c++ – Is there any way to use a single for Loop for this code?

I want to use only one for Loop for this code. Is this possible? If not then how can I optimise my code further?

It works well for the constraint 1 ≤ T ≤ 10, 2 ≤ N ≤ 10^3, 1 ≤ M ≤ 10^5,
but I am getting time limit exceeded for 1 ≤ T ≤ 100, 2 ≤ N ≤ 10^5, 1 ≤ M ≤ 10^5.

#include <iostream>
using namespace std;
#include <vector>
#include <bits/stdc++.h>
#include <iterator>
#include <utility>
#include <boost/multiprecision/cpp_int.hpp>
using boost::multiprecision::cpp_int;

using namespace std;

int main() {
    // your code goes here
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);   

    cpp_int t,ans;
    std::cin >> t;
    while(t-->0) {
    
        cpp_int n;
        std::cin >> n;
        
        cpp_int m;
        std::cin >> m;
        
        cpp_int count=0;
        
        for(int a=1;a<=n;++a) 
            {
                for(int b=1;b<=n;++b)
                {
                    
                    if(a<b) 
                     {
                       if( ((m%a)%b) == ((m%b)%a) )
                           count++;
                     }
            }
            }
            
            cout << count << "n";
    }
    return 0;
}

gui design – Is having multiple links to the same destination from a single GUI a good practice?

gui design – Is having multiple links to the same destination from a single GUI a good practice? – User Experience Stack Exchange

customization – white fonts in white background in single product page

in WP woocommerce with Porto theme, inside the single product page where the categories and the brand are shown, the results are white on a white background and while they exist they do not appear,; no matter how hard I tried I could not change the color to make them appear

enter image description here

sqlite – I want to search record of a single student but I cannot do this with my query

sqlite – I want to search record of a single student but I cannot do this with my query – Android Enthusiasts Stack Exchange

lo.logic – Detecting non-negativity of a single constraint by polyhedral constraints – $II$ (parallel complexity)

Let $$langle a,xrangle=b$$ be a linear constraint where $xinmathbb R^n$ and every entry in $a=(a_1,dots,a_n)$ is in $mathbb Z_{geq0}^{n}$ (non-negative) and the entry $b$ is in $mathbb Z_{geq0}$ (non-negative) and are of $m=poly(n)$ bitlength.

Is there a polyhedron $Byleq c$ (depending on $a,b$) satisfying the properties

  1. $Binmathbb Z^{qtimes(n+1)},cinmathbb Z^{q}$ where $q=poly(n)$
  2. $log_2max_{i,j}|B_{i,j}c_i|=O(n)$
  3. $B,c$ constructible in $O(log n)$ time in $poly(n)$ processors ($NC^1$ complexity)
  4. $exists xinmathbb R_{geq0}^n:langle a,xrangle=biff B(a,b)’leq c$

satisfied?

I think there might be (perhaps every entry of $B,c$ can be computed in $O(log n)$ time).

c++ – How to sort single linked list under two determinants?

Ok, so i got list of some products, which have two atribiutes x and y. I need to sort them ascending by x and if there will be two products with same x then i have to sort products with same x descending by y. Note that elements are already on the list and i need to do sorting repetedly.

For now i have something like this:

void Sort_my_list(Product * &list, int x)  
{
  Product* sorted = 0; 
  while (list != 0) 
  {
    Product* max = list, * before_max = 0; 
    for (Product* p = list, *i = list->next_;                               
      i != 0; 
      p = i, i = i->next_) 
    {
      if (i->get_x(x) > max->get_x(x))
      {
        max = i; 
        before_max = p; 
      }
    }
    if (before_max != 0) 
      before_max->next_ = max->next_; 
    else 
      list = max->next_; 
    max->next_ = sorted; 
    sorted = max; 
  }
  list = sorted; 
}

lo.logic – Detecting non-negativity of a single constraint by polyhedral constraints

Let $langle a,xrangle=b$ be a linear constraint where $xinmathbb R^n$ and every entry in $a=(a_1,dots,a_n)$ and the entry $b$ are of $m=O(log n)$ bitlength and are in $mathbb Z$. Is there an universal polyhedron $Byleq c$ satisying the properties

  1. $Binmathbb Z^{qtimes(n+1)},cinmathbb Z^{q}$ where $q=poly(n)$

  2. $log_2max_{i,j}|B_{i,j}c_i|=poly(n)$

  3. $exists xinmathbb R_{geq0}^n:langle a,xrangle=biff B(a,b)’leq c$?

html – Google Sites – Single Page Website

I am currently trying to implement a single page on google sites but I can’t figure out how to make the menu pointing to specific one page sections. I do think it’s possible since there’s already a working example online.

Ideally I want to make a section eg, Gallery and anchor that onto #gallery via a custom link. Anyone has an idea how I can go about implementing this?

Thanks!

usability – Change in Percentage (Drop or Increase or No change) and it’s details in single column from two column

The real situation is
In a company generally a shareholder increase or decrease their shareholding or at times none (Pledges his shares)

.
enter image description here
.
.
Currently, These details are showing in two different columns.
.
I want to combine these details together and show it in a single column. Also I am showing the number of securities(equity) in a tooltip.

simplifying expressions – How to expand a rational function as a single fraction

This has been annoying me for a long time. I want a rational function to be represented in the form

$$frac{a_nx^n+….a_0x^0}{b_mx^m+….b_0x^0}$$

But this seems to be quite difficult. Mathematica really loves to factor things out. //ExpandAll usually gives me a sum of bunch of rational functions. I just want the numerator to be a straightforward polynomial and the denominator to be a straightforward polynomial.

I can //Together to get a single fraction and //Expand the numerator and denominator separately, and then combine them by hand, but that is very annoying and it feels like there should be a command to do this. The form I wrote above is the most common rational function form, so why would it be so difficult to arrive at?

For example what do I need to do the fraction below to get it to be a polynomial divided by a polynomial?

-2/n^3 + (32 n)/(1 - 8 n^2 + 16 n^4)

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