## encryption – how to invert this code VB

I have a vb file or c # am confused which language anyway here is what we need

from the file as functions (PHP fan: p).

``````StringParser public static object (object d, object p)
{
ASCIIEncoding asciiencoding = new ASCIIEncoding ();
byte[] array = Convert.FromBase64String (Conversions.ToString (d));
array = (byte[]) DecodeStringx.smethod_0 (array, RuntimeHelpers.GetObjectValue (p));
return asciiencoding.GetString (array);
}

private static object smethod_0 (octet[] b, object p)
{
return DecodeStringx.DC_Work (b, (byte[]) DecodeStringx.StrToByteArray (Conversions.ToString (p)));
}

private static object DC_Work (byte[] d, byte[] p)
{
checked
{
new byte[d.Length + 1];
int[] array = new int[257];
int num = 0;
int num2 = 0;
DecodeStringx.DC_Init (p, table of references);
int num3 = d.Length - 1;
for (int i = 0; i <= num3; i ++)
{
num = (num + 1)% 256;
num2 = (num2 + array[num])% 256;
int num4 = table[num];
board[num] = table[num2];
board[num2] = num4;
int value = table[(board[(Array[(tableau[(array[num] + table[num2])% 256];
re[i] ^ = Convert.ToByte (value);
}
return d;
}
}

static void protected DC_Init (octet[] k, ref int[] r)
{
int num = k.Length;
int num2 = 0;
checked
{
make
{
r[num2] = num2;
num2 ++;
}
while (num2 <= 255);
int num3 = 0;
num2 = 0;
make
{
num3 = (num3 + r[num2] + (int) k[num2 % num])% 256;
int num4 = r[num2];
r[num2] = r[num3];
r[num3] = num4;
num2 ++;
}
while (num2 <= 255);
}
}

private static object StrToByteArray (string d)
{
ASCIIEncoding asciiencoding = new ASCIIEncoding ();
return asciiencoding.GetBytes (" 0" + d + " 0");
}
``````

so what i need is to reverse these codes and get a php code that decrypts

scrambled texts an example:

``````Versioned.CallByName (DecodeStringx.string_23, Conversions.ToString (DecodeStringx.StringParser ("t2381U9 / fVs =, xxxxxxx")), CallType.Set,
``````

P.S: I'm in the right place 🙂

## Number Theory – Resolution of \$ (u-x_1) ^ {1/3} + (u-x_2) ^ {1/3} + (u-x_3) ^ {1/3} = {vb} ^ {1 / 3} \$ with elliptic curves

Let $$x_1$$,$$x_2$$,$$x_3$$ to be the roots of cubic $$x ^ 3 + px + q$$ more than $$mathbb Q$$, the idea is that rational solutions $$(u, v)$$ of the equation

$$(u-x_1) ^ {1/3} + (u-x_2) ^ {1/3} + (u-x_3) ^ {1/3} = {vb} ^ {1/3} quad ( 1)$$

actually form a affine plane algebraic curve, which can be constructed as follows. First, consider the variety $$V$$ lying in space $$mathbb A ^ 8 langle u, v, x_1, x_2, x_3, y_1, y_2, y_3 rangle$$ on the function field $$mathbb Q (p, q)$$,
V: left { begin {aligned} & x_1 + x_2 + x_3 = 0, \ & x_1 x_2 + x_2 x_3 + x_1 x_3 = p, \ & x_1 x_2 x_3 = -q, \ & y_1 ^ 3 = u-x_1, \ & y_2 ^ 3 = u-x_2, \ & y_3 ^ 3 = u-x_3, \ & (y_1 + y_2 + y_3) ^ 3 = v. \ end {aligned} right.

