The new SIM card does not support data traffic in the old iPhone.

I just received a new SIM card that I want to use in an iPhone 4S. The phone reports decent 3G connectivity and can make phone calls, but does not connect to data services. Data services work with older SIM cards from the same operator. In addition, the new SIM card works when it is installed in newer phones (testet on an iPhone SE and an iPhone X).

Thus, out of six possible combinations of phone and SIM card, the only one that does not work is the oldest phone with the most recent SIM card. All SIM cards come from the same carrier and the mobile data network settings are the ones recommended by the operator and identical on all phones, except for the older phone that is a 3G phone, while that the new models support 4G / LTE.

Can the new SIM card be incompatible with older phones? If not, what can be the problem? Carrier support has not been useful so far.

Put the iPhone SIM card in iPad Cellular. I thought the iPad would replace my iPhone?

I am totally confused by cellular iPad.

If I put the iPhone SIM card in an iPad cell, how to make a call, how to receive a call.

I have known iPad wifi + cellular for a long time, I did not think how it worked, only what I thought I had to work, until I bought a cellular iPad, which is totally useless for me.

If I care about iPad WIFI browsing, I can configure the iPhone access point to connect the iPad to the Internet.

Why should I buy an iPad cell phone? Cellular iPad can only do data, if I put my SIM card in iPad …. so how to call ???

1) The iPad can not dial / receive call.

2) Even if, in a way, configure it (iPad can receive calls and dial a number, it seems complicated). iPhone, what's the point of my iPhone without a SIM card?

Conditional distribution of $ X sim mathbb {R} ^ 2 sim mathcal {N} (1, Sigma) $ since $ | X | = a $

I have a random variable $ X sim mathbb {R} ^ 2 $ with global distribution $ X sim mathcal {N} (1, Sigma) $. I wish I could specify the conditional distribution of $ | X | $ given that $ | X | = a $. How would we do that?

My thought is that $[X | |X| = a]$ could be specified as a "normal wrapped" distribution. But I do not know how to specify the parameters.

I have changed SIM card abroad and changed number by mistake. Can I go back to my old number in WhatsApp?

Arriving from the United States in Ireland, I received a new SIM card with an Irish phone number. At the prompt, I said yes to change my number in WhatsApp, but now no one from my home can text me. Can I just use the Change my number link in WhatsApp to restore it even if the SIM card is an Irish number?

cell phones – Buy a SIM card for China abroad?

A group of German tourists traveling to China are looking for options to have a SIM card with a data plan during their stay.

Their own experience of previous trips, as well as some publications here (for example, this one or this one) indicate that it can be difficult to obtain one without a Chinese identity card. As they will travel in a group, they can not spend much time browsing the respective cities of their stay to find "main offices".

There seems to be some options for SIM cards that can be ordered before the trip, even in Europe, like this one or this one. These providers advertise fairly large data packets (in the order of 1 GB).

Are these offers reliable?

I wonder, because they also announce the absence of Chinese censorship on the Internet, which can not please much the Chinese government. Therefore, I am afraid that the purchase of such a card leaves no service to tourists during the trip, as the Chinese authorities could "unplug" at any time such a service provider.

SIM cards – Keep my phone calls secret

I travel to Canada and I do not want to use my company's phone for private calls, but I want to have a second phone to minimize costs. I have therefore bought a SIM card and it works well. Will my employer still be able to see SMS and record my phone calls? I want to avoid that.

The factory reset of HTC Onem9 caused the blocking of the direct SIM card

I'm a little lost with that right now, I did it originally because my phone did not recognize music downloads on the music app. I did not have an original SIM card if it mattered. Any help is greatly appreciated.

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phone – Samsung Galaxy S7- If I empty the battery and remove it from the SIM card, can I locate its location?

I have 2 questions regarding my Samsung Galaxy S7-

Q1) If I empty the battery in an exhausted manner and remove the SIM card, can I locate its location? I'm talking about a dead battery and not a battery, because you can not remove a Samsung Galaxy S7 battery without special tools.

Q2) Does the Samsung Galaxy S7 have any kind of battery backup that allows the phone to shut down before emptying completely? Or a second battery or a way to track your phone even with a dead battery.

Ex: If your mobile phone is on and you are driving somewhere and you have lost your phone, it should be traceable. But if your battery is dead and you remove the SIM card, if I understand correctly, it can NOT be traced and will only show the last point on which the phone was lit or before the battery is dead … but again, I do not know for sure.


According to some articles, I googled, it is said that this is not possible.

Can you follow a cell phone with a dead battery?
Unfortunately, a phone with a dead battery will not respond to attempts to locate via GPS. Mobile Lookout automatically saves the last known location of your Android phone just before the battery runs out.

general topology – Show that $ widehat {(0,1)} $ is homeomorphic to $[0,1]/ sim $ where $ x sim y iff x = y text {or} {x, y } = {0,1 } $.

$ widehat {(0,1)} = (0,1) cup {p } $, or $ p not in (0,1) $. A set $ U $ in $ widehat {(0,1)} $ is open if ($ U not nor p $ and $ U $ is open in $ (0.1) $) or ($ U ni p $ and $ (0,1) setminus U $ is a compact subset of $ (0.1) $).

CA watch $ widehat {(0,1)} $ is homeomorphic to $[0,1]/ sim $ or $ x sim y ssi x = y text {or} {x, y } = {0,1 } $.

A set of representatives of $[0,1]/ sim = {[x] mid x in[0,1] } $ is $ bigcup_ {x in (0,1)} underbrace {[x]} _ {= {x }} cup underbrace {[0]} _ {=[1]= {0,1 }} $.

Let $ p:[0,1] twoheadrightarrow [0,1]/ sim: x mapsto [x]$ to be the quotient map, so $ U subset[0,1]/ sim $ is open if $ p ^ {- 1} (U) subset [0,1]$ is open.

I have to prove that
$$ begin {align *} f colon[0,1]/ sim & longrightarrow widehat {(0,1)} \ [x]& longmapsto x text {if} x in (0,1) \ [0]=[1]& longmapsto p end {align *} $$

is a homeomorphism.

It is clear that it is a bijection. I have problems to prove that it is continuous.

Let $ U subset widehat {(0,1)} $ open. assume $ p not in U $then $ U $ is open in $ (0.1) $, So $ U = (0,1) cap B $ ($ B $ open in $ mathbf {R} $). then $ f ^ {- 1} (U) $ is open in $[0,1]/ sim $, since $ p ^ {- 1} (f ^ {- 1} (U)) = U $which is open in $[0,1]$, since $ U = underbrace {((0,1) cap B)} _ { text {open in} mathbf {R}} cap [0,1]$.

Now assume $ to U $. then $ (0,1) setminus U $ is a compact subset of $ (0.1) $ (I guess that means by Heine Borel that he's closed $ (0.1) $?) So $ (0,1) setminus U = (0,1) cap C $ ($ C $ shut in $ mathbf {R} $). Now $ (0,1) setminus ((0,1) setminus U) = (0,1) cap underbrace {( mathbf {R} setminus C)} _ { text {open in} mathbf {R}} $. It means that $ p ^ {- 1} (f ^ {- 1} (U)) $ is the union of an open subset of $ (0.1) $ and $ {0,1 } $, which is not open in $[0,1]$.

I think this problem is difficult for me because I do not feel familiar with the topology of the quotient yet. Could someone provide some help or a simpler way to handle this?