosting is done over SSH.

1. Bug on ninjastream
I didn’t manage to connect to ninjastream the first time, I don’t know what it’s connected with. Failed to create file system for “CINEMATORRENT1:”: NewFs: failed to make FTP connection to “ftp.ninjastream.to:8025”: 550 Checking password error. Therefore, you need to make the connection a second time for CINEMATORRENT1. Enter the same information as the first time. The second time everyone connected successfully.

2. Bug on streamtape
Also, it was not possible to upload to streamtape, since for some reason the folders there are not created via FTP. Do you know why? If you find the reason for the error, please write to me.

3. Bug on streamsb
And finally, when uploading something to streamsb, sometimes an error appears: Failed to create file system for “CINEMATORRENT3:tt12809988/”: NewFs: failed to make FTP connection to “ftp.streamsb.com:21”: 530 Login incorrect. The data is entered correctly, some series are loading, and some are not, so this is an error on the streamsb side.

After some time (about 1 hour), all episodes of the series automatically appeared on my website in the player.

Successful streaming everyone

PS: Do not create a streaming portal if it is prohibited in your country. I am located in Malaysia and there is no DMCA in this country.

## inner products – Fourier series of sin and cos

Let f ∈ C(−π, π). Show that both the nth Fourier sine and the nth Fourier cosine
coefficient of f go to 0 as n → +∞.

Hello guys. I did some work for proof but i am not sure that am i on the right track. I used Bessel’s inequality and got that ||f||^2 ≥ π(Σ(|an|^2 +|bn|^2)
So if i choose f to be zero, then an and bn must be zero. This is my idea but not sure is it true.

## special functions – Recognizing the type of hypergeometric series based on the dominant terms

I am solving a (infinitely long) differential equation which has the solution
$$y(r)=-frac{c}{5}+frac{l^4c^3}{20r^5}+frac{l^{6}c^5}{16r^9}+mathcal{O}(l^8),$$
where I am not sure about the sign of the last term. Additionally, I know that this solution is a series of the form
$$y(r)=-left(frac{c}{r}right)cdotp_2F_1(d,e;f;z),$$
Where $$_2F_1$$ is a hypergeometric series. My question is: how can I make mathematica find the exact form of the hypergeometric series, based on the first few terms?

## calculus – Is radius of convergence of power series of the function unique?

I have function $$f(x)=frac{1}{3-z}$$ which can be rewritten as
begin{align} frac{1}{1-(z-2)} quad text{or}quad frac{1}{3(1-frac{z}{3})} end{align}
By the $$frac{1}{1-r}=1+r+r^2+…$$ and $$|r|<1$$, their Taylor expansion

$$frac{1}{1-(z-2)}=sum_{n=0}^{infty} (z-2)^n$$ and the radius of convergence $$R=1$$.

$$frac{1}{3(1-frac{z}{3})}=frac{1}{3}sum_{n=0}^{infty}left(frac{z}{3}right)^n$$ and radius of convergence $$R=3$$.

It seems it is not unique. Can we say that ?

Any help appreciated. Thanks in advance.

## Asymptotes of series sums

How to find asymptotics of sums with of the form

$$sumlimits_{k=0}^n frac{n^k}{k!}$$

as $$ntoinfty$$

## sequences and series – Rudin Theorem 3.4(a)

I believe I understand the proof, but I just want to be sure I understand fully what Rudin is saying.

The theorem is:

Suppose $$x_n in mathbb{R}^k$$ and $$x_n = (a_{1,n}, ldots, a_{k,n})$$ Then $${x_n}$$ converges to $$x = (a_1, ldots, a_k)$$ if and only if $$limlimits_{n to infty}$$ if and only if $$limlimits_{n to infty} a_{j,n} = a_j$$ for $$1 leq j leq k$$.

The forward direction is more or less clear, though I have only one small question.. Rudin writes that
$$|a_{j,n} – a_j| leq |x_n -x|.$$
I assume the right side is a vector norm, the right-hand side is the absoltue value of a difference of scalars, because the inequality comes from taking the square root of a square. Is that right?

The backward direction is a bit more confusing. Rudin’s proof, replicated verbatim, is:

Conversely, if (2) holds, then to each $$epsilon > 0$$ there corresponds an integer $$N$$ such that $$n geq N$$ implies $$|a_{j,n} – a_j| < frac{epsilon}{sqrt{k}}$$. Hence $$n geq N$$ implies
$$|x_n – x| = left(sumlimits_{j=1}^k |a_{j,n} – a_j|^2 right)^{1/2} < epsilon,$$
so that $$x_n to x$$.

Here is my confusion: I think Rudin has skipped a step. He picks an $$N$$ for only a single $$j$$, but not for each $$j$$. It seems to me that we should, for each $$j$$, pick $$N_j$$ so that $$n geq N_j$$ implies $$|a_{j,n} – a_j| < frac{epsilon}{sqrt{k}}$$ and then set $$N = max(N_1, ldots, N_k)$$. Otherwise, Rudin is in some way bounding the above sum by a single index, which seems peculiar.

Would I be correct that Rudin has actually done what I just suggested, but been silent about it in the write-up?