Then define our curve $$C$$ like the image of $$V$$ under the map $$f: V to mathbb A ^ 2 langle x, y rangle$$ given by
$$(u, v, x_1, x_2, x_3, y_1, y_2, y_3) mapsto (u, v)$$. We can get an explicit equation for $$C$$ with the help of
Magma calculator:

``````> F: = FunctionField (Rationals (), 2);
> A8: = AffineSpace (F, 8);
> V: = Scheme (A8,[x1+x2+x3, x1*x2+x2*x3+x3*x1-p, x1*x2*x3+q,
> u-x1-y1^3, u-x2-y2^3, u-x3-y3^3, (y1+y2+y3)^3-v])
> A2: = AffineSpace (F, 2);
> f: = mapA2 |[u,v]>;
> C: = image (f); C;
Diagram of Rational Multivariate Rational Function Field 2 on a Rational Field
Defined by
x ^ 7 * y ^ 2 - 1/27 * x ^ 6 * y ^ 3 + 1/9 * x ^ 5 * y ^ 4 + 11/9 * p * x ^ 5 * y ^ 2 - q * x ^ 5 * y - 1/243 * x ^ 4 * y ^ 5
- 13/27 * p * x ^ 4 * y ^ 3 + 11/9 * q * x ^ 4 * y ^ 2 + 2/9 * p ^ 2 * x ^ 4 * y + 1/243 * x ^ 3 * y ^ 6 +
46/243 * p * x ^ 3 * y ^ 4 - 16/27 * q * x ^ 3 * y ^ 3 + 7/27 * p ^ 2 * x ^ 3 * y ^ 2 - 5/9 * p * q * x ^ 3 * y -
1/27 * p ^ 3 * x ^ 3 - 1/6561 * x ^ 2 * y ^ 7 - 10/729 * p * x ^ 2 * y ^ 5 - 8/243 * q * x ^ 2 * y ^ 4 -
73/243 * p ^ 2 * x ^ 2 * y ^ 3 + 26/27 * p * q * x ^ 2 * y ^ 2 + (1/9 * p ^ 3 - 7/9 * q ^ 2) * x ^ 2 * y -
1/9 * p ^ 2 * q * x ^ 2 + 1/19683 * x * y ^ 8 + 35/6561 * p * x * y ^ 6 - 7/729 * q * x * y ^ 5 +
29/243 * p ^ 2 * x * y ^ 4 - 155/243 * p * q * x * y ^ 3 + (-1 / 9 * p ^ 3 + 19/27 * q ^ 2) * x * y ^ 2 +
2/9 * p ^ 2 * q * x * y - 1/9 * p * q ^ 2 * x - 1/531441 * y ^ 9 + 1/6561 * p * y ^ 7 + 53/6561 * q * y ^ 6 -
1/243 * p ^ 2 * y ^ 5 + 20/243 * p * q * y ^ 4 + (1/27 * p ^ 3 - 28/243 * q ^ 2) * y ^ 3 - 1/9 * p ^ 2 * q * y ^ 2
+ 1/9 * p * q ^ 2 * y - 1/27 * q ^ 3
``````

Note that although the map $$f$$ is not invertible, the bijection between the rational solutions of the equation $$(1)$$ and rational points on the curve $$C$$ is obvious:
$$(u, v) longleftrightarrow (x, y)$$.
Moreover, using formulas in
this answer, we can build a rational map (which will be noted by $$varphi$$) of elliptic curve
$$E: e ^ 2 = d ^ 3 + 27p ^ 3 + frac {729} 4q ^ 2$$ at the curve $$C$$:

``````> One: = AffineSpace (F, 2);
> E: = curve (A,[-e^2+d^3+27*p^3+(729/4)*q^2])
> u: = (1/9 * d ^ 6 * e - 27/2 * q * d ^ 6 - p * d ^ 5 * e - 243/2 * p * q * d ^ 5 + (-12 * p ^ 3 -
> 81 * q ^ 2) * d ^ 3 * e + (-1458 * p ^ 3 * q - 19683/2 * q ^ 3) * d ^ 3 + (216 * p ^ 4 +
> 1458 * p * q ^ 2) * d ^ 2 * e + (-2592 * p ^ 6 - 34992 * p ^ 3 * q ^ 2 - 118098 * q ^ 4) * e) / (d ^ 7
> + 9 * p * d ^ 6 + 81 * p ^ 2 * d ^ 5 + (216 * p ^ 3 + 1458 * q ^ 2) * d ^ 4 + (972 * p ^ 4 +
> 6561 * p * q ^ 2) * d ^ 3 + (11664 * p ^ 6 + 157464 * p ^ 3 * q ^ 2 + 531441 * q ^ 4) * d);
> w: = (1/9 * d ^ 6 * e + 27/2 * q * d ^ 6 + 2 * p * d ^ 5 * e + (-12 * p ^ 3 - 81 * q ^ 2) * d ^ 3 * e +
> (1458 * p ^ 3 * q + 19683/2 * q ^ 3) * d ^ 3 + (-432 * p ^ 4 - 2916 * p * q ^ 2) * d ^ 2 * e +
> (-2592 * p ^ 6 - 34992 * p ^ 3 * q ^ 2 - 118098 * q ^ 4) * e) / (d ^ 7
> + 9 * p * d ^ 6 + 81 * p ^ 2 * d ^ 5 + (216 * p ^ 3 + 1458 * q ^ 2) * d ^ 4 + (972 * p ^ 4 +
> 6561 * p * q ^ 2) * d ^ 3 + (11664 * p ^ 6 + 157464 * p ^ 3 * q ^ 2 + 531441 * q ^ 4) * d);
> m: = e * (d ^ 5 + 12 * p * d ^ 4 + 54 * p ^ 2 * d ^ 3 + (108 * p ^ 3 + 729 * q ^ 2) * d ^ 2 +
> (-648 * p ^ 4 - 4374 * p * q ^ 2) * d) +
> 81/2 * q * d ^ 5 + (4374 * p ^ 3 * q + 59049/2 * q ^ 3) * d ^ 2;
> n: = d ^ 6 + 9 * p * d ^ 5 + 81 * p ^ 2 * d ^ 4 +
> (216 * p ^ 3 + 1458 * q ^ 2) * d ^ 3 + (972 * p ^ 4 + 6561 * p * q ^ 2) * d ^ 2 +
## EQU1 ##
> phi: = map C | [u, 3*u+3*m/n-3*w]>;
> time Image (phi) eq C;
true
Time: 66,680
``````

If we choose the point $$P: = (- 3p, frac {27} 2 q)$$ sure $$E$$, we can check that the preimage of the point $$varphi (nP) in C$$ cardinality $$1$$ for everyone $$n in mathbb Z$$ such as $$| n | < 5$$. It therefore seems plausible that the map $$varphi: E to C$$ is a birational isomorphism; from where the questions:

1. Is it possible to find the reverse of the map $$varphi$$?
2. How can we transform the curve $$C$$ in the normal form of Weierstrass without knowing $$E$$ in advance?

## vb.net – Publish an application in VB with database

Well

I create a small program in Visual Basic to access access to the database, in which one can insert, edit, delete, and so on. But when I create the configuration, everything works fine, I can not access the database. Is there a way to create a configuration with the embedded database or must it be hosted on a server?

Thank you

## Nginx proxy cache 404 static files not found (css, js, jpg, png vb)

My proxy server Nginx: 10.90.100.2
My back-end server: 10.90.100.3

my proxy server does not load static files (css, js, woff, png vb.)

My conf

``````

proxy_cache_path / etc / nginx / proxy_cache levels = 1: 2 keys_zone = ferditest: 10m inactive = 60m;
proxy_cache_key "\$ scheme \$ request_method \$ host \$ request_uri";

server {

listen to 80;
listen to 443 ssl;
server_name www.abc.com abc.com;

ssl_certificate /etc/letsencrypt/live/abc.com/fullchain.pem;
ssl_certificate_key /etc/letsencrypt/live/abc.com/privkey.pem;

location ~ * . (jpg | jpeg | png | gif | ico | css | js | pdf | woff | woff2 | pdf) \$ {
expires 30d;
}

#include /etc/nginx/bots.d/ddos.conf;
#include /etc/nginx/bots.d/blockbots.conf;
#include /etc/nginx/bots.d/blacklist-ips.conf;

ssl_ciphers HIGH :! aNULL :! MD5;
ssl_prefer_server_ciphers on;
shared ssl_session_cache: SSL: 1m;
ssl_session_timeout 5m;
ssl_protocols TLSv1 TLSv1.1 TLSv1.2; # do not use SSLv3 because of deadly poodles

the speed of pages on;
pagespeed FileCachePath "/ etc / nginx / ngx_pagespeed /";
pagespeed EnableFilters collapse_whitespace;
pagespeed EnableFilters extend_cache;
pagespeed EnableFilters rewrite_images;

location ~ " .pagespeed .[a-z].)?[a-z]{2} .[^.]{ten}.[^.]+ "{
}
location ~ "^ / pagespeed_static /" {}
location ~ "^ / ngx_pagespeed_beacon \$" {}

location / {

proxy_cache ferditest;

proxy_buffering on;
proxy_cache_valid 200 302 1m;
proxy_cache_valid 404 1m;

wait time error proxy_cache_use_stale invalid_header update http_500 http_502 http_503 http_504;
proxy_cache_lock on;
proxy_cache_use_stale updated;
proxy_bind 0.0.0.0;

proxy_pass http://10.90.100.3;

}
}
```
```

error.log

``````
[error]    23151 # 23151: * 6 open () "/etc/nginx/html/test1/wp-includes/js/wp-embed.min.js" failed (2: no such file or directory), client:
```
```

Thank you

## vb.net – The index was out of reach. It must have a non-negative value and less than the size of the collection. vb

``````Public Sub Form1_Load (sender as object and as EventArgs) handles MyBase.Load

Me.DataGridView1.RowCount = 5

End Sub
``````

I stated in the data grid 4 columns and 5 rows, but when performing this procedure, an error occurred.

``````Public Sub fillDatagrdid (
Me.DataGridView1 (0, 0) .Value = 12345
End Sub
``````

## Kali Linux Install the VB MacBook

I have downloaded the kali-linux-2018.4-amd64.iso file and have run the graphical installation on the virtualbox on my mac.

After installation, I was able to log in and I saw all the tools available, but when I turned off my terminal and I tried to restart the computer, this screen s & # 39; displays.

I am super new on Linux and consider CEH as an alternative to my daily work.

## Help me convert the VB script to Google script

Can any one help me convert the following VB script into Google script.

``````Sub ShowPass ()

UserForm1.Show

End Sub

Under ResetSIG ()
Dim pwd As String

& # 39; Disable application events to avoid issues related to updating the page
Application.EnableEvents = False

& # 39; Get the GIS password
pwd = ActiveWorkbook.Worksheets ("Drops"). Beach ("A17"). Value

& # 39; Reset all tabs to their defaults
Application.Run "Module2.ColHide", pwd

& # 39; And password protects the leaves
Application.Run "module2.ProtectOnly", pwd

& # 39; Move to the Scope tab
ActiveWorkbook.Worksheets (4) .Select

& # 39; Enable application events
Application.EnableEvents = True

End Sub

Under ScopingPWProtect ()

PWPass1.Show

End Sub
``````

``````Sub ShowPass ()

UserForm1.Show

End Sub

Under ResetSIG ()
Dim pwd As String

& # 39; Disable application events to avoid issues related to updating the page
Application.EnableEvents = False

& # 39; Get the GIS password
pwd = ActiveWorkbook.Worksheets ("Drops"). Beach ("A17"). Value

& # 39; Reset all tabs to their defaults
Application.Run "Module2.ColHide", pwd

& # 39; And password protects the leaves
Application.Run "module2.ProtectOnly", pwd

& # 39; Move to the Scope tab
ActiveWorkbook.Worksheets (4) .Select

& # 39; Enable application events
Application.EnableEvents = True

End Sub

Under ScopingPWProtect ()

PWPass1.Show

End Sub
``````

## vb – save the elements of an XML response in vailable

How to save list items from an xml?

that is to say that I have the answer that reigns me with multiple elements and that these elements record it in variables?

example:

For each record nd As Xml.XmlNode In
rec.name = nd.Item ("Name"). InnerText
rec.direction = nd.Item ("dir"). InnerText
rec.factura = nd.Item ("folio"). InnerText
On page 124 of Introduction to Set Theory, Jech states that the ordinal functions below are continuous in the second variable: If $$gamma$$ is a limit ordinal and $$beta = sup_ {v < gamma} beta_ {vb}$$ then
$$alpha + beta = sup_ {v < gamma} ( alpha + beta_ {vb})$$
$$alpha. beta = sup_ {v < gamma} ( alpha. beta_ {vb})$$
$$alpha ^ beta = sup_ {v < gamma} ( alpha ^ { beta_ {vb}}$